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Linear Approximation.

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Presentation on theme: "Linear Approximation."— Presentation transcript:

1 Linear Approximation

2 Learning Objectives Upon completing this module, you should be able to:  Recognize the linear approximation of a function as the tangent line to the function. Derive a linear approximation for a function at a particular value Interpret linear approximation graphically Use Linear approximation of a function to estimate numerical values

3 What is the Linear Approximation?
Linear approximation is the process of finding the equation of a line that is the closest estimate of a function for a given value of x. It is sometimes called “tangent line approximation”

4 Applications of Linear Approximation

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7 Linear Approximation Formula

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15 Linear approximation Equation of tangent line to y=f(x) at a is y = f(a) + f′(a) (x - a) y y = f(x) f(a) x a

16 Linear approximation If x is near a, we have: f(x) ≈ f(a) + f′(a) (x - a) y f(a) + f′(a) (x - a) y = f(x) f(x) f(a) x a x

17 Linear approximation Function L(x) = f(a) + f′(a) (x - a) is called linear approximation (or linearization) of f(x) at a y y = L(x) L(x) y = f(x) f(x) f(a) x a x

18 Example Find linearization of f(x) = √x at a
Use it to find approximate value of √5

19 Linearization

20 Approximation of √5 Find a such that Use linearization at a
√a is easy to compute a is close to 5 Use linearization at a Take a = 4 and compute linear approximation

21 Approximation of √5

22 Approximation of √5 y = L(x) = 2 + ¼ (x - 4) y y = √x a = 4 5 √5 2.25

23 Example Find approximate value of sin 10o

24 Example We measure x in radians So, 10o = 10 (π/180) = π/18 radians
Consider f(x) = sin x Find a such that sin(a) is easy to compute a is near π/18 Take a = 0 and compute linear approximation

25 Solution f(x) ≈ f(a) + f′(a) (x - a) = f(0) + f′(0) (x - 0)
f(x) = sin x, f′(x) = (sin x) ′ = cos x Therefore we obtain: sin x ≈ sin(0) + cos(0) (x - 0) = 0 +1(x – 0) = x Thus sin x ≈ x (when x is near 0) For x = π/18 we obtain: sin 10o = sin (π/18) ≈ π/18 ≈ Calculator gives: sin 10o ≈

26 Exercise If f(3) =8, f’(3) = -4, then f(3.02) =7.92

27 Try a few simple linearizations near x = 0:
The graph would look like this:

28 Try a few simple linearizations near zero:
Now try the other three.

29 Find the linearization of the function f (x) = at a = 1 and use it to approximate the numbers and .


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