1. Reaction Mechanisms
The sequence of events that describes the actual process by which reactants become products is called the reaction mechanism.
Reactions may occur all at once or through several discrete steps.
Each of these processes is known as an elementary reaction
The overall reaction cannot occur faster than this slowest, rate-determining step.
also called the RDS

2. Mechanisms Intermediate Catalyst
A species that is created in one step and consumed in the other
Catalyst
A species that is present originally then reforms later on during the reaction
It is not written in the overall equation, but you may see it noted above the reaction arrow.

3. Catalysts SLOW A Better and Different Way HBr Catalyst Fast Slow, RDS
Overall

4. Visualizing the reaction pathway No catalyst.
H2(g)+ 2 ICl (g) → I2 (g)+ 2 HCl (g)
A two step reaction mechanism with NO catalyst
slow RDS : H2+ ICl → HI + HCl
fast : HI + ICl → I2 + HCl
Overall H2 + 2 ICl → I2+ 2 HCl
Why is the 1st step the slowest step?
In which step would a catalyst go?

5. Reaction Mechanisms
The molecularity of a process tells how many molecules are involved in the process.
The rate law for an elementary step CAN be written directly from that step.
Ter steps is NOT likely, or highly improbable
The rate law for the rate-determining step becomes the rate law for the overall reaction.

6. A Mechanism With A Slow Step Gives Rate ORDER
Slow step: H2O2 + I-  H2O + OI-
Fast step: H2O2 + OI-  H2O + O2 + I-
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Net equation: 2 H2O2  2 H2O + O2
The catalyst? I-
The intermediate?
OI-
The slow step is the rate-determining step, so from it the
Rate of reaction is?
Rate = rate of slow step = k[H2O2][I-]

7. Sample Problem
Determining Molecularity and Rate Laws for Elementary Steps
PROBLEM:
The following elementary steps are proposed for a reaction mechanism:
(1) NO2Cl(g) → NO2(g) + Cl(g) (slow)
(2) NO2Cl(g) + Cl(g) → NO2(g) + Cl2(g) (fast)
(a) Write the overall balanced equation.
(b) Determine the molecularity of each step.
(c) Write the rate law for each step.
PLAN:
We find the overall equation from the sum of the elementary steps. The molecularity of each step equals the total number of reactant particles. We write the rate law for each step using the molecularities as reaction orders.

8. Sample Problem
SOLUTION:
(a) Writing the overall balanced equation:
(1) NO2Cl(g) → NO2(g) + Cl(g)
(2) NO2Cl(g) + Cl(g) → NO2(g) + Cl2(g)
2NO2Cl(g) → 2NO2(g) + Cl2(g)
Step(1) is unimolecular, it is the slowest step (simplest).
Step(2) is bimolecular.
(b)
The rate law for the rate-determining step becomes the rate law for the overall reaction.
rate1 = k1[NO2Cl]
rate2 = k2[NO2Cl][Cl]
Overall rate of reaction is rate1 = k1[NO2Cl]
(c) 8

9. Mechanisms with a Slow Initial Step
The overall reaction 2NO2(g) + F2(g) →2NO2F(g) has an experimental rate law Rate = k[NO2][F2].
The accepted mechanism is
NO2(g) + F2(g) → NO2F(g) + F(g) [slow; rate determining]
NO2(g) + F(g) → NO2F(g) [fast]
2NO2(g) + F2(g) →2NO2F(g)
rate1 = k1[NO2[F2]
Step 1 is the slow step, and rate1 correlates with the observed rate law.
The mechanism is therefore reasonable.

10. One more: Mechanisms with a Fast Initial Step
The overall reaction 2NO (g) + O2(g) →2NO2(g) has an experimental rate law Rate = k[NO]2[O2].
A proposed mechanism is
NO(g) + O2(g) D NO3(g) [fast]
NO3(g) + NO(g) → 2NO2(g) [slow; rate determining] RDS
2NO (g) + O2(g) →2NO2(g)
rateoverall = k2[NO3][NO]