1. CHEMICAL EQUILIBRIUM:
Some chemical reactions are reversible.
A reversible reaction is one in which the conversion of reactants to products & the conversion of products to reactants occur at the same time.
Ex. ?
Forward
2SO2(g) + O2(g) → 2SO3(g) ∆H < 0
Exothermic
Reverse
∆H > 0
Endothermic
The two equations can be combined in one using a double arrow:

2. CHEMICAL EQUILIBRIUM:
Reversible Reaction:
2SO2(g) + O2(g) SO3(g) ΔH < 0
(2 mol/L)
(3 mol/L)
(4 mol/L)
Forward V1
(Rate of reaction)
Reverse V2
(Rate of reaction)
The concentration of all substances remains
constant.
Equilibrium:
V1=V2

3. EQUILIBRIUM Parking lot (15 trucks) Parking lot (___ trucks)
Every 5 min:
3 trucks (out)
Parking lot
(15 trucks)
Parking lot
(___ trucks) 15
3 trucks (in)

4. Ex. Analyze the following graphs:
When the rates of the forward & reverse reactions are equal, the reaction has reached a state of balance called Chemical Equilibrium.
V1=V2
In a Chemical Equilibrium, the forward & the reverse reactions continue, but their rates are equal, no net change occur in the concentration of the reaction components.
Ex. Analyze the following graphs:

5. Equilibrium

6. Equilibrium

7. Equilibrium
For this reaction, at equilibrium the concentration of the reactants is higher than the concentration of the products (the equilibrium is shifted to the left).
This should be represented using arrows with different lengths:
N2(g) + 3 H2(g) NH3 (g)

8. Factors Affecting equilibrium: Le Chatelier’s Principle.
Le Chatelier’s Principle: If a stress is applied to a system in dynamic equilibrium, the system changes in a way that relieves the stress.
Stresses:
Changes in concentration (reactants
or products).
2) Changes in temperature.
3) Changes in pressure (gases).
Examples:

9. 1) Concentration:
Changing the concentration (amount) of any reactant or product disturbs the equilibrium and the system will adjust to minimize the effects of the change.
Ex:
N2(g) + 3 H2(g) NH3 (g)
N2(g)
Adding N2(g), increases its concentration, so the equilibrium shift to the right to minimize the effect of the change.
As consequence of the increase of the [N2]
[H2] (concentration of H2)
decreases
[NH3] (concentration of NH3)
increases

10. 1) Concentration: An increase in concentration on the left
Makes the equilibrium to
shift to the right
Or a decrease in
concentration
on the right
N2(g) + 3 H2(g) NH3 (g)
Or a decrease in
concentration
on the left
Makes the equilibrium to
shift to the left
An increase in
concentration
on the right

11. 2) Temperature:
Increasing the temperature causes the equilibrium position to shift in the direction that absorbs heat to minimize the effects of the change.
Ex:
(∆H < 0)
N2(g) + 3 H2(g) NH3 (g) + heat
The equilibrium shift to the left (endothermic reaction) to minimize the effect of the change.
[H2] (concentration of H2)
increases
As consequence of the increase in temperature
[N2] (concentration of N2)
increases
[NH3] (concentration of NH3)
decreases

12. 2) Temperature:
Increasing the temperature causes the equilibrium position to shift toward the endothermic reaction.
(∆H < 0)
N2(g) + 3 H2(g) NH3 (g) + heat
Decreasing the temperature causes the equilibrium position to shift toward the exothermic reaction.

13. 3) Pressure:
Increasing the pressure (reducing the volume of the container) causes the equilibrium position to shift in the direction that reduce the number of moles to minimize the effects of the change.
Ex:
N2(g) + 3 H2(g) NH3 (g) + heat
The equilibrium shift to the right (less number of molecules, less pressure) to minimize the effect of the change.
[H2] (concentration of H2)
decreases
As consequence of the increase in pressure
[N2] (concentration of N2)
decreases
[NH3] (concentration of NH3)
increases

14. 3) Pressure:
Increasing the pressure causes the equilibrium position to shift toward the side with the lesser number of moles (to reduce the pressure).
N2(g) + 3 H2(g) NH3 (g)
(4 mol)
(2 mol)
Decreasing the pressure causes the equilibrium position to shift toward the side with the greater number of moles (to increase the pressure).

15. Catalysts? Do the catalysts affect the chemical equilibrium?
Catalysts lower the activation energy for both, the forward reaction and the reverse reaction in the same way.
Catalysts decrease the time it takes to establish the equilibrium, so catalysts don’t affect the chemical equilibrium.

16. Exercise (Practice):

17. Class work : W/S: Factors Affecting the Chemical Equilibrium.
Home work: WS: Le Chatelier Principle (3)
(Edmodo)
Equations:
1 – 12:
5 CO(g) + I2O5 (s) ⇄ I2 (g) + 5 CO2 (g) ∆H = kJ
13-17:
4 NO(g) + 6 H2O (g) ⇄ 4 NH3 (g) + 5 O2 (g) ∆H = kJ