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Adaptive Resource Allocation in Multiuser OFDM Systems

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Presentation on theme: "Adaptive Resource Allocation in Multiuser OFDM Systems"— Presentation transcript:

1 Adaptive Resource Allocation in Multiuser OFDM Systems
Malik Meherali Saleh EE May 05, 2005 (05/05/05)

2 Introduction Future Generation (4G) systems to provide high data rates
Issue: Inter-Symbol Interference (ISI) Multiple Input Multiple Output (MIMO) and Orthogonal Frequency Division Multiplexing (OFDM) to the rescue… Resource Allocation Margin Adaptive [Wong, Cheng, Letaief and Murch, 1999] Rate Adaptive [Jang and Lee, 2003] Rate Adaptive + proportional fairness [Shen, Andrews and Evans, (Draft) 2004] In my prev talk I had mentioned the use of Hybrid OFDM and MIMO systems to overcome ISI in future generation communication systems My focus is on the way resources such as power or subcarriers are shared between multiple users of such hybrid systems. These are 3 papers mentioned last time which talk about adaptive resource allocation within the users the first one minimizes power while has fixed data rates for each user as a constraint The other two max total data rate or system capacity, while have fixed total power as a constraint I will be talking about the last two papers

3 Subcarrier Gain User 1 User 2
Channel Magnitude Channel Magnitude Tones Tones Before talking about the papers I will throw some light on the basics of OFDM Total BW divided into N subcarrier, Data is sent on each individual subcarriers, The lower the gain of the subcarrier more the power needed to transmit reliable data on that subcarrier Since total power is fixed and limited, assigning or sharing power to subcarriers is done such that maximum system capacity is achieved For e.g. in the first case user 1 sees low gain on subcarrier where as user 2 sees a high gain. On this basis, user 2 is assigned Subcarriers with higher gain and so the case for user 1 But in the second case user 1 does not see any high gain carriers compared to user 2 According to the allocation of jang and lee, user 1 will never be able to send any data across if the channel persists for him and u would say that is not fair But prof evans and collegue bring in some fairness into such a system by introducing proportional fairness among users and allowing user 1 to get a fair share of the total capacity User 1 User 2 These figures have been created for better understanding of algorithm. They are NOT results from simulations

4 Algorithm for [Jang and Lee]
Initialization Set Rk = 0 for k=1~K For n = 1 to N { Find the user k having higher channel gain Update Rk } For Power Allocation Water-filling Equal power allocation (Ptotal/N) Rk is the kth user capacity The algo is that for each channel n, find the user k which has the best channel gain, and then update Rk This is subcarrier allocation For power allocation, the paper mentions the use of water filling, which is the greedy algorithm to allocat power Or use simple equal power over all subcarriers which furtehr reduces complexity

5 Subcarrier allocation
User 2 User 1 Channel Magnitude Channel Magnitude Tones Tones These figures have been created for better understanding of algorithm. They are NOT results from simulations

6 Algorithm for [Prof. Evans et al]
Initialization Set Rk = 0, Wk = {0} for k = 1 to K and A = {1,2,…,N} Y1:Y2:…:YK For k = 1 to K Find n satisfying h(k,n) > h(k,j) for all j ε A Let Wk = Wk U {n}, A = A-{n} and update Rk The algorithm for the second method take care of users with consistent bad channel gain Here Rk is the kth users data rate, Uk is the subcarrier allocated for user k and A is the collection of subcarriers left to be assigned For each user 1 to K, assign it the channel for which it has maximum gain Add that channel to Uk Delete that channel from collection A For each user k the algorithm assigns a subcarrier n which has maximum gain amongst the subcarriers in A Update Rk, Wk and remove that subcarrier from A

7 Algorithm for [Prof. Evans et al] Conti..
While A != empty Find k satisfying Rk/Yk <= Ri/Yi for all I, 1<=i<=K For the found k, find n satisfying h(k,n) >= h(k,j) for all j ε A For the found k and n, let Wk = Wk U {n}, A=A-{n} and update Rk While A is not empty Find the user k for which minimum ratio Rk to Yk For this user k, find the highest gain subcarrier amongst the subcarrier in collection A Update Uk, A and Rk

8 Implementation For Non Fair System For Fair System
Code Development in progress For Fair System ‘A Low Complexity Algorithm for Proportional Resource Allocation in OFDMA Systems’ – Ian Wong et al Linearizes power allocation Approximates rate proportionality

9 Results Normalized Rate Proportions User Number (k)

10 Results Conti…

11 Future Work Implement code for first method
Compare the two methods on the following Total Capacity Normalized data rate for individual user Complexity


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