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Published byἈζαρίας Αντωνόπουλος Modified over 6 years ago
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NUMBER OF ATOMS PER UNIT CELL IN A CUBIC LATTICE
Simple cubic cell: 1atom/unit cell of sc e.g. Polonium Body-centered cell: 2 atoms/unit cell of bcc e.g. CsCl, CsBr Face-centered cell: 4 atoms/unit cell of fcc e.g. NaCl, NaF, KBr, MgO End face-centered cell: 2 atoms/unit cell
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Simple Cubic Lattice No of atoms per unit cell= 8 x 1/8 = 1
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Body-Centred Cubic Lattice
No of atoms per unit cell= (8 x 1/8) + (1x1) = 2
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Face-Centered Cubic Lattice
No of atoms present per unit cell = (8 x 1/8 ) + (6 x 1/2) = 4
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End Face-Centred Cubic Lattice
No of atoms present per unit cell = (8 x 1/8 ) + (2 x 1/2) = 2
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