1. A ______________ solution contains a ____________ amount of solute.
16.2
Molarity
The _________________ of a solution is a measure of the amount of solute that is dissolved in a given quantity of solvent.
A _________ solution is one that contains a ___________ amount of solute.
A ______________ solution contains a ____________ amount of solute.

2. 16.2
Molarity
____________ (M) is the number of moles of solute dissolved in one liter of solution.
To calculate the ______________ of a solution, divide the _______ of _________ by the ___________ of the ____________.

3. Swirl the flask carefully to dissolve the solute.
16.2
Molarity
To make a 0.5-molar (0.5M) solution, first add 0.5 mol of solute to a 1-L volumetric flask half filled with distilled water.
Swirl the flask carefully to dissolve the solute.
Fill the flask with water exactly to the 1-L mark.
The photos show how to make a 0.5-molar (0.5M) solution. a) Add 0.5 mol of solute to a 1-L volumetric flask half filled with distilled water. b) Swirl the flask carefully to dissolve the solute. c) Fill the flask with water exactly to the 1-L mark.

4. 16.2

5. for Sample Problem 16.2

6. 16.3

7. for Sample Problem 16.3

8. 16.2
Making Dilutions
Diluting a solution _____________ the number of ___________ of solute per __________ ________________, but the _________ ____________ of moles of solute in solution does __________ change.

9. 16.2
Making Dilutions
The total number of moles of solute remains unchanged upon dilution, so you can write this equation.
M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the diluted solution.

10. She then transfers the 20 mL to a 100-mL volumetric flask.
16.2
Making Dilutions
To prepare 100 ml of 0.40M MgSO4 from a stock solution of 2.0M MgSO4, a student first measures 20 mL of the stock solution with a 20-mL pipet.
She then transfers the 20 mL to a 100-mL volumetric flask.
Finally she carefully adds water to the mark to make 100 mL of solution.
The student is preparing 100 mL of 0.40M MgSO4 from a stock solution of 2.0M MgSO4 . a) She measures 20 mL of the stock solution with a 20-mL pipet. b) She transfers the 20 mL to a 100-mL volumetric flask. c) She carefully adds water to the mark to make 100 mL of solution. Inferring How many significant figures does the new molarity have?

11. 16.4

12. for Sample Problem 16.4 `
Problem Solving Solve Problem 12 with the help of an interactive guided tutorial.

13. 16.2
Percent Solutions
The ________________ of a solution in percent can be expressed in two ways: as the _________ of the volume of the _______ to the volume of the __________ or as the _______ of the mass of the ____________ to the mass of the ____________.

14. Concentration in Percent (Volume/Volume)
16.2
Percent Solutions
Concentration in Percent (Volume/Volume)

15. 16.2
Percent Solutions
Isopropyl alcohol (2-propanol) is sold as a 91% solution. This solution consist of 91 mL of isopropyl alcohol mixed with enough water to make 100 mL of solution.
The label clearly distinguishes this solution of isopropyl alcohol from rubbing alcohol, which is a 70% solution of isopropyl alcohol. Applying Concepts How many milliliters of isopropyl alcohol are in 100 mL of 91% alcohol?

16. 16.5

17. Practice Problems For Sample Problem 16.5
Problem-Solving Solve Problem 15 with the help of an interactive guided tutorial.

18. Concentration in Percent (Mass/Mass)
16.2
Percent Solutions
Concentration in Percent (Mass/Mass)