1. Molar Conversions
Atoms to Moles, moles to atoms, mass to atoms, atoms to mass, mass to mass

2. How to Convert Anything!
Identify the information given
Given: Start point
End point
Connect information
Conversion factor, mole ration, etc
Setup conversion plan
Start point and end point
Fill in units
New unit on the top old unit on the bottom
Do the math!
Fill in numbers

3. Atoms to mole, moles to atoms
A few things to remember
6.022 x particles = 1 mole of ANY compound
Particles can be: ions, atoms, formula units, or molecules
Conversion factors must link the two units
New unit Old Unit

4. Lets convert ! End point: Moles Mg 2. Moles Mg atoms Mg
Atoms to moles
How many moles of magnesium are in 3.01 x 1022 atoms of magnesium?
1. Given: 3.01 x 1022 atoms Mg
End point: Moles Mg
Moles Mg atoms Mg
x 1022 atoms Mg x moles Mg atoms Mg = ____Moles Mg
x 1022 atoms Mg x 1 mole Mg x 10 23atoms Mg = .05 Moles Mg

5. Keep converting!
Moles to molecules
How many molecules are there in 4.00 moles of glucose, C6H12O6?
1.Given: 4.00 moles C6H12O6
End point: Molecules of C6H12O6
Molecules of C6H12O6 moles C6H12O6
moles C6H12O6 x Molecules of C6H12O6 moles C6H12O6 = ____Molecules of C6H12O6
moles C6H12O6 x x 1023Molecules of C6H12O6 1 moles C6H12O6 = 2.4 x Molecules of C6H12O6

6. Moles to mass/ Mass to moles
SAME PROCESS AS PARTICLES TO MOLES/MOLE TO PARTICLES
Just different units!
A few things to remember
1 moles = molar mass
Elements: average atomic mass (periodic table)
Compounds: Must calculate

7. Lets Convert! 1. What is the mass of 5 moles of Fe2O3
grams Fe2O3 moles of Fe2O3
5 moles of Fe2O3x grams Fe2O3 moles of Fe2O3 = ____ grams Fe2O3
5 moles of Fe2O3x grams Fe2O3 1 moles of Fe2O3 = grams Fe2O3
2. Find the number of moles of argon in 452 g of argon.
Moles Ar grams of Ar
452 grams x Moles Ar grams of Ar = ____ Moles Ar
452 grams x 1 Moles Ar grams of Ar = Moles Ar
Side Calculation
Fe2O3
Fe: (2) =
O: (3) =
g/mol

8. Moles to volume/Volume to moles
SAME PROCESS AS PARTICLES TO MOLES/MOLE TO PARTICLES
Just different units!
A few things to remember
1 moles = 22.4
S: standard
T: temperature ( 0 oC)
P: Pressure (1 atm = kPa = 760 mm Hg)

9. Conversion time What is the volume of 0.05 mol of neon gas at STP?
How many moles of argon atoms are present in L of argon gas at STP?
  Moles of Ar Liters of Ar
11.2 L of Ar x Moles of Ar Liters of Ar = ____ Moles of Ar
11.2 L of Ar x 1 Moles of Ar 22.4 Liters of Ar = 0.5 Moles of Ar
What is the volume of 0.05 mol of neon gas at STP?
  Liters of Ne Moles of Ne
0.05 moles Ne x Liters of Ne Moles of Ne = ____ Liters Ne
0.05 moles Ne x 22.4 Liters of Ne 1 Moles of Ne = 1.12 Liters Ne

10. Mass to Particles : of the same Compound
A few things to remember
6.022 x particles = 1 mole of ANY compound
Particles can be: ions, atoms, formula unit, or molecules
1 moles = molar mass
Elements: average atomic mass (periodic table)
Compounds: Must calculate
Cannot complete in one step! Grams and particles cannot connect in one step.
Must go to Moles 1st

11. Time to Convert Side Calculation N: (2) 14.007= 28.014 g/mol
Find the mass, in grams, of 1.00 x 1023 molecules of N2
1.Start point: 1.00 x molecules N2
End point: Grams of N2
Moles of N2 molecules N2 and Grams of N2 molecules N2
x molecules N2 x Moles of N2 molecules N2 = ____ Moles of N2
1.00 x molecules N2 x 1 Moles of N x 1023molecules N2 = .166 Moles of N2
_____Moles of N2 x Grams of N2 Moles of N2 = ____ Grams of N2
Side Calculation
N: (2) = g/mol
Moles of N2 x Grams of N2 1 Moles of N2 = Grams of N2

12. Mass of one compound to mass of another
Five Steps
Label what is given
Start point/ endpoint
Connect the information
Mole ratio (from balanced equation)
Setup first conversion
Setup second conversion
Setup third conversion and solve

13. Steps 1 and 2
How many grams of potassium chloride, KCl, are produced if 25.0g of potassium chlorate, KClO3, decompose? 2KClO3 → 2KCl + 3O2
25.0 g
? g
2 moles KClO3 : 2 mole KCl

14. Step 3 and 4
Moles of KClO3 Grams of KClO g of KClO3 x Moles of KClO3 Grams of KClO3 = ____Moles of KClO g of KClO3 x 1 Moles of KClO g of KClO3 = .204 Moles of KClO3
Moles of KCl Moles of KClO3 _____Moles of KClO3x Moles of KCl Moles of KClO3 = ____ Moles of KCl .204 Moles of KClO3x 2 Moles of KCl 2 Moles of KClO3 = .204 Moles of KCl
Side Calculation
K: g/mol
Cl: g/mol
O: (3) = g/mol
g/mol

15. Step 5
Side Calculation
K: g/mol
Cl: g/mol
g/mol
grams of KCl Moles of KCl
_____Moles of KCl x grams of KCl Moles of KCl = ____grams of KCl
.204 Moles of KCl x grams of KCl 1 Moles of KCl = grams of KCl