1. Redox Review

2. 1. KK+ + 1e-
Has potassium been oxidized or reduced?

3. KK+ + 1e-
Potassium has been oxidized, it has become more positive from reactant to product and potassium is a solid on the reactant side.

4. 2. Ag+ + 1e-  Ag
Has silver been oxidized or reduced?

5. Ag+ + 1e-  Ag
Silver has been reduced, it has gained an electron to neutralize the ion and it is an ion on the reactant side.

6. 3. K + Na+  K+ + Na
Identify which element has been oxidized and which element has been reduced.

7. K + Na+  K+ + Na
Potassium has been oxidized (LEO) and sodium has been reduced (GER).

8. 4. K + Na+  K+ + Na
Write the half reactions for potassium and sodium.

9. K + Na+  K+ + Na
K  K e LEO
Na+ + 1e-  Na GER

10. 5. Cu + AgCl 
Predict the products.

11. Cu + AgCl 
Cu + AgCl  Ag + CuCl2

12. 6. Cu + AgCl  Ag + CuCl2
Write the half reactions for copper and silver, show that chlorine is the spectator ion

13. Cu + AgCl  Ag + CuCl2 Cu + Ag+ + Cl-  Ag + Cu+2 + Cl-
Chlorine hasn’t changed from reactant to product, so it’s the spectator. Chlorine can be removed.
Cu  Cu+2 + 2e-
Ag+ + 1e-  Ag
Electrons must be equal, so…. 2 x [Ag+ + 1e-  Ag]
= 2Ag+ + 2e-  2Ag
Now copper and silver electrons are equal

14. 7. Cu + AgCl  Ag + CuCl2
Write the net ionic equation for this reaction.

15. Cu + AgCl  Ag + CuCl2
Cu + 2Ag+  2Ag + Cu+2

16. 8. Mg + Al+3  Mg+2 + Al
Create a half reaction for magnesium and one for aluminum, and balance the electrons.

17. Mg + Al+3  Mg+2 + Al Mg  Mg+2 + 2e- Al+3 + 3e-  Al
So the electrons don’t match, so bring each equation up to 6e- by multiplication.
3 x [Mg  Mg+2 + 2e-] = 3Mg  3Mg+2 + 6e-
2 x [Al+3 + 3e-  Al] = 2Al+3 + 6e-  2Al

18. 9. Diagram lithium with sodium, identify anode and cathode
Porous cup V

19. lithium with sodium
Porous cup V Li Na
Na+
Li+

20. 10. Create half reactions and a net ionic equation for lithium and sodiumV Li Na
Na+
Li+

21. Li  Li+ + 1 e- ; Na+ + 1e-  Na Li + Na+  Li+ + NaV Li Na
Na+
Li+

22. 11. An Ox sat on a big Red Cat, where does oxidation and reduction take place?
Li  Li+ + 1 e-
Na+ + 1e-  Na

23. Li  Li+ + 1 e- Na+ + 1e-  Na
Lithium = LEO , oxidation takes place at the anode.
Sodium = GER, reduction takes place at the cathode.

24. 12. Assign oxidation numbers
PbSO4 H2
H2O
NaCl
Ag+
SO4-2 Na

25. Oxidation numbers PbSO4 ; Pb = +2, S = +6, O= -2 x 4 oxygens = -8
H2 = 0
H2O; H = +1, 2 hydrogens = +2; O = -2
NaCl; Na= +1, Cl = -1
Ag+ = +1
SO4-2; S = + 6, O = -2 x 4 oxygens = -8; -2 is the final charge
Na = 0

26. 13. Identify this equation as Redox using oxidation numbers
Na +AgCl  NaCl + Ag

27. Oxidation numbers Na +AgCl  NaCl + Ag Na: 0  +1 LEO Ag: +1  0 GER
Cl- both sides spectator ion

28. 14. Identify LEO and GER for the following equation
Cu + AgBr CuBr2 + Ag

29. Oxidation Numbers
Cu + AgBr  CuBr2 + Ag
Cu: 0  LEO
Ag :+1  0 GER