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CHAPTER 12.2 BASIC STOICHIOMETRY

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1 CHAPTER 12.2 BASIC STOICHIOMETRY
MRS RAGSDALE CHEMISTRY I

2 MOLAR RATIO REALLY SUPER BIG IMPORTANT!
OBTAINED FROM A PROPERLY BALANCED CHEMICAL EQUATION BALANCE THE EQUATION WRONG? MOLAR RATIO IS WRONG! FAIL. COEFFICIENTS FROM BALANCED EQUATION = MOLAR RATIO

3 MOLAR RATIOS N₂ + 3H₂ → 2NH₃ BASED ON THE COEFFIECIENTS:
Molar Ratio is 1:3:2 FOR EVERY 1 MOLE OF N₂ I WILL NEED 3 MOLES OF H₂ THIS WILL PRODUCE 2 MOLES OF NH₃

4 Moles to Moles N₂ + 3H₂ → 2NH₃
IF YOU HAVE 5 MOLES OF N₂, HOW CAN YOU CONVERT THIS TO NH₃? N₂ AND NH₃ ARE IN A 1 : 2 RATIO FOR EVERY 1 MOLE OF N₂, YOU WILL MAKE 2 MOLES OF NH₃ 5 MOLES N₂ X = 10 MOLES NH₃

5 Grams to Moles N₂ + 3H₂ → 2NH₃
IF YOU HAVE 25 GRAMS OF N₂, HOW CAN YOU CONVERT THIS TO MOLES OF NH₃? Remember – to convert grams of a substance into moles, you will need the molar mass (g/mol) There are 28g of N₂ in 1 mol of N₂ For every 1 mol of N₂ there are 2 moles of NH₃ 25gN₂ X X = 1.79 moles NH₃

6 MRS RAGSDALE CHEMISTRY I
12.3 LIMITING REAGENTS MRS RAGSDALE CHEMISTRY I

7 WHAT EXACTLY IS A LIMITING REAGENT?
LIMITING REAGENTS – WHATEVER REACTANT THAT YOU RUN OUT OF FIRST EXCESS REAGENT – WHATEVER REACTANT YOU HAVE LEFT OVER

8 HOW IS A LIMITING REAGENT USEFUL?
YOU CAN PREDICT THE AMOUNT OF PRODUCE YOU CAN EXPECT TO FORM IN A REACTION BASED ON THE LIMITING REAGENT

9 ENOUGH ALREADY… I UNDERSTAND WHAT IT IS BUT HOW THE HECK AM I SUPPOSED TO DO THIS????

10 MRS RAGSDALE’S WAY… 2Cu + S → Cu₂S
LET’S SAY I HAVE 80.0g OF Cu REACTING WITH 25.0g OF S. HOW CAN I FIND OUT WHAT THE LIMITING REAGENT IS? CONVERT 80.0g OF Cu INTO ?g OF S AFTER DOING THE MATH I GET 20.2g OF S USE LOGIC!!! I HAVE 25g OF S AVAILABLE… HOW MUCH DO I ACTUALLY NEED THOUGH? THAT’S RIGHT! I NEED 20.2g BUT HAVE 25g – S IS IN EXCESS THAT MEANS THAT Cu IS MY LIMITING REAGENT

11 WHAT IS % YIELD? WE’RE JUST NOT PERFECT – EVEN THE BEST SCIENTIST WILL LOSE SOME PRODUCT % YIELD – MEASUREMENT OF HOW MUCH PRODUCT YOU OBTAINED VS HOW MUCH YOU SHOULD HAVE OBTAINED

12 HOW TO CALCULATE % YIELD
STEP 1: THEORETICAL VS ACTUAL THEORETICAL YIELD: WHAT YOU CALCULATED USING STOICHIOMETRY ACTUAL YIELD: WHAT YOU PHYSICALLY OBTAINED DOING AN EXPERIMENT STEP 2: DO THE MATH


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