Presentation is loading. Please wait.

Presentation is loading. Please wait.

Calculus 3-4 Rates of Change.

Similar presentations


Presentation on theme: "Calculus 3-4 Rates of Change."โ€” Presentation transcript:

1 Calculus 3-4 Rates of Change

2 Instantaneous Rate of Change
๐‘“ โ€ฒ ๐‘ฅ The derivative at a given point will tell you the instantaneous rate of change (slope) at that point

3 ๐ด=๐œ‹ ๐‘Ÿ 2 Find ๐‘‘๐ด ๐‘‘๐‘Ÿ when ๐‘Ÿ=2, ๐‘Ž๐‘›๐‘‘ ๐‘Ÿ=5 ๐‘‘๐ด ๐‘‘๐‘Ÿ =2๐œ‹๐‘Ÿ ๐‘Ÿ=2: ๐‘‘๐ด ๐‘‘๐‘Ÿ =4๐œ‹
๐‘Ÿ=2: ๐‘‘๐ด ๐‘‘๐‘Ÿ =4๐œ‹ ๐‘Ÿ=5: ๐‘‘๐ด ๐‘‘๐‘Ÿ =10๐œ‹ Why is ๐‘‘๐ด ๐‘‘๐‘Ÿ larger at ๐‘Ÿ=5 As the radius increase the rate that the area of circle increase as well

4 Linear Motion ๐‘ฃ๐‘’๐‘™๐‘œ๐‘๐‘–๐‘ก๐‘ฆ= ๐‘‘๐‘–๐‘ ๐‘ก๐‘Ž๐‘›๐‘๐‘’ โ€ฒ ๐‘  ๐‘ก =4 ๐‘ฅ 2 +8๐‘ฅโˆ’9 ๐‘ฃ ๐‘ก =8๐‘ฅ+8

5

6 Motion under Gravity ๐‘  ๐‘ก = ๐‘  0 + ๐‘ฃ 0 ๐‘กโˆ’ 1 2 ๐‘” ๐‘ก 2 ๐‘ฃ ๐‘ก = ๐‘‘๐‘  ๐‘‘๐‘ก = ๐‘ฃ 0 โˆ’๐‘”๐‘ก ๐‘”โ‰ˆ9.8 ๐‘š ๐‘  2 ๐‘œ๐‘Ÿ 32 ๐‘“๐‘ก ๐‘  2

7 Find the velocity of an object dropped from a height of 300 m at the moment it his the ground.
Equation for the object How long before it hits the ground Velocity function Velocity at that time

8 ๐‘  ๐‘ก =300โˆ’ ๐‘ก 2 ๐‘ก= ๐‘ ๐‘’๐‘๐‘  ๐‘ฃ ๐‘ก =โˆ’9.8๐‘ก ๐‘ฃ 0 =โˆ’ ๐‘š/๐‘ 

9 Problems 3.4 #1, 7, 9-11, odd NOT 23 and 29, 38, and 49


Download ppt "Calculus 3-4 Rates of Change."

Similar presentations


Ads by Google