1. Formulas pages 113–115 Exercises 12. y = –2x + 4 1. r = 13. y =
ALGEBRA 1 LESSON 2-6
pages 113–115  Exercises
1. r =
2. d =
3. = – w
4. B =
5. h =
6. s =
7. b1 = – b2
8. h =
9. y = –2x + 5
10. y = 6x – 1
11. y = –4x + 3
12. y = –2x + 4
13. y =
14. y =
15. y =
16. y =
17. x =
18. g =
19. z = a + y
20. y =
21. t =
22. r = – 1
23. p =
24. y = mx + b
25. a. H =
b. 11 ft
26. a. h = na
b. 53 hits
27. a. p =
b. $3000
c. If the interest at 3.5%
for 4 yr is $420, the
principal is $
28. a. s =
b. $494.20
C 2 5x N 7L C
–3x P 2
–5x
S – L 2
–2x I rt V w c d P 4 d c 2A h V
r 2
c – ax b C
0.05
A – P Pr S C qm n
2-6

2. 42. Answers may vary. Sample: Both types of equations are
Formulas
ALGEBRA 1 LESSON 2-6
29. b =
30. x = (y – 8)
31. p =
32. p = – r
33. h =
34. y =
35. b =
36. m = hw – k
37. h =
38. y = 3x – 2
39. y = w
40. x = m – 4 A h S
180
–V – h
41. a. n =
b. 5; 7; 4; 9
42. Answers may vary. Sample:
Both types of equations are
transformed in the same way.
In solving a literal equation,
you must be concerned about
dividing by a variable where the
value of the variable might be zero.
43. Check students’ work.
44. a. 5.85
b. b = 2m – a
c. 5.9
45. a. A =
b. 27 ft2
46. a =
47. B
48. I
49. B
50. G
51. 71, 72, 73 cm
53. [–60  9]
54.
55. 3 2
r + b a 5 2
SA –2B r 2x da c 3V
r 2
14 –6.2
–16 1 2 3 4 s2 R –
0 24 –28.5 3 2
2-6