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Graphical Relationships

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Presentation on theme: "Graphical Relationships"— Presentation transcript:

1 Graphical Relationships
By the end of this topic, you should be able to (a) Draw a straight line given its equation in the form y = ax + b by making a table of values

2 Plotting Points The points (1,3), (4,3) and (6,3) all lie on the line. 1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y A has coordinates (1,5) a y = 3 This is known as the equation of the line. b B has coordinate (3,2)

3 Lines parallel to the y axis
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y Lines parallel to the x axis Lines parallel to the y axis Y = 8 Y = 4 Y = 2 Y = 0 Y = -3 Y = -8 x = - 7 x = - 4 x = 5 x = 0 x = 9

4 Drawing Straight Line Graphs
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y y = 3x y = x x y x y 0  0  3  3 2  6 -4  -4 -3  -9 y = ½x y = 2x x y x y 0  0  8  4 3  6 4  2 -4  -8 Use grid 1 to draw 4 graphs with me.

5 x y y = x + 5 y = x + 1 x y x y y = x - 7 y = x + 2 x y x y 0  1 0 
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y y = x + 5 y = x + 1 x y x y 0  1 0  5 3  4 3  8 -4  -3 -5  y = x - 7 y = x + 2 x y x y 0  -7 0  2 10  3 5  7 4  -3 -5  -3

6 x y y = 3x – 4 y = 2x + 1 x y x y y = ½x + 5 y = 2x - 5 x y x y 0  1
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y y = 3x – 4 y = 2x + 1 x y x y 0  1 0  -4 3  7 4  8 -4  -7 -2  -10 y = ½x + 5 y = 2x - 5 x y x y 0  5 0  -5 8  9 6  7 -8  1 -2  -9

7 x y y = -3x + 4 y = -x x y x y y = -½x - 3 y = -2x x y x y 0  0  4
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y y = -3x + 4 y = -x x y x y 0  0  4 5  -5 4  -8 -6  6 -2  10 y = -½x - 3 y = -2x x y x y 0  -3 0  8  -7 3  -6 -8  1 -5  10

8 Draw the following straight line graphs
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y Draw the following straight line graphs y = 2x + 3 y = 3x – 5 y = -x + 6 y = -4 x = 7 Y = ½x –2 Y = - 4x -9


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