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Acids and Bases.

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Presentation on theme: "Acids and Bases."— Presentation transcript:

1 Acids and Bases

2 Acids & Bases Acids: acids are sour tasting
Arrhenius acid: Any substance that, when dissolved in water, increases the concentration of hydronium ion (H3O+) Bronsted-Lowry acid: A proton donor Bases: bases are bitter tasting and slippery Arrhenius base: Any substance that, when dissolved in water, increases the concentration of hydroxide ion (OH-) Bronsted-Lowry base: A proton acceptor

3 Lone Hydrogen ions do not exist by themselves in solution
Lone Hydrogen ions do not exist by themselves in solution. H+ is always bound to a water molecule to form a hydronium ion

4 General Equation Brønsted-Lowry Theory of Acids & Bases
Conjugate Acid-Base Pairs General Equation

5 Brønsted-Lowry Theory of Acids & Bases

6 Brønsted-Lowry Theory of Acids & Bases

7 Brønsted-Lowry Theory of Acids & Bases
Notice that water is both an acid & a base = amphoteric Reversible reaction

8 ELECTROLYTES Electrolytes are species which conducts electricity when dissolved in water. Acids, Bases, and Salts are all electrolytes. Salts and strong Acids or Bases form Electrolytes. Salt and strong acids (and bases) are fully dissociated therefore all of the ions present are available to conduct electricity. HCl(s) + H2O  H3O Cl- Weak Acids and Weak Bases for Weak Electrolytes. Weaks electrolytes are partially dissociated - have less ions available to conduct electricity. NH3 + H2O  NH OH-

9

10 Acids & Bases STRONG vs WEAK H2SO4 NaOH HI KOH HBr Ca(OH)2 HCl Sr(OH)2
_ completely ionized _ partially ionized _ strong electrolyte _ weak electrolyte _ ionic/very polar bonds _ some covalent bonds Strong Acids: Strong Bases: HClO4 LiOH H2SO4 NaOH HI KOH HBr Ca(OH)2 HCl Sr(OH)2 HNO3 Ba(OH)2

11 Acids & Bases a. OH-1 + HCl  b. H2O + HC2H3O2  c. OH-1 + H2SO4 
For the following identify the acid and the base. a. OH HCl  b. H2O + HC2H3O2  c. OH H2SO4  d. NH3 + H2O 

12 Acids & Bases a. OH-1 + HCl  b. H2O + HC2H3O2  Cl-1 + H2O
For the following predict the product. To check your answer left click on the mouse. Draw a mechanism detailing the proton movement. a. OH HCl  b. H2O + HC2H3O2  c. OH H2SO4  d. NH3 + H2O  Cl-1 + H2O C2H3O H3O+ SO H2O NH4+ + OH-

13 Conjugate Acid-Base Pairs

14 Conjugate Acid-Base Pairs

15 Acids & Bases a. Al(OH)3 + 3 HCl  AlCl3 + 3 H2O
For the following Identify the conjugate acid and the conjugate base. The conjugate refers to the acid or base produced in an acid/base reaction. The acid reactant produces its conjugate base (CB). a. Al(OH) HCl  AlCl3 + 3 H2O b. Ba(OH)2 + 2 HC2H3O2  Ba(C2H3O2)2 + 2 H2O c. 2 KOH + H2SO4  K2SO4 + 2 H2O d. NH3 + H2O  NH4+ + OH- CB CA CB CA CB CA CA CB

16 TITRATION MAVA = MBVB nacid = nbase
Titration of a strong acid with a strong base ENDPOINT = POINT OF NEUTRALIZATION = EQUIVALENCE POINT At the end point for the titration of a strong acid with a strong base, the moles of acid (H+) equals the moles of base (OH-) to produce the neutral species water (H2O). If the mole ratio in the balanced chemical equation is 1:1 then the following equation can be used. MAVA = MBVB MOLES OF ACID = MOLES OF BASE nacid = nbase Since M=n/V

17 Ma Va = Mb Vb rearranges to Ma = Mb Vb / Va
TITRATION MAVA = MBVB 1. Suppose mL of hydrochloric acid was required to neutralize mLof 0.52 M NaOH. What is the molarity of the acid? HCl + NaOH  H2O + NaCl Ma Va = Mb Vb rearranges to Ma = Mb Vb / Va so Ma = (0.52 M) (22.50 mL) / (75.00 mL) = 0.16 M Now you try: 2. If mL of M HNO3 neutralized mL of KOH, what is the molarity of the base? Mb = mol/L

18 TITRATION nacid = nbase
Titration of a strong acid with a strong base ENDPOINT = POINT OF NEUTRALIZATION = EQUIVALENCE POINT At the end point for the titration of a strong acid with a strong base, the moles of acid (H+) equals the moles of base (OH-) to produce the neutral species water (H2O). If the mole ratio in the balanced chemical equation is NOT 1:1 then you must rely on the mole relationship and handle the problem like any other stoichiometry problem. MOLES OF ACID = MOLES OF BASE nacid = nbase

19 TITRATION 1. If mL of M LiOH neutralized mL of H2SO4, what is the molarity of the acid? 2 LiOH + H2SO4  Li2SO4 + 2 H2O First calculate the moles of base: L LiOH (0.543 mol/1 L) = mol LiOH Next calculate the moles of acid: mol LiOH (1 mol H2SO4 / 2 mol LiOH)= mol H2SO4 Last calculate the Molarity: Ma = n/V = mol H2SO4 / L = M 2. If mL of Ba(OH)2 solution was used to titrate29.26 mL of M HCl, what is the molarity of the barium hydroxide solution? Mb = mol/L

20 Water Equilibrium

21 Equilibrium constant for water
Water Equilibrium Kw = [H+] [OH-] = 1.0 x 10-14 Equilibrium constant for water Water or water solutions in which [H+] = [OH-] = 10-7 M are neutral solutions. A solution in which [H+] > [OH-] is acidic A solution in which [H+] < [OH-] is basic

22 pH A measure of the hydronium ion
The scale for measuring the hydronium ion concentration [H3O+] in any solution. The “p” in pH stands for log. A solution with a pH of 1 has [H3O+] of 0.1 mol/L or 10-1 A solution with a pH of 3 has [H3O+] of mol/L or 10-3 A solution with a pH of 7 has [H3O+] of mol/L or 10-7 pH = - log [H3O+]

23 The pH scale pH = - log [H3O+] 1 2 3 4 5 6 7 8 9 10 11 12 13 14
The pH scale ranges from 1 to mol/L or from 1 to 14. pH = - log [H3O+] acid neutral base

24 pH + pOH = 14 ; the entire pH range!
Manipulating pH Algebraic manipulation of: pH = - log [H3O+] allows for: [H3O+] = 10-pH If pH is a measure of the hydronium ion concentration then the same equations could be used to describe the hydroxide (base) concentration. [OH-] = 10-pOH pOH = - log [OH-] thus: pH + pOH = 14 ; the entire pH range!

25 PRACTICE PROBLEM #25 5.62 x 10-9 M pH = 4.04 pOH = 4.93
1. What is the molar concentration of hydronium ion in a solution of pH 8.25? 2. What is the pH of a solution that has a molar concentration of hydronium ion of x 10-5? 3. What is the pOH of a solution that has a molar concentration of hydronium ion of x 10-10? 5.62 x 10-9 M pH = 4.04 pOH = 4.93

26 GROUP STUDY PROBLEM #25 ______1. How many milliliters of 0.75 M KOH must be added to neutralize 50.0 mL of 2.50 M HCl? ______2. What mass of Ca(OH)2 will be required to neutralize 100 mL of M HCl solution? ______3. How many mL of M H2SO4 must be added to neutralize 25.0 mL of M NaOH? ______ 4. What is the molar concentration of hydronium ion in a solution of pH 2.45? ______ 5. What is the pH of a solution that has a molar concentration of hydronium ion of x 10-9? ______ 6. What is the pOH of a solution that has a molar concentration of hydronium ion of x 10-4?


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