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Warm up Honors algebra 2 2/25/19

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1 Warm up Honors algebra 2 2/25/19
1. Your 3 year investment of $20,000 received 5.2% interest compounded semi annually. What is your total return? 2. You borrowed $59,000 for 2 years at 11% interest compounded continuously. What total will you pay back? Go over homework

2 Suppose that the present value of $1000 to be received in 5 years is $550. What rate of interest, compounded continuously, was used to compute this present value? ๐ด=๐‘ƒ ๐‘’ ๐‘Ÿ๐‘ก 1000=550 ๐‘’ ๐‘Ÿ 5 = 550 ๐‘’ ๐‘Ÿ 1.82= ๐‘’ 5๐‘Ÿ ln =๐‘™๐‘› ๐‘’ 5๐‘Ÿ ln =5๐‘Ÿ ln = 5๐‘Ÿ 5 ๐‘Ÿ=0.12 12% interest rate

3 Half life Half life of a substance is the time it takes for half of the substance to breakdown or convert to another substance during the process of decay. Natural decay is modeled by the function: ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก ๐‘ ๐‘ก is the amount remaining k is the decay constant ๐‘ 0 is the initial amount (at ๐‘ก=0) t is the time Decay constant is the fraction of the number of atoms that decay in 1 second.

4 Plutonium-239 (Pu-239) has a half-life of 24,110 years
Plutonium-239 (Pu-239) has a half-life of 24,110 years. How long does it take for a 1 gram sample of Pu-239 to decay to 0.1 grams? How would you solve this problem? Find your formula: ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก Find the decay constant (k) since it is not given. Write the decay function (with k) and solve for t

5 Plutonium-239 (Pu-239) has a half-life of 24,110 years
Plutonium-239 (Pu-239) has a half-life of 24,110 years. How long does it take for a 1 gram sample of Pu-239 to decay to 0.1 grams? ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก 1 2 = 1 ๐‘’ โˆ’๐‘˜ 24110 Find the decay constant for Pu-239. ๐‘ ๐‘ก =1/2 because ยฝ of the substance is remaining the same and the other half is decaying or changing. ๐‘ 0 =1 ๐‘ก=24,110

6 Plutonium-239 (Pu-239) has a half-life of 24,110 years
Plutonium-239 (Pu-239) has a half-life of 24,110 years. How long does it take for a 1 gram sample of Pu-239 to decay to 0.1 grams? 1 2 = ๐‘’ โˆ’๐‘˜ 24110 ๐‘™๐‘› 1 2 =๐‘™๐‘› ๐‘’ โˆ’๐‘˜ 24110 ๐‘™๐‘› 1 2 =โˆ’24,110๐‘˜ ln โˆ’24,110 =๐‘˜ ๐‘˜โ‰ˆ Pu-239 is decaying at a constant of atoms per second.

7 Plutonium-239 (Pu-239) has a half-life of 24,110 years
Plutonium-239 (Pu-239) has a half-life of 24,110 years. How long does it take for a 1 gram sample of Pu-239 to decay to 0.1 grams? ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก 0.1=1 ๐‘’ โˆ’ ๐‘ก Now we solve for t to answer the question. ๐‘ ๐‘ก =0.1 ๐‘ 0 =1 ๐‘˜=

8 Plutonium-239 (Pu-239) has a half-life of 24,110 years
Plutonium-239 (Pu-239) has a half-life of 24,110 years. How long does it take for a 1 gram sample of Pu-239 to decay to 0.1 grams? 0.1= ๐‘’ โˆ’ ๐‘ก ๐‘™๐‘›0.1=๐‘™๐‘› ๐‘’ โˆ’ ๐‘ก ๐‘™๐‘›0.1=โˆ’ ๐‘ก ๐‘™๐‘›0.1 โˆ’ =๐‘ก ๐‘กโ‰ˆ80,000 It takes approximately 80,000 years for 1 gram of Pu-239 to decay to 0.1 grams.

9 An isotope of cesium has a half life of 30 years. If 1
An isotope of cesium has a half life of 30 years. If 1.0 grams of cesium disintegrates over a period of 90 years, how many grams of cesium would remain? ๐‘™๐‘› 1 2 โˆ’30 = โˆ’30๐‘˜ โˆ’30 ๐‘˜=0.0231 is the decay constant for cesium ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก 1 2 =1 ๐‘’ โˆ’๐‘˜(30) ๐‘™๐‘› 1 2 =๐‘™๐‘› ๐‘’ โˆ’๐‘˜(30) ๐‘™๐‘› 1 2 =โˆ’30๐‘˜

10 An isotope of cesium has a half life of 30 years. If 1
An isotope of cesium has a half life of 30 years. If 1.0 grams of cesium disintegrates over a period of 90 years, how many grams of cesium would remain? ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก ๐‘ ๐‘ก =1 ๐‘’ โˆ’0.0231(90) ๐‘ ๐‘ก =0.125 There will be grams of cesium left after 90 years.

11 Polonium-214 has a relatively short half-life of 164 seconds
Polonium-214 has a relatively short half-life of 164 seconds. How many seconds would it take for 8.0 g of this isotope to decay to 0.25 g? ๐‘ ๐‘ก = ๐‘ 0 ๐‘’ โˆ’๐‘˜๐‘ก 1 2 = ๐‘’ โˆ’๐‘˜ 164 ๐‘™๐‘› 1 2 = ๐‘™๐‘›๐‘’ โˆ’๐‘˜ 164 ๐‘™๐‘› 1 2 =โˆ’164๐‘˜ ๐‘™๐‘› 1 2 โˆ’164 =๐‘˜ ๐‘˜=0.0042

12 Polonium-214 has a relatively short half-life of 164 seconds
Polonium-214 has a relatively short half-life of 164 seconds. How many seconds would it take for 8.0 g of this isotope to decay to 0.25 g? ln =โˆ’0.0042๐‘ก ln โˆ’ =๐‘ก ๐‘ก= ๐‘ ๐‘’๐‘๐‘œ๐‘›๐‘‘๐‘  0.25=8 ๐‘’ โˆ’ ๐‘ก = ๐‘’ โˆ’ ๐‘ก = ๐‘’ โˆ’0.0042๐‘ก ln =๐‘™๐‘› ๐‘’ โˆ’0.0042๐‘ก


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