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Linear strain triangular Tieme Willems

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Presentation on theme: "Linear strain triangular Tieme Willems"— Presentation transcript:

1 Linear strain triangular Tieme Willems
Finite element method Linear strain triangular Tieme Willems

2 introduction Plane stress situation
Normal stress and shear stress directed perpendicular to the plane (assumed to be 0) Loads act only in x-y plane In this presentation: Investigate amount of elements/ nodes Investigate aspect ration

3 Chapter 1, Aspect ratio Changing the aspect ratio, by increasing the amount of elements. 4 elements 8 elements 10 elements 20 elements

4 1.2 conclusion Exact = PL = 10000*20 EA 10*(30*10^6) Case Aspect ratio
# nodes # elements FEM e-004 Exact % error 1 6 4 674.68 670 0.69 2 10 8 670.41 0.06 3 2.5 12 668.44 0.23 5 22 20 663.45 0.98 Exact = PL = 10000* EA 10*(30*10^6)

5 Chapter 2, elements Increase the amount of elements, but maintain the aspect ratio Aspect ratio 1 4 elements 16 elements 64 elements Aspect ratio 2 2 elements 8elements

6 Chapter 2, number of elements
Increase the amount of elements, but maintain the aspect ratio More elements gives in this case at first a more accurate solution, but with 64 nodes a less accurate solution due to the distribution of force on the nodes Case Aspect ratio # nodes # elements FEM e-004 Exact % error 1 6 4 674.68 670 0.69 2 15 16 671.93 0.29 3 45 64 722.48 7.27 Case Aspect ratio # nodes # elements FEM e-004 Exact % error 1 2 4 663.70 670 0.95 10 8 670.41 0.06

7 Chapter 2, conclusion Increasing the amount of elements results into a more exact solution; If can distribute the forces appropriate over more notes, the result becomes more accurate; If can keep the aspect ratio close to 1 the result comes closest to the exact result; Amount of elements is situation related (meaning we should run the program with different aspect ratio to see which result comes closest to the exact)


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