1. Redox Reactions
Reduction
Oxidation

2. What is a redox reaciton?
Redox (or oxidation-reduction) reactions are reactions in which electrons are transferred from one atom to another.
And redox reactions are…EVERYWHERE!

3. For Example…
Zinc, a component of galvanized steel, can react with oxygen in the following reaction:
2 Zn (s) + O2 (g)  2 ZnO (s)
But really, you can also think of it like this…
2 Zn (s) + O2 (g)  2 Zn2+ (s) + 2 O2- (s)
As you can see…Zinc loses electrons while oxygen gains electrons.

4. It’s actually TWO reactions!
Oxidation reaction – a reaction in which an element loses electrons
Zn  [Zn]2+ + 2e-
Reduction reaction – a reaction in which an element gains electrons
O + 2e-  [O]2-

6. Just Remember…
O xidation
I s
L oss
R eduction
G ain

7. This is all based on the Octet Rule!
And don’t forget…
This is all based on the Octet Rule!

8. Oxidation Numbers
In order to determine which atoms are reduced and which are oxidzed, we must assign each element an oxidation number
Remember! Oxidation numbers are…
The hypothetical electrical charge on an element or ion

9. Rules for Assigning Oxidation Numbers`
Rules for Assigning Oxidation Numbers

10. A Few Basics…
The oxidation number of Oxygen is always -2 (with the exception of peroxides where Oxygen is -1)
The oxidation number of Hydrogen is always +1 (except when combined to form metal hydrides where it is -1)
Oxidation numbers for elements of very high and very low electronegativity are based on the periodic table.

11. Oxidation Numbers F -1 O -2 H +1 Cl Oxidation state of O in O2?
1. The oxidation number of atoms in their elemental state is zero. F -1 O -2 H +1 Cl
Oxidation state of O in O2?

12. Oxidation Numbers F -1 O -2 H +1 Cl Oxidation state of C in CO2?
2. The oxidation numbers of atoms in a neutral compound add up to zero. F -1 O -2 H +1 Cl
Oxidation state of C in CO2?
? – 4 = 0
? = +4
Put the +!

13. Oxidation Numbers F -1 O -2 H +1 Cl +2 Oxidation state of Mg in MgCl2?
2. The oxidation numbers of atoms in a neutral compound add up to zero. F -1 O -2 H +1 Cl
Oxidation state of Mg in MgCl2? +2

14. Oxidation Numbers F -1 O -2 H +1 Cl -3 Oxidation state of N in NH3?
2. The oxidation numbers of atoms in a neutral compound add up to zero. F -1 O -2 H +1 Cl
Oxidation state of N in NH3? -3

15. Oxidation Numbers F -1 O -2 H +1 Cl -2 Oxidation state of S in S2-?
3. The oxidation numbers of a monatomic ion is equal to its charge. F -1 O -2 H +1 Cl
Oxidation state of S in S2-? -2

16. Oxidation Numbers F -1 O -2 H +1 Cl +6 Oxidation state of S in SO42-?
4. The oxidation numbers of atoms in a polyatomic ion add up to the charge on the ion. F -1 O -2 H +1 Cl
Oxidation state of S in SO42-?
? – 8 = -2
? = +6 +6

17. Oxidation Numbers F -1 O -2 H +1 Cl -3 Oxidation state of N in NH4+?
4. The oxidation numbers of atoms in a polyatomic ion add up to the charge on the ion. F -1 O -2 H +1 Cl
Oxidation state of N in NH4+? -3

18. Oxidation: Reduction: Loss of electrons Often a gain of Oxygen
Gain of electrons
Often a loss of Oxygen
Increase in
oxidation
number
Decrease in
oxidation
number

19. For these two reactions…
Burning magnesium
Copper in silver nitrate solution
Write…
Word equation
Balanced chemical equation

20. Redox Half Reactions
We can separate redox reactions into half reactions. These reactions illustrate the flow of electrons from the electron donor (reducing agent) to the electron acceptor (oxidizing agent).

21. 2Mg(s) + O2(g)  2MgO(s) Mg  Mg2+ O  O2-
Redox Half Reactions
2Mg(s) + O2(g)  2MgO(s)
Mg  Mg2+
Oxidized – loss of e-
+2e-
O  O2-
Reduced – gain of e-
+2e-

22. Cu(s) + 2AgNO3(aq)  Cu(NO3 )2(aq) + 2Ag(s)
Redox Half Reactions
Cu(s) + 2AgNO3(aq)  Cu(NO3 )2(aq) + 2Ag(s)
Cu  Cu2+
Oxidized – loss of e-
+2e-
Ag  Ag
Reduced – gain of e-
+e-