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The Real Zeros of a Polynomial Function

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Presentation on theme: "The Real Zeros of a Polynomial Function"— Presentation transcript:

1 The Real Zeros of a Polynomial Function
Section 5.2 The Real Zeros of a Polynomial Function

2 OBJECTIVE 1

3

4

5 (a) f(-2) = (-2)3 + 3(-2)2 + 2(-2) -1 = -1
(b) f(1) = (1)3 + 3(1)2 + 2(1) -1 = 5

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7 a) f(-1) = -2(-1)3 - (-1)2 + 4(-1) + 3 = 0  x + 1 is a factor
b) f(1) = -2(1)3 – (1)2 + 4(1) + 3 = 4  x - 1 is NOT a factor

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9 OBJECTIVE 2

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11 p: ±1, ±2, ±3, ±4, ±6, ±12 q: ±1, ±3 p/q: ±1, ±1/3, ±2, ±2/3, ±3, ±4, ±4/3, ±6, ±12

12 OBJECTIVE 3

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14 p/q: ±1, ±1/3, ±2, ±2/3, ±3, ±4, ±4/3, ±6, ±12

15 f(-3) = 3(-3) (-3) (-3) – 12 = 0 f(-1) = 3(-1) (-1) (-1) – 12 = 0 f(4/3) = 3(4/3) (4/3)2 - 7(4/3) – 12 = 0 -3 | ____________ (x + 3)(3x2 –x - 4) (x + 3)(3x – 4)(x + 1)

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17 p: ±1, ±3, ±9 q: ±1, ±2 p/q: ±1, ±1/2, ±3, ±3/2, ±9, ±9/2

18 p/q: -1, ±1/2, -3, -3/2, ±9, ±9/2

19 f(-3) = 2(-3)4 + 13(-3)3 + 29(-3)2 + 27(-3) + 9 = 0
-1 | _________________ (x + 1)(2x x x + 9) -3 | _________________ (x + 1)(x + 3)(2x2 + 5x + 3) = (x + 1)(x + 3)(2x + 3)(x + 1) = (x + 1)2(x + 3)(2x + 3)

20 OBJECTIVE 5

21 BOUND

22 Smaller of two values is 10 Bound is -10 ≤ x ≤ 10
g(x) = 4(x5 – 1/2x3 + 1/2x2 + 1/4) Max{ 1, } = Max{1, 17} = 17 Max{ 1, 1/2 + 1/2 + 1/4} = Max{1, 5/4} = 5/4 1 + Max{3, 9, 5} = = 10 1 + Max{1/2, 1/2, 1/4} = 1 + ½ = 3/2 Smaller of two values is 10 Bound is -10 ≤ x ≤ 10 Smaller of two values is 5/4. Bound is -5/4 ≤ x ≤ 5/4

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24 May be at most 5 zeros. Can NOT use Rational Zeros Theorem (non-integer coefficients) Find bounds: Max{1, } = Max{1, } = 1 + Max{1.8, 17.79, , 37.95, } = 38.95 Bound: 38.95

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26 OBJECTIVE 6

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28 Using the function from the last example, determine whether there is a repeated zero or two distinct zeros near 3.30. f(3.29) = > 0 and f(3.30) = < 0 f(3.30) = < 0 and f(3.31) = > 0

29 Use xmin 3.29 and xmax 3.31 Use ymin and ymax


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