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Unit 4. Day 13.
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A math βsentenceβ with an equal sign
Q: What is an equation? A: A math βsentenceβ with an equal sign 3π₯ + 4 = 78 3 5βπ¦ =6β3π¦ 6 π+5 =7β9π Q: What does it mean to solve an equation? A: To find the value of the variable Q: How do we solve an equation? A: Isolate the variable
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5 4 π₯ = π₯β 3 4 = 1 2 = = Example A: Solve. + 3 4 + 3 4 1 2 + 3 4
π₯β 3 4 = 1 2 + 3 4 + 3 4 5 4 π₯ = 5 4 = =
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πβ 2 7 =4 Example B*: π¦ = 3 4 Example C*:
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30 7 π = πβ 2 7 =4 = = = Example B*: Solve. + 2 7 + 2 7 4+ 2 7
πβ 2 7 =4 + 2 7 + 2 7 30 7 π = 4+ 2 7 30 7 = = =
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β 1 12 π¦ = π¦+ 5 6 = 3 4 = = Example C*: Solve. β 5 6 β 5 6 3 4 β 5 6
π¦ = 3 4 β 5 6 β 5 6 β 1 12 π¦ = 3 4 β 5 6 9 12 β 10 12 β 1 12 = =
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3 8 π₯ = 1 10 1 10 β π₯ = Γ· 3 8 π₯ = 1 10 β π₯ = β π₯ = = = Example D: 3 8
3 8 π₯ = 1 10 1 10 β π₯ = Γ· 3 8 3 8 3 8 8 3 3 8 π₯ = 1 10 8 3 β π₯ = β 8 30 4 15 1 10 8 3 8 30 π₯ = β = =
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6 5 β = 3 4 Example E*: β 3 2 π₯ = 7 8 Example F*:
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6 5 β = 3 4 3 4 β β = Γ· 6 5 β = 3 4 β β = β β = = = Example E*: 6 5
6 5 β = 3 4 3 4 β β = Γ· 6 5 6 5 6 5 6 5 β = 3 4 5 6 5 6 β β = β 15 24 5 8 3 4 5 6 15 24 β = β = =
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β 3 2 π₯+ 1 6 = 7 8 = = β 3 2 π₯ 17 24 = π₯= Example F*: Solve. β 1 6
β 3 2 π₯ = 7 8 Example F*: Solve. 7 8 β 1 6 21 24 β 4 24 17 24 β 1 6 β 1 6 = = β 3 2 π₯ 17 24 β = β 3 2 β 3 2 17 24 β 3 2 π₯= Γ· 17 24 β 2 3 34 2β17 β 17 36 π₯ = β = β = = 72 2β2β2β3β3
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