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Unit 4. Day 13..

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Presentation on theme: "Unit 4. Day 13.."β€” Presentation transcript:

1 Unit 4. Day 13.

2 A math β€œsentence” with an equal sign
Q: What is an equation? A: A math β€œsentence” with an equal sign 3π‘₯ + 4 = 78 3 5βˆ’π‘¦ =6βˆ’3𝑦 6 π‘Ž+5 =7βˆ’9π‘Ž Q: What does it mean to solve an equation? A: To find the value of the variable Q: How do we solve an equation? A: Isolate the variable

3 5 4 π‘₯ = π‘₯βˆ’ 3 4 = 1 2 = = Example A: Solve. + 3 4 + 3 4 1 2 + 3 4
π‘₯βˆ’ 3 4 = 1 2 + 3 4 + 3 4 5 4 π‘₯ = 5 4 = =

4 π‘šβˆ’ 2 7 =4 Example B*: 𝑦 = 3 4 Example C*:

5 30 7 π‘š = π‘šβˆ’ 2 7 =4 = = = Example B*: Solve. + 2 7 + 2 7 4+ 2 7
π‘šβˆ’ 2 7 =4 + 2 7 + 2 7 30 7 π‘š = 4+ 2 7 30 7 = = =

6 βˆ’ 1 12 𝑦 = 𝑦+ 5 6 = 3 4 = = Example C*: Solve. βˆ’ 5 6 βˆ’ 5 6 3 4 βˆ’ 5 6
𝑦 = 3 4 βˆ’ 5 6 βˆ’ 5 6 βˆ’ 1 12 𝑦 = 3 4 βˆ’ 5 6 9 12 βˆ’ 10 12 βˆ’ 1 12 = =

7 3 8 π‘₯ = 1 10 1 10 βˆ™ π‘₯ = Γ· 3 8 π‘₯ = 1 10 βˆ™ π‘₯ = βˆ™ π‘₯ = = = Example D: 3 8
3 8 π‘₯ = 1 10 1 10 βˆ™ π‘₯ = Γ· 3 8 3 8 3 8 8 3 3 8 π‘₯ = 1 10 8 3 βˆ™ π‘₯ = βˆ™ 8 30 4 15 1 10 8 3 8 30 π‘₯ = βˆ™ = =

8 6 5 β„Ž = 3 4 Example E*: βˆ’ 3 2 π‘₯ = 7 8 Example F*:

9 6 5 β„Ž = 3 4 3 4 βˆ™ β„Ž = Γ· 6 5 β„Ž = 3 4 βˆ™ β„Ž = βˆ™ β„Ž = = = Example E*: 6 5
6 5 β„Ž = 3 4 3 4 βˆ™ β„Ž = Γ· 6 5 6 5 6 5 6 5 β„Ž = 3 4 5 6 5 6 βˆ™ β„Ž = βˆ™ 15 24 5 8 3 4 5 6 15 24 β„Ž = βˆ™ = =

10 βˆ’ 3 2 π‘₯+ 1 6 = 7 8 = = βˆ’ 3 2 π‘₯ 17 24 = π‘₯= Example F*: Solve. βˆ’ 1 6
βˆ’ 3 2 π‘₯ = 7 8 Example F*: Solve. 7 8 βˆ’ 1 6 21 24 βˆ’ 4 24 17 24 βˆ’ 1 6 βˆ’ 1 6 = = βˆ’ 3 2 π‘₯ 17 24 βˆ™ = βˆ’ 3 2 βˆ’ 3 2 17 24 βˆ’ 3 2 π‘₯= Γ· 17 24 βˆ’ 2 3 34 2βˆ™17 βˆ’ 17 36 π‘₯ = βˆ™ = βˆ’ = = 72 2βˆ™2βˆ™2βˆ™3βˆ™3


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