1. Force on springs F = kx F = restoring force (in N)
k = spring constant (in N/m) (spring stiffness)
x - Amount the spring has been distorted (in m) (stretched,/compressed)

2. A spring requires 15 N to stretch 42 cm. k = ?
F = kx
15 N = k(.42 m),
k = (15 N)/(.42 m) = 35.7 N/m
35.7 N/m

3. Ali Zabov stretches a 53 N/m spring 13 cm with what force?
F = kx
= (53 N/m)(.13 m) = 6.89 N = 6.9 N
6.9 N

4. Nona Zabov allows the weight of a 2
Nona Zabov allows the weight of a 2.1 kg mass to stretch a 35 N/m spring. What distance does it stretch?
F = ma, weight = mg
F = kx
F = (2.1 kg)(9.8 N/kg) = N F = kx, x = F/k
x = (20.58 N)/(35 N/m) = .588 m = .59 m
.59 m