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Algebra and Modeling 2018 Algebra and Modeling 2018 Algebra 1 Bootcamp
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MAFS.912.A-APR.1.1 Which expression is equivalent to 2 3šā4 ā 8š+3 ?
Algebra and Modeling MAFS.912.A-APR.1.1 Which expression is equivalent to 2 3šā4 ā 8š+3 ? ā2gā1 ā2gā5 ā2gā7 ā2gā11 Group 1 D 2018 Algebra 1 Bootcamp
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MAFS.912.A-APR.1.1 Simplify: 3 3 š 2 ā4š¾+6 ā 8 š 2 +š+3 ? š 2 ā13š+15
Algebra and Modeling MAFS.912.A-APR.1.1 Simplify: 3 3 š 2 ā4š¾+6 ā 8 š 2 +š+3 ? š 2 ā13š+15 Group 1 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-APR.1.1 Write an expression which is equivalent to š¤(4š¤3 + 8š¤4) ā (5š¤3 ā 2š¤5) 10w5 + 4w4 ā 5w3 Group 1 and 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-APR.1.1 Multiply and combine like terms to determine the product of these polynomials. 2š„ā3 5š„+6 10 š„ 2 ā3š„ā18 Group 1 and 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-APR.1.1 The area of a trapezoid is found using the formula š“= 1 2 ā š 1 + š 2 , where š“ is the area, ā is the height, and š 1 and š 2 are the lengths of the bases. What is the area of the above trapezoid? š“ = 4š„ + 2 š“ = 4š„ + 8 š“ = 2š„² + 4š„ ā 21 š“ = 2š„² + 8š„ ā 42 Groups 1 and 2 B 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-APR.1.1 Which expression is equivalent to ā2š 3š+š ā7 +3 ā6š +2š +š š+4š ā 5 ? A. 4š2 ā 5šš ā 23š + 22š B. 4š2 + 2š2 ā 5šš ā 23š ā 8š C. 4š2 ā 2š2 ā 5šš ā 23š + 20š D. 4š2 ā 2š2 ā 6šš ā 23š + 20š Group 2 and 3 C 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-APR.1.1 Find the area of the shaded region of the square, with side length 2š„ ā 3, if each of the ovals has an area of š„ā5 square inches. 4 š„ 2 ā14š„+19 Group 2 and 3 Howard County Public Schools Office of Secondary Mathematics Curricular Projects has licensed this product under a Creative Commons Attribution-NonCommercial-NoDerivs 3.0 Unported License 2018 Algebra 1 Bootcamp
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MAFS.912.A-APR.1.1 Both š(š„) and š(š„) are polynomial functions.
Algebra and Modeling NEW MAFS.912.A-APR.1.1 Both š(š„) and š(š„) are polynomial functions. Determine whether each expression must be a polynomial. Must Be a Polynomial May Not Be a Polynomial š š„ +š(š„) š(š„) š š„ āš(š„) š š„ +š(š„) š(š„) Groups 2 and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-APR.1.1 Consider the polynomial: 2 3 š„(2š„+3)ā š„+7 š„ā7
Algebra and Modeling MAFS.912.A-APR.1.1 Consider the polynomial: 2 3 š„(2š„+3)ā š„+7 š„ā7 When simplified, what is the coefficient of the quadratic term? 1 3 Group 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-APR.1.1 Multiply and combine like terms to determine the product of these polynomials. (ā2š„ā3)(2 š„ 2 āš„+1)(š„ā2) ā4 š„ 4 +4 š„ 3 +9 š„ 2 ā5š„+6 Group 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-APR.1.1 The polynomial 2š„ā1 š„ 2 ā2 āš„( š„ 2 āš„ā2) can be written in the form š š„ 3 +š š„ 2 +šš„+š, where š, š, š, and š are constants. What are the values of š, š, š, and š? š= š= š= š= 1 Group 3 ā2 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-APR.1.1 Kiera claimed that the sum of two linear polynomials with rational coefficients is always a linear polynomial with rational coefficients. Drag the six statements into a logical sequence to outline an argument that proves this claim. Group 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.1 A fence is being built around a rectangular garden. The length of the garden is 35 feet, and the total fencing used to enclose the garden measures 160 feet. Which equation can be used to find the width, , of the garden, in feet? 35š¤=160 70š¤=160 35+2š¤=160 70+2š¤=160 Groups 1 and 2 D 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 A parking garage charges a base rate of $3.50 for up to 2 hours, and an hourly rate for each additional hour. The sign below gives the prices for up to 5 hours of parking. Which linear equation can be used to find x, the additional hourly parking rate? Group 1 and 2 9.00+3š„=20.00 š„=20.00 2š„+3.50=14.50 2š„+9.00=14.50 C 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 Kyran was given a check for $100 by his grandmother for his birthday, but had to promise her that he would invest the money in a bank until it had at least doubled in value. Kyran agreed, reluctantly, and found a bank where he could invest the $100 in a simple interest account that would gain 5% interest per year. If š¦ represents the number of years that Kyran will invest his money, which inequality could be used to find when he would have at least $200 in his account? 200< š¦ 200ā¤100(1+0.05š¦) 200> š¦ 200ā„100(1+0.05š¦) Group 1 and 2 B 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 Carmella just planted seeds for her vegetable garden. Anxious to view the progress of her plants, she checks her garden one afternoon, but sees that 4 weeds she has never seen before are growing in her vegetable garden. After a few weeks, she notices that the number of weeds appears to be tripling each week. If she doesnāt do something, she calculates that there could soon be 972 weeds in her garden. If š¤ represents the number of weeks, which equation could be used to determine what week Carmella would expect to find 972 weeds in her garden: 3š¤+4=972 3 (4) š¤ =972 4 (3) š¤ =972 4 (š¤) 3 =972 Group 1 and 2 C 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 A sales clerkās daily earnings include $125 per day plus commission equal to š„ percent of his daily sales. Enter an equation that can be used to find the commission percentage (š„), if the clerkās daily sales are $1375 and his total earnings for that day are $180. 125+ š„ 100 ā1375=180 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.1 John has a goal to ride his bike at least 100 miles this summer. John has ridden 12 miles thus far. There are 40 days left in the summer. Part A Write an inequality to represent the average distance, d, in miles, John must ride each day for the rest of the summer to achieve his goal. Enter your inequality in the space provided. 40š ā„ 100 Part B Determine the average number of miles John must ride each day to reach exactly 100 miles. Enter your answer in the space provided. Groups 1, 2, and 3 2.2 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.1 A school purchases boxes of candy bars.
Algebra and Modeling NEW MAFS.912.A-CED.1.1 A school purchases boxes of candy bars. Each box contains 50 candy bars. Each box costs $30. How much does the school have to charge for each candy bar to make a profit of $10 per box? $0.40 $0.50 $0.80 $1.25 Groups 1, 2, and 3 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.1 Kendrick deposits twice as much money into his account as he did the day before. His initial deposit is $5. Write an equation to model his daily deposit, š¦, š„ days after his initial deposit. š¦=5 2 š„ Groups 2 and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is Which equation could be used to find Jeremyās age, š, if he is the younger man? š 2 +2=783 š 2 ā2=783 š 2 +2š=783 š 2 ā2š=783 Group 2 and 3 C 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 A rectangular garden measures 13 meters by 17 meters and has cement walkway around its perimeter, as shown. The width of the walkway remains constant on all four sides. The garden and walkway have a combined area of 396 square meters. Part A: Enter an equation that can be used to help determine the width, š¤, of the walkway in the first response box. Part B: Determine the width, in meters, of the walkway. Enter your answer in the second response box. (17+2š¤)(13+2š¤)=396 Group 2 and 3 5 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.1 The length of a rectangle is 2 inches more than a number. The width is 1 inch less than twice the same number. If the area of the rectangle is 42 šš 2 , find the dimensions of the rectangle. Width: 4 in Length: 4 in Width: 6 in Length: 6 in Width: 7 in Length: 7 in Group 3 Length: 6 in, Width: 7 in 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.1 Two boys, Shawn and Curtis, went for a walk. Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per second. Curtis walked at a speed of 6 feet per second. For how many seconds had Shawn been walking at the moment when the two boys had walked exactly the same distance? Enter your answer in the space provided. Group 3 120 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-REI.2.3 Enter the value for š„ that makes the given equation true. 20š„ā5 6š„+4 =4š„ā6 ā1 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-REI.2.3 What is the solution of 3 2š„ā1 ā¤4š„+7?. š„ā¤5
Algebra and Modeling MAFS.912.A-REI.2.3 What is the solution of 3 2š„ā1 ā¤4š„+7?. š„ā¤5 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-REI.2.3 Solve for š„: 3 5 š„+2 =š„ā4 13 Algebra and Modeling
3 5 š„+2 =š„ā4 13 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-REI.2.3 Solve algebraically for š„: 2 š„ā4 ā„ 1 2 (š„ā4) š„ā„4
Algebra and Modeling MAFS.912.A-REI.2.3 Solve algebraically for š„: 2 š„ā4 ā„ 1 2 (š„ā4) š„ā„4 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-REI.2.3 Solve for š„: (š„+4) 2 =4š„ā6 š„= 16 7 š„= 8 3 š„= 10 3
Algebra and Modeling MAFS.912.A-REI.2.3 Solve for š„: (š„+4) 2 =4š„ā6 š„= 16 7 š„= 8 3 š„= 10 3 š„=7 Groups 1, 2, and 3 š“ 2018 Algebra 1 Bootcamp
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MAFS.912.A-REI.2.3 Consider the inequality 51ā¤šš„+9.
Algebra and Modeling NEW MAFS.912.A-REI.2.3 Consider the inequality 51ā¤šš„+9. What value of š will result in the solution š„ā„7? 6 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-REI.2.3 The value of š„ which makes š„ā2 = š„ā1 true is: ā11. 3 ā10 ā9. 09 ā2 Groups 2 and 3 š“ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-REI.2.3 Equivalent equations have exactly the same solution set. Select Yes or No to indicate whether each equation is equivalent to this equation: 4š„+3= 5 2 š„ā7 Equation Yes No 4š„= 5 2 š„ā4 8š„+3=5š„ā7 4š„= 5 2 š„ā10 Groups 2 and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.4 Solve 5š+12š=9 for š. š· š=5 12šā9 š=5 9ā12š
Algebra and Modeling MAFS.912.A-CED.1.4 Solve 5š+12š=9 for š. š=5 12šā9 š=5 9ā12š š= 12šā9 5 š= 9ā12š 5 Group 1 and 2 š· 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.4 Solve 7š„ā2š§=4āš„š¦ for š„. š· š„=4āš„š¦+ 2š§ 7 š„= 4āš„š¦+2š§ 7
Algebra and Modeling MAFS.912.A-CED.1.4 Solve 7š„ā2š§=4āš„š¦ for š„. š„=4āš„š¦+ 2š§ 7 š„= 4āš„š¦+2š§ 7 š„=4+2š§ā(7+š¦) š„= 4+2š§ (7+š¦) Groups 2 and 3 š· 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.4 If šš„āš š”=š, which expression represents š„. š+š š” š
Algebra and Modeling MAFS.912.A-CED.1.4 If šš„āš š”=š, which expression represents š„. š+š š” š š š+š š” š šāš š” šāš š” š Groups 1, 2 and 3 š“ 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.4 If šš„āš š”=š, which expression represents š. š š” (š„ā1)
Algebra and Modeling MAFS.912.A-CED.1.4 If šš„āš š”=š, which expression represents š. š š” (š„ā1) 1+š š” š„ š š” š„ š š”ā(š„+š) Groups 2 and 3 š“ 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.4 Consider the given equation. 4 š 2 + 5š = 9š ā 7š
Algebra and Modeling NEW MAFS.912.A-CED.1.4 Consider the given equation. 4 š š = 9š ā 7š Solve the equation for š. Select all that apply. š= ā7šā4 š 2 5 š= 4šā7š 4 š= 4 š 2 +7š 4 š= 4 š 2 ā4š 7 š= š 2 + 7š 4 Groups 2 and 3 C and E 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.2 Emily has a gift certificate for $10 to use at an online store. She can purchase songs for $1 each or episodes of TV shows for $3 each. She wants to spend exactly $10. Create an equation to show the relationship between the number of songs, š„, Emily can purchase and the number of episodes of TV shows, š¦, she can purchase. š„+3š¦=10 Groups 1 and 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.2 Grace and her brother need $400 to go to band camp. Their parents have agreed to help them earn money by paying them $25 each time they mow the lawn and $10 for each hour they babysit their younger brother. They will have to do a combination of both chores to earn the money. Select the equation that represents the number of lawns they can mow, š, and hours they can babysit, š, to earn $400. 10š + 25š = 400 10š ā 25š = 400 25š + 10š = 400 25š ā 10š = 400 Groups 1, 2, and 3 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.2 Jessieās bus ride to school is 5 minutes more than the time of Robertās bus ride. Which graph shows the possible times of Jessieās and Robertās bus rides? A. B. C. D. Groups 1, 2, and 3 šµ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.2 An elementary school is having sand delivered for the playground. Sadieās Sand charges $5.00 per ton of sand plus a delivery fee of $200. Gregās Sand Pit charges $12.00 per ton of sand plus a delivery fee of $50. Use the graph below to represent functions that show the cost C of buying T tons of sand from each company. Groups 1, 2 and 3 2018 Algebra 1 Bootcamp
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MAFS.912.A-CED.1.2 š=(15š„)(10š„+25)+200 š=15š„+(10š„+25)+200 š=25š„+225
Algebra and Modeling MAFS.912.A-CED.1.2 A local coffee company, Netherlanders Sisters, is trying to determine how much it costs to run a coffee stand for one day. The daily cost to pay employees can be represented by 15š„, the daily cost for ingredients/supplies can be represented by 10š„+25, and the daily cost to rent the coffee stand is $200. It has been determined that the product of the daily cost of employees and the daily cost of ingredients/supplies, plus the daily cost to rent the coffee stand represents the total cost to run the coffee stand for one day. Select all of the equations, which could be used to find the daily cost, š, to run the coffee stand: š=(15š„)(10š„+25)+200 š=15š„+(10š„+25)+200 š=25š„+225 š=150 š„ š„+200 š=(15š„)(10š„+25)(200) Groups 2 and 3 A and D 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.2 Meredith is purchasing a new toilet for her home. Toilet A costs $149 and uses approximately 380 gallons of water per month. Toilet B costs $169 and uses approximately 300 gallons of water per month. Water costs $2.75 per 1000 gallons. Part A: Write a system of equations that models this situation. A. A= ā300āt B= ā380āt C. A= ā0.3āt B= ā0.38āt B. A= ā380āt B= ā300āt D. A= ā0.38āt B= ā0.3āt š· Part B: How many months will it take for Toilet B to be more cost effective? Groups 2 and 3 91 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.2 Malik and Nora are playing a video game. ⢠Malik starts with m points and Nora starts n points. ⢠Then Malik gets 150 more points, while Nora loses 50 points. ⢠Finally, Nora gets a bonus and her score is doubled. ⢠Nora now has 50 more points than Malik. Write an equation that represents the relationship between š and š given the information above. 2 šā50 = š Groups 2 and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912.A-CED.1.2 The floor of a rectangular cage has a length 4 feet greater than its width, š¤. James will increase both dimensions of the floor by 2 feet. Which equation represents the new area, š, of the floor of the cage? š = š¤ 2 + 4š¤ š = š¤ 2 + 6š¤ š = š¤ 2 + 6š¤ + 8 š = š¤ 2 + 8š¤ + 12 Groups 2 and 3 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912.A-CED.1.2 Maia deposited $5,500 in a bank account. The money earns interest annually, and the interest is deposited back into her account. Maia uses an online calculator to determine the amount of money she will have in the account at the end of each year. The amount of money that Maia will have in her account at the end of the selected year, up to 6 years, is shown in the table below. Enter an equation that models the amount of money, y, Maia will have in the account at the end of š” years. Years Money in Bank 1 5,665.00 2 5,834.95 3 6,009.99 4 6,190.30 5 6,376.01 6 6,567.29 š¦=5, š” Group 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.5 Which system of equations has the same solution as the system below? š„+3š¦=6 4š„ā8š¦=4 ā5š„+15š¦=30 5š„ā5š¦=10 5š„+15š¦=30 ā5š„ā15š¦=ā30 5š„+š¦=10 A. B. Groups 2 and 3 C. D. šµ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.5 Mr. Xavier is solving the system of equations 4š„ ā 3š¦ = 9 and 2š„ + 6š¦ = 5. Which system of equations has the same solution as the system that Mr. Xavier is solving? A. 4š„ ā 3š¦ = 9 ā19š¦=ā1 4š„ā3š¦=9 9š¦=19 2š„+6š¦=5 6š„=23 10š„=23 B. Group 3 C. D. š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.6 The equations 5š„+2š¦=48 and 3š„+2š¦=32 represent the money collected from school concert ticket sales during two class periods. If š„ represents the cost for each adult ticket and š¦ represents the cost for each student ticket, what is the cost for each adult ticket? š„=8 Groups 1 and 2 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.3.6 A system of equations is shown below.
Algebra and Modeling NEW MAFS.912. A-REI.3.6 A system of equations is shown below. Equation šØ: 5š„ + 9š¦ = 12 Equation š©: 4š„ ā 3š¦ = 8 Which method eliminates one of the variables? Multiply equation š“ by ā 1 3 and add the result to equation šµ. Multiply equation šµ by 3 and add the result to equation š“. Multiply equation š“ by 2 and equation šµ by ā6 and add the results together. Multiply equation šµ by 5 and equation š“ by 4 and add the results together. Groups 1, 2, and 3 šµ 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI.3.6 The math club sells candy bars and drinks during football games. 60 candy bars and 110 drinks will sell for $265. 120 candy bars and 90 drinks will sell for $270. How much does each candy bar sell for? Enter your answer in the space provided. 0.75 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI.3.6 Jackie buys 3 hot dogs and 1 pretzel from a restaurant for $ Sylvia buys 2 hot dogs and 4 pretzels from the same restaurant for $16.50. Part A Which system of equations can be used to determine the price of a hot dog, ā, and a pretzel, š, at the restaurant? Part B What is the price of a hot dog at the restaurant? Enter your answer in the space provided. 3ā + 1š = 12.25 2ā + 4š = 16.50 2ā + 1š = 12.25 3ā + 4š = 16.50 3ā + 2ā = 12.25 1š + 4š = 16.50 2ā + 4š = 12.25 3ā + 1š = 16.50 A. B. C. D. 3.25 Groups 1, 2, and 3 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.6 A restaurant serves a vegetarian and a chicken lunch special each day. Each vegetarian special is the same price. Each chicken special is the same price. However, the price of the vegetarian special is different from the price of the chicken special. On Thursday, the restaurant collected $467 selling 21 vegetarian specials and 40 chicken specials. On Friday, the restaurant collected $484 selling 28 vegetarian specials and 36 chicken specials. What is the cost, in dollars, of each lunch special? 7 Group 3 8 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.6 The basketball team sold t-shirts and hats as a fund-raiser. They sold a total of 23 items and made a profit of $246. They made a profit of $10 for every t-shirt they sold and $12 for every hat they sold. Determine the number of t-shirts and the number of hats the basketball team sold. Enter the number of t-shirts in the first response box. Enter the number of hats in the second response box. 15 8 Group 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.4.12 Which is a graph of the solution set of the inequality 3š¦ ā š„ > 6? A. B. C. D. Group 1 š¶ 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.4.12 Which inequality does this graph represent?
Algebra and Modeling MAFS.912. A-REI.4.12 Which inequality does this graph represent? A. š¦ > 3š„ + 2 B. š¦ > ā3š„ ā 2 C. š¦ < 3š„ ā 2 D. š¦ < ā3š„ ā 2 Group 1 and 2 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI.4.12 What scenario could be modeled by the graph below? The number of pounds of apples, š¦, minus two times the number of pounds of oranges, š„, is at most 5. The number of pounds of apples, š¦, minus half the number of pounds of oranges, š„, is at most 5. The number of pounds of apples, š¦, plus two times the number of pounds of oranges, š„, is at most 5. The number of pounds of apples, š¦, plus half the number of pounds of oranges, š„, is at most 5. Groups 1, 2, and 3 š¶ 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.4.12 š¦<ā5š„ā2 š¦ā¤āš„+2
Algebra and Modeling MAFS.912. A-REI.4.12 š¦<ā5š„ā2 š¦ā¤āš„+2 Graph the system of inequalities: A. B. C. D. Groups 1, 2, and 3 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.4.12 The coordinate grid below shows points A through J. Given the system of inequalities shown below, select all the points that are solutions to this system of inequalities. š„+š¦<3 2š„āš¦>ā6 A B C D E F G Groups 1, 2, and 3 A , F, and G 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.4.12 Determine the solution to the system of inequalities: 3š„+3š¦ā¤3 š„ā3š¦ā„ā6 Groups 2 and 3 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.4.12 Consider the system of inequalities. 3š„+2š¦<8
Algebra and Modeling NEW MAFS.912. A-REI.4.12 Consider the system of inequalities. 3š„+2š¦<8 ā5š„ā9š¦ā„2 Select all ordered pairs that are solutions to the system of inequalities. ā10, ā3 ā2, 7 0, 0 1, ā1 4, ā2 8, 9 Groups 2 and 3 A and D 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-CED.1.3 The number of medals won by an Olympic Team is modeled by š¦ = 3š„ + 5, where š„ is the number of athletes. The number of medals for another team is modeled by š¦ =5š„ ā 8, where š„ is the number of athletes. Part A: For what number of athletes would both teams have the same number of Olympic medals? Part B: Is this a viable answer? Explain. š„= or š„=6.5 This answer is not a viable solution because you cannot have part of an athlete. 6.5 athletes implies half an athlete, which is not possible in the context of the problem. Groups 1 and 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-CED.1.3 Alicia purchased š» half-gallons of ice cream for $3.50 each and š packages of ice cream cones for $2.50 each. She purchased 14 items and spent $43. Which system of equations could be used to determine how many of each item Alicia purchased? 3.50š» š = 43 š»+š=14 3.50š+ 2.50š» = 43 š+š»=14 3.50š»+ 2.50š =14 š»+š=43 A. B. C. D. Groups 1, 2, and 3 A 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-CED.1.3 David has two jobs. He earns $8 per hour babysitting his neighborās children and he earns $11 per hour working at the coffee shop. Part A: Write an inequality to represent the number of hours, š„, babysitting and the number of hours, š¦, working at the coffee shop that David will need to work to earn a minimum of $200. Part B: David worked 15 hours at the coffee shop. Use the inequality to find the number of full hours he must babysit to reach his goal of $200. 8š„+11š¦ā„200 5 Group 2 2018 Algebra 1 Bootcamp
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MAFS.912. A-CED.1.3 š+š”ā¤10 šā„1 š”ā„1 š+š”ā„10 šā„0 š”ā„0
Algebra and Modeling MAFS.912. A-CED.1.3 In a community service program, students earn points for painting over graffiti and picking up trash. The following restrictions are imposed on the program: A student may not serve more than 10 total hours per week; and A student must serve at least 1 hour per week at each task. Let š= the number of hours a student spends in a week painting over graffiti. Let š”= the number of hours a student spends in a week picking up trash. Part A: Which system represents the imposed constraints? Part B: Which numbers of hours spent painting over graffiti and hours spent picking up trash could fit the community service requirements? Select all that apply. A. C. š+š”ā¤10 šā„1 š”ā„1 š+š”ā„10 šā„0 š”ā„0 Group 3 3 graffiti hours and 4 trash hours 6 graffiti hours and 7 trash hours 8 graffiti hours and 3 trash hours 9 graffiti hours and 1 trash hours 0 graffiti hours and 10 trash hours 5 graffiti hours and 5 trash hours B. D. š+š”ā¤10 šā„0 š”ā„0 š+š”<10 š=š” A A, D, and F 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.1.1 When solving for the value of š„ in the equation 4(š„ā1)+3=18 , Aaron wrote the following lines on the board. Step 1 4 š„ā1 +3=18 Step 2 4 š„ā1 =15 Step 3 4š„ā1=15 Step 4 4š„=16 Step 5 š„=4 Which property was used incorrectly when going from Step 2 to Step 3? Addition Property Distributive Property Substitution Property Transitive Property Groups 1, 2, and 3 šµ 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.1.1 Martha solved the equation 5 š+3 =š+39.
Algebra and Modeling MAFS.912. A-REI.1.1 Martha solved the equation 5 š+3 =š+39. Which step is the first incorrect step in Marthaās solution shown above? Step 1 5(š+3)=š+39 Step 2 5š+15=š+39 Step 3 6š+15=39 Step 4 6š=24 Step 5 š=4 Step 2 Step 3 Step 4 Step 5 Groups 1, 2, and 3 šµ 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI.1.1 When solving the equation 12 š„ 2 ā7š„=6ā2( š„ 2 ā1), Evan wrote š„ 2 ā7š„=6ā2 š„ 2 +2, as his first step. Which property justifies this step? subtraction property of equality multiplication property of equality associative property of multiplication distributive property of multiplication over subtraction Groups 1, 2, and 3 š· 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.2.4 Which are the solutions to š„ 2 +9š„=36? š„=ā12,š„=3
Algebra and Modeling MAFS.912. A-REI.2.4 Which are the solutions to š„ 2 +9š„=36? š„=ā12,š„=3 š„=4,š„=9 š„=12,š„=ā3 š„=ā4,š„=9 Groups 1, 2, and 3 š“ 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.2.4 Consider the equation š„ 2 ā12š„+49=22
Algebra and Modeling NEW MAFS.912. A-REI.2.4 Consider the equation š„ 2 ā12š„+49=22 Which equation has the same solution(s) as the given equation? (š„ā6) 2 = 9 (š„ā7) 2 = 22 (š„+7) 2 =4.7 (š„ā12) 2 = ā27 Groups 2 and 3 š“ 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.2.4 Solve by completing the square: š„ 2 ā6š„ā4=0 3± 13
Algebra and Modeling MAFS.912. A-REI.2.4 Solve by completing the square: š„ 2 ā6š„ā4=0 3± 13 ā3±2 13 3±2 13 ā3± 13 Group 3 š“ 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.2.4 Consider the equation. 2 š„+4 2 ā113=49
Algebra and Modeling NEW MAFS.912. A-REI.2.4 Consider the equation. 2 š„+4 2 ā113=49 What value(s) of š„ makes the equation true? Enter one solution in each response box. If there is only one solution, leave one response box blank. Group 3 5 ā13 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.2.4 Consider the equation. 3 š„ā5 2 +6=54
Algebra and Modeling NEW MAFS.912. A-REI.2.4 Consider the equation. 3 š„ā =54 What value(s) of š„ makes the equation true? Enter one solution in each response box. If there is only one solution, leave one response box blank. Group 3 1 9 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI.2.4 Which equations have no real solutions? Select all that apply. 2 š„ā3 2 =0 2 š„ =1 š„ā =8 š„ =2 š„ 2 +8š„=15 Group 3 B and D 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI. 4.11 Which system of equations has only one solution?
Algebra and Modeling NEW MAFS.912. A-REI. 4.11 Which system of equations has only one solution? š¦=š„+5 and š¦=ā3š„+6 š¦=š„ā2and š¦=š„+4 š¦=2š„+6 and š¦=2(š„+3) š¦= š„ 2 ā1 and š¦=1.5š„+1 Groups 1, 2, and 3 š“ 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI. 4.11 The graph of two functions is shown on the coordinate plane. Select all values of š„ for which š(š„) = š(š„). ā2 ā1 1 3 4 Groups 2 and 3 B and F 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI. 4.11 The graphs of the functions š and š are shown
Algebra and Modeling MAFS.912. A-REI. 4.11 The graphs of the functions š and š are shown Use the graphs to approximate the solution(s) to the equation f(š„) = š(š„). - 0.8 2 Group 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-REI. 4.11 Lucy and Barbara began saving money the same week. The table below shows the models for the amount of money Lucy and Barbara had saved after š„ weeks. After how many weeks will Lucy and Barbara have the same amount of money saved? 1.1 weeks 1.7 weeks 8 weeks 12 weeks Group 3 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.6 Based on the tables, at what point do the lines š¦ = āš„ + 5 and š¦ = 2š„ ā 1 intersect? (1, 1) (3, 5) (2, 3) (3, 2) Group 1 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.3.6 Look at the tables of values for two linear functions, š(š„) and š(š„). What is the solution to š(š„) = š(š„)? š„=3 Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.4.10 Choose the ordered pair that is a solution to the equation represented by the graph. (0, ā3) (2, 0) (2, 2) (ā3, 0) Group 1 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.4.10 Which points are on the graph of the equation 3 ā 6š„ + 2š¦ = ā5? Select all that apply. (-2, -10) (-1, 1) (0, 4) (4, 8) (6, 14) Groups 1 and 2 A, D, and E 2018 Algebra 1 Bootcamp
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MAFS.912. A-REI.4.10 When is this statement true? š¦ = š„ 2 + 4š„ ā 1
Algebra and Modeling MAFS.912. A-REI.4.10 When is this statement true? š¦ = š„ š„ ā 1 A. This statement is true for all positive values of š„ only. B. This statement is true for all negative values of š„ only. C. This statement is true for the point (1,4). D. This statement is true for the point (0,0). Groups 2 and 3 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI.4.10 For the function š š„ = 2 š„ . Is (5, 32) a solution to š(š„)? Explain. Yes, it is a solution. Two raised to the power of 5 is equal 32. Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-REI. 4.10 Which point is NOT on the graph represented by š¦= š„ 2 +3š„ā6? (ā6, 12) (ā4, ā2) (2, 4) (3, ā6) Group 3 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.2.3 Consider the function f x = š„ 2 ā 6š„ + 8.Rewrite the equation to reveal the zeros of the function. š¦=(š„ā4)(š„ā2) Group 1 and 2 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.2.3 Consider the function f x = š„ 2 ā2š„ ā3.Rewrite the equation to reveal the zeros of the function. š¦ =(š„+1)(š„ā3) Groups 1, 2, and 3 2018 Algebra 1 Bootcamp
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MAFS.912. A-SSE.2.3 Select all the equations with equivalent zeros.
Algebra and Modeling MAFS.912. A-SSE.2.3 Select all the equations with equivalent zeros. š¦= š„ 2 +14 š¦= š„ 2 +9š„+14 š¦= š„ā ā 25 4 š¦=(š„+7)(š„+2) Groups 2 and 3 š¦= 1 2 š„+7 2š„+2 B and D 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-SSE.2.3 Nora inherited a savings account that was started by her grandmother 25 years ago. This scenario is modeled by the function š“(š”) = š”+25 , where š“(š”) represents the value of the account, in dollars, š” years after the inheritance. Which function below is equivalent to š“(š”)? š“ š” = š” 25 š“ š” = š” š“ š” = š” š” š“ š” = š” Groups 2 and 3 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-SSE.2.3 A quadratic function is given as š š„ = š„ 2 +8š„+6. Rewrite the given function in an equivalent form that would reveal the vertex of the function. Enter your answer in the space provided. š š„ = š„+4 2 ā10 Groups 2 and 3 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.2.3 Arturo made an error when finding the minimum value of the function š(š„) = š„ 2 ā 6š„ His work is shown below. š(š„) = š„ 2 ā 6š„ + 10 š(š„) = ( š„ 2 ā 6š„ ā 9) š(š„) = (š„ ā 3) The vertex is (3, 19), so the minimum value is 19. Describe the error that Arturo made. Then give the correct minimum value of the function. Write your answer on the lines provided. Group 3 To complete the square, Arturo should have added 9 inside the parenthesis instead of subtracting 9. To keep the equation balanced he should have subtracted 9 instead of adding it. The correct minimum value of the function is 1. 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.2.3 Given (š„+4) is a factor of 2 š„ 2 +11š„+2š, determine the value of š. Since (š„+4) is a factor, š must be 4. Since (š„+4) is a factor, š„=ā4. Substitute ā4 into 2 š„ 2 +11š„+2š=0 and solve for š to get š=6. Since (š„+4) is a factor, 2š=ā4, therefore š=ā2. Since (š„+4) is a factor, š„=4. Substitute 4 into 2 š„ 2 +11š„+2š=0 and solve for š to get š=ā38. Group 3 B 2018 Algebra 1 Bootcamp
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MAFS.912. A-SSE.2.3 Select all expressions equivalent to 16 2 šā3
Algebra and Modeling NEW MAFS.912. A-SSE.2.3 Select all expressions equivalent to šā3 2 4šā12 2 4šā3 2 š+1 8 2 šā1 8 2 šā2 Group 3 C and E 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.1.1 In the equation š¦ = š„ , what value does the 35 represent? š„-intercept Starting value Growth rate Decay rate Groups 1 and 2 šµ 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.1.1 Is the equation š“=21000 (1ā0.12) š” a model of exponential growth or exponential decay, and what is the rate (percent) of change per time period? exponential growth and 12% exponential growth and 88% exponential decay and 12% exponential decay and 88% Groups 1 and 2 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A-SSE.1.1 A scientist began a study with a sample of 1,500 bacteria. He noticed that the number of bacteria in the sample after š” days can be modeled by the equation š=1,500ā 5 š” . In this equation, what does 5 š” represent? The number of bacteria increases by 5 bacteria each day. The number of bacteria increases by š” bacteria after 5 days. The number of bacteria increases by a factor of 5 each day. The number of bacteria increases by a factor of š” each day for 5 days. Groups 1, 2, and 3 š¶ 2018 Algebra 1 Bootcamp
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MAFS.912. A-SSE.1.1 š+š š„+š¦ š„š+š š¦
Algebra and Modeling MAFS.912. A-SSE.1.1 A company uses two different-sized trucks to deliver cement. The first truck can deliver š„ cubic yards at a time and the second š¦ cubic yards. The first truck makes š trips to a job site, while the second truck makes š trips. What do the following expressions represent in this context? š+š The total number of trips both trucks make to the job site. The total number of cubic yards that the two trucks deliver in one trip. š„+š¦ Group 3 š„š+š š¦ The total number of cubic yards delivered to the job site. 2018 Algebra 1 Bootcamp
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Algebra and Modeling MAFS.912. A-SSE.1.1 Amy owns a graphic design store. She purchases a new printer to use in her store. The printer depreciates by a constant rate of 14% per year. The function V=2,400 (1ā0.14) š” can be used to model the value of the printer in dollars after š” years. Part A: Explain what the parameter 2,400 represents in the equation of the function. The parameter 2,400 represents the initial cost of the printer. Part B: What is the factor by which the printer depreciates each year? The factor is 0.86. Group 3 Part C: Amy also considered purchasing a printer that costs $4,000 and depreciates by 25% each year. Which printer will have more value in 5 years? The printer that cost $2,400 will have a better value by $179.80 2018 Algebra 1 Bootcamp
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MAFS.912. A.SSE.1.2 Which equation is equivalent to (š 2 ā25)?
Algebra and Modeling MAFS.912. A.SSE.1.2 Which equation is equivalent to (š 2 ā25)? ( š 2 ā10š+25) ( š 2 +10š+25) šā5 š+5 (šā5) 2 Group 1 and 2 š¶ 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A.SSE.1.2 Select the expression that is equivalent to š 2 ā144. šā12 2 šā72 2 šā8 š+18 šā12 š+12 Groups 1, 2, and 3 š· 2018 Algebra 1 Bootcamp
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MAFS.912. A.SSE.1.2 Which equation is equivalent to š¦ = 3 š„ 2 +6š„ + 5?
Algebra and Modeling MAFS.912. A.SSE.1.2 Which equation is equivalent to š¦ = 3 š„ 2 +6š„ + 5? š¦ = 3 (š„+3) 2 ā 9 š¦ = 3 (š„+3) 2 ā 4 š¦ = 3 (š„+1) 2 + 4 š¦ = 3 (š„+1) 2 + 2 Groups 2 and 3 š· 2018 Algebra 1 Bootcamp
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MAFS.912. A.SSE.1.2 Which equation is equivalent to 121 š„ 2 ā64 š¦ 2 ?
Algebra and Modeling MAFS.912. A.SSE.1.2 Which equation is equivalent to 121 š„ 2 ā64 š¦ 2 ? (11š„ā16š¦)(11š„+16š¦) (11š„ā16š¦)(11š„ā16š¦) 11š„+8š¦ 11š„+8š¦ (11š„+8š¦)(11š„ā8š¦) Groups 2 and 3 š· 2018 Algebra 1 Bootcamp
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Algebra and Modeling NEW MAFS.912. A.SSE.1.2 Select all expressions that are equivalent to 3 š„ 5 ā6 š„ 4 +3 š„ 3 . 3 š„ 3 š„ā1 2 3 š„ 3 š„ 2 ā2š„+1 3 š„ 3 š„+1 2 3 š„ 3 š„ā1 (š„+1) 3 š„ 3 š„ā1 š„ā1 Group 3 A, B, and E 2018 Algebra 1 Bootcamp
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