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Chapter 10 Hypothesis Testing On The Comparisons of Two Population Means
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Chapter Outline Inferences About the Difference Between Two Population Means: s 1 and s 2 Known
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Interval Estimation of m 1 – m 2
Inferences About the Difference Between Two Population Means: s 1 and s 2 Known Interval Estimation of m 1 – m 2 Hypothesis Tests About m 1 – m 2
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Estimating the Difference Between Two Population Means
So far, we have studied the estimation of ONE population mean based on the distribution of a sample drawn from the population. Similarly, when we want to estimate the difference between two population means, we can pick a sample from each population and analyze the sampling distribution of the difference between the two sample means. More specifically, to estimate 1 - 2, we will select a simple random sample of size n1 from population 1 and a simple random sample of size n2 from population 2. The point estimator of the difference between the means of the populations 1 and 2 is simply
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Sampling Distribution of
Expected Value Standard Deviation (Standard Error) where: 1 = standard deviation of population 1 2 = standard deviation of population 2 n1 = sample size from population 1 n2 = sample size from population 2
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Interval Estimation of 1 - 2: s 1 and s 2 Known
Interval Estimate where: 1 - is the confidence coefficient
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Interval Estimation of 1 - 2: s 1 and s 2 Known
Example: Textbook Spending To compare the amount of money students spent on textbooks in the Fall semester between two universities, independent random samples were chosen and revealed the following sample information: University A University B Sample Size Sample Mean $ $250 We assume that the population standard deviations of students’ spending on textbooks are known, i.e. s A=$20 and s B=$23 .
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Interval Estimation of 1 - 2: s 1 and s 2 Known
Example: Textbook Spending Let us develop a 95% confidence interval estimate of the difference in the average spending on textbooks between the two universities. Point estimate of 1 - 2 = = = $10 where: 1 = average spending on textbooks of students in University A 2 = average spending on textbooks of students in University B
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Interval Estimation of 1 - 2: s 1 and s 2 Known
Example: Textbook Spending or $0.97 to $19.03 We are 95% confident that the difference in the average spending on textbooks by students between the two universities is from $0.97 to $19.03.
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Hypothesis Tests About 1 - 2: s 1 and s 2 Known
Hypotheses Left-tailed Right-tailed Two-tailed Test Statistic
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Hypothesis Tests About 1 - 2: s 1 and s 2 Known
Example: Textbook Spending Can we conclude, using = .05, that, on the average, students at University A spent the same amount on textbooks as the students at University B?
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Hypothesis Tests About 1 - 2: s 1 and s 2 Known
p-Value and Critical Value Approaches 1. Develop the hypotheses. H0: 1 - 2 = 0 Ha: 1 - 2 0 where: 1 = average spending on textbooks by students in university A 2 = average spending on textbooks by students in university B 2. Specify the level of significance. a = .05
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Hypothesis Tests About 1 - 2: s 1 and s 2 Known
p-Value and Critical Value Approaches 3. Compute the value of the test statistic:
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Hypothesis Tests About 1 - 2: s 1 and s 2 Known
p-Value Approach 4. Compute the p-value: For z=2.17, the area to the left of 2.17 is = So, the p-value is 2(0.015)=0.03 for the two-tailed test. Determine whether to reject H0: Because p-value < a = .05, we reject H0. At the .05 level of significance, the sample data indicate that the average spending on textbooks by students in university A is NOT the same at that in university B.
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Hypothesis Tests About 1 - 2: s 1 and s 2 Known
Critical Value Approach 4. Determine the critical value and rejection rule: For = .05, z0.05/2= z0.025 = 1.96. Reject H0 if z > 1.96 or z < -1.96 5. Determine whether to reject H0: Because the test statistic z = 2.17 > 1.96, we reject H0. Again, at the .05 level of significance, the sample data indicate that the average spending on textbooks by students in university A is NOT the same at that in university B.
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