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Vectors - Finding Vector Components Contents:

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1 Vectors - Finding Vector Components Contents:
Definition of vector components Whiteboards: Writing the notation How to find components Whiteboard Am to VC

2 Vectors - What components are
Y - Component X - Component

3 Vectors - What components are
Suppose A = 5 cm Ay = 3 cm Ax = 4 cm A = 4 cm x + 3 cm y (This is how you write it) ^

4 Whiteboards: Writing the notation 1 | 2 | 3

5 3.2 m 4.5 m 4.5 m x m y

6 3.9 m 1.2 m -1.2 m x m y

7 4.1 m 1.9 m -1.9 m x m y

8 Vectors - Finding Components - step by step
Step 1: Find the Trig angle – ACW from x axis 0o Or 360o 90o 180o 270o 27o This is the trig angle 15o 51o 17o T = 360 – 17 = 343o OR T = -17o T = 270 – 15 = 255o T = = 321o

9 Whiteboards: Getting the trig angle 1 | 2 | 3 | 4 | 5 | 6

10 What’s the Trigonometric angle?

11 What’s the Trigonometric angle?

12 What’s the Trigonometric angle?

13 What’s the Trigonometric angle?

14 What’s the Trigonometric angle?

15 What’s the Trigonometric angle?

16 Vectors - Try this yourself
Get out your calculator type: sin 90 <ENTER> 1???? If not <2nd?> MODE Cursor arrows to “Degree” <ENTER> <CLEAR> Try again (sin 90)

17 Vectors - Finding Components - step by step
 = 180o – 27o = 153o 12 m 27o x = (12 m)Cos(153o) = m y = (12 m)Sin(153o) = m Step 2: Figure the sides using Cos and Sin: x = mag Cos() y = mag Sin() (iff  = trig angle)

18 Vectors - Finding Components - step by step
Step 3: Write it in Vector Component notation: Vector = -11 m x m y (With sig figs) Reality Check: (+ and -), relative size

19 Vectors - Try this yourself
23.0 m/s Draw the Components Figure the components with sin and cos Write the answer in VC Notation  = = 121o 23cos(121) x + 23sin(121) y x y -11.8 m/s x m/s y

20 Whiteboards: AM to VC 1 | 2 | 3 | 4 | 5

21 27.0 km 32.2o  = 32.2o 27.0cos(32.2) x sin(32.2) y 22.8 km x km y 22.8 km x km y

22 27o 42 m  = 360 – 27 = 333o 42cos(333) x + 42sin(333) y
37 m x m y 37 m x m y

23 77o 5.0 feet  = 90 + 77 = 167o 5cos(167) x + 5sin(167) y
-4.9 ft x ft y -4.9 ft x ft y

24 38o 110.0 N  = 270 + 38 = 308o 110.0cos(308) x + 110.0sin(308) y
N x N y 68 N x N y

25 30.0o 5.0 m/s  = 180 + 30.0 = 210.0o 5.0cos(210.0) x + 5.0sin(210) y
-4.3 m/s x m/s y -4.3 m/s x m/s y


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