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Chemistry 104B Dr. Christine Yerkes 207 Chem Annex

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Presentation on theme: "Chemistry 104B Dr. Christine Yerkes 207 Chem Annex"— Presentation transcript:

1 Chemistry 104B Dr. Christine Yerkes 207 Chem Annex 333-6353
Mon. and Wed. 11: :00 Tues. and Thurs.1:00 - 2:00 or by appointment

2 Required Text: Chemistry, 8th ed., Zumdahl Recommended I >clicker Quiz sections began: Tuesday, Jan. 17

3 Grading Policy: On-line Homework: 76 pts. Quiz score: 150 pts.
Discussion Quizzes 24 pts. Hour Exams (3 x 150) 450 pts. Final Exam pts. 1000 pts. No make-up quizzes or exams

4 Grades 1000 points total 97-100% (970 - 1000) = A+
% ( ) = B+ % ( ) = B % ( ) = B- etc., etc., etc.

5 150 points Quiz scores: weekly quizzes - material from Lecture and
Quiz section Quizzes on LON-CAPA open Wednesday at 5:00 open for 1 week Three tries – 1st worth 15 2nd worth 13.5 3rd worth 12 keep 10 highest 150 points

6 On-line Homework: 13(?) Homework assignments on LON-CAPA
due dates in the on-line Syllabus and calendar credit for all problems completed by deadline normalized to 76 points

7 150 points Quiz scores: weekly quizzes - material from Lecture and
Quiz section each quiz worth 15 points - keep 10 highest On-line LON-CAPA attempt % attempt % attempt % 150 points

8 Discussion Sections Worksheets in groups Discussion Quiz old hour exam problem 5 minutes 3 pts for correct 2 pts for partial 1 pt for attendance Keep 12 highest 24 pts max 12 bonus points

9 Course Homepage Course Web Sites Chem 104A Lon-Capa = net i.d.
www. chem.uiuc.edu Course Web Sites Chem 104A Lon-Capa = net i.d. Password = AD password homepage

10 Go = wmax 3 CuCl2 (aq) + Al (s) 2 AlCl3 (aq) 2 + Cu (s) 3 3 Cu Cl- + 2 Al 2 Al Cl- + 3 Cu 65.0 kJ 0 kJ -481 kJ 0 kJ Go = (3 x 0) + (2 x -481) - (2 x 0) - (3 x 65) Go = kJ w = - Pext V w = - n F Electrochemical work

11 3 CuCl2 (aq) + 2 Al (s) 2 AlCl3 (aq) + 3 Cu (s) Al (s) = Al0 AlCl3 aluminum chloride Al0 has _____ electrons 13 Al3+has ______ electrons 10 oxidation state = oxidation state = 3+ Al0 loses___ e- 3 increase oxidation number losing e- = oxidation 3+ LEO GER Lose Electrons Oxidation Gain Electrons Reduction Cu2+ Cu (s) 2+

12 Rules for oxidation numbers
1. Oxidation number for elements is zero. N2, O2, Na(s), Co(s), He (g) Oxidation number of monatomic ions is the same as their charge Group IA = +1 Al3+, Zn2+, Cd2+, Ag+ Group IIA = +2 Oxidation number of oxygen in most compounds is –2. Exceptions: H2O2, O22- (peroxides) –1 4. Oxidation number of hydrogen is +1 Exceptions: bonded to metals LiH -1 5. Fluorine is always –1. Other halogens are –1. Exceptions: bonded to O or F, they are positive

13 Assign oxidation numbers to all of the elements:
Li2O Li = O = PF3 P = F = HNO3 H = N = O = MnO4- Mn = O = Cr2O72- Cr = O =

14 What is the oxidation state of the highlighted element?
P2O5 NaH SnBr4 BaO2

15 Redox reactions Zn (s) + 2H+ (aq) H2 (g) + Zn 2+ Zn oxidation state H oxidation state

16 2H2(g) + O2 (g) 2H2O(l) H loses or gains electrons is oxidized or reduced oxidizing or reducing agent O loses or gains electrons is oxidized or reduced oxidizing or reducing agent

17 What is the oxidation state of S in each of these
compounds: H2S S = H = S8 S = SCl2 S = Cl = Na2SO3 S = O = Na = SO42- S = O = Which of these compounds can not act as a reducing agent? Which of these compounds can not act as a oxidizing agent?

18 2H2O + Al(s) + MnO4- Al(OH)4- + MnO2 H2O What is being oxidized? Al What is oxidation? MnO4- LEO Al(OH)4- MnO2 How many e-? What is being reduced? GER What is the reducing agent?

19 Cd(s) + NiO2 + 2H2O Cd(OH)2 + Ni(OH)2 What is being oxidized? What is being reduced? What is the oxidizing agent? What is the reducing agent? How many electrons are transferred?


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