1. Vectors
Day 9
Lyzinski Physics

2. 45)
46)

3. 47)

4. #47….continued

5. 48)

6. 49)

7. 50)

8. Day #9

9. Plane Problems

10. Important things to know:
P: Plane W: Wind G: Ground
vPG = vPW + vWG
“airspeed” means VPW
You can use d = rt in these problems only because a = 0

11. vPG = vPW vWG
Example: A plane is flying with an airspeed of 400 mph in the northeast direction. Wind is blowing towards the North at 50 mph. Find the velocity of the plane relative to the ground.
45o
400 =
282.84 50 =
436.8
49.6o
VPG = mph [E 49.6o N]

12. A difficult plane problem
From tonight’s HW 
vPG = vPW vWG
vWG = vPG vPW
rearranging
200 mph
10o
mph
230 mph
39.94 mph
??? x: y:
Vx = = mph
Putting together the super triangle yields
VWG = 47.9 mph [W 33.6o N]
Vy = – 200 = mph

13. Tonight’s HW Review for Test
2 night HW Assignment!
Review for Test
Days #9 & #10 Review For Test (from the packet)
The Ultimate River Problem and the Ultimate Plane Problem (from the packet)