1. Hardy - Weinberg
Questions

2. Hardy-Weinberg
In a population of 600 members, the numbers of different individuals of 3 different genotypes are
AA=350
Aa=100
aa=150
What are the genotypic frequencies in this population?
AA + Aa + aa = = 600 individuals So …..
AA/Total = 350 / 600 = .58 (58%) AA = 0.58
Aa/Total = 100 / 600 = .17 (17%) Aa = 0.17
aa/ Total = 150 / 600 = .25 (25%) aa = 0.25

3. Hardy-Weinberg

4. Hardy-Weinberg
In a population of 600 members, the numbers of different individuals of 3 different genotypes are
AA=350
Aa=100
aa=150
What would be the expected genotypic frequencies?
Since p = 0.5 and q = 0.5
Then p2 = (0.5)2 = What this means is
2pq = 2 x (0.5) x (0.5) = .5 p2 + 2pq + q2 = 1
And q2 = (0.5)2 = = 1

5. Hardy-Weinberg
In a population of 600 members, the numbers of different individuals of 3 different genotypes are
AA=350
Aa=100
aa=150
Is this population in genetic equilibrium?
Frequencies in the Population Expected Frequencies in
Hardy-Weinberg equilibrium
No AA Aa aa