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12. Navier-Stokes Applications

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1 12. Navier-Stokes Applications
CH EN 374: Fluid Mechanics

2 Problem Consider a steady, two-dimensional, incompressible velocity field: 𝑣 = π‘Žπ‘₯+𝑏 𝑖 + βˆ’π‘Žπ‘¦+𝑐π‘₯ 𝑗 Calculate the pressure as a function of x and y.

3 Problem Consider a steady, two-dimensional, incompressible velocity field: 𝑣 = π‘Žπ‘₯+𝑏 𝑖 + βˆ’π‘Žπ‘¦+𝑐π‘₯ 𝑗 Calculate the pressure as a function of x and y. 𝜌 πœ• 𝑣 π‘₯ πœ•π‘‘ + 𝑣 π‘₯ πœ• 𝑣 π‘₯ πœ•π‘₯ + 𝑣 𝑦 πœ• 𝑣 π‘₯ πœ•π‘¦ + 𝑣 𝑧 πœ• 𝑣 π‘₯ πœ•π‘§ =βˆ’ πœ•π‘ƒ πœ•π‘₯ +𝜌 𝑔 π‘₯ +πœ‡ πœ• 2 𝑣 π‘₯ πœ• π‘₯ πœ• 2 𝑣 π‘₯ πœ• 𝑦 πœ• 2 𝑣 π‘₯ πœ• 𝑧 2 𝜌 πœ• 𝑣 𝑦 πœ•π‘‘ + 𝑣 π‘₯ πœ• 𝑣 𝑦 πœ•π‘₯ + 𝑣 𝑦 πœ• 𝑣 𝑦 πœ•π‘¦ + 𝑣 𝑧 πœ• 𝑣 𝑦 πœ•π‘§ =βˆ’ πœ•π‘ƒ πœ•π‘¦ +𝜌 𝑔 𝑦 +πœ‡ πœ• 2 𝑣 𝑦 πœ• π‘₯ πœ• 2 𝑣 𝑦 πœ• 𝑦 πœ• 2 𝑣 𝑦 πœ• 𝑧 2

4 Laminar Pipe Flow I’ve shown you pictures of the velocity profile of laminar pipe flow. Now let’s find the profile ourselves.

5 1 π‘Ÿ πœ•(π‘Ÿ 𝑣 π‘Ÿ ) πœ•π‘Ÿ + 1 π‘Ÿ πœ• 𝑣 πœƒ πœ•π‘Ÿ + πœ• 𝑣 𝑧 πœ•π‘§ =0
Continuity Incompressible continuity equation (incompressible): 1 π‘Ÿ πœ•(π‘Ÿ 𝑣 π‘Ÿ ) πœ•π‘Ÿ + 1 π‘Ÿ πœ• 𝑣 πœƒ πœ•π‘Ÿ + πœ• 𝑣 𝑧 πœ•π‘§ =0 For laminar flow, we know all flow is in the z direction 𝑣 π‘Ÿ =0 𝑣 πœƒ =0 So what does the continuity equation tell us about πœ• 𝑣 𝑧 πœ•π‘§ ?

6 Simplifying NS We did this Friday:
𝜌 πœ• 𝑣 𝑧 πœ•π‘‘ + 𝑣 π‘Ÿ πœ• 𝑣 𝑧 πœ•π‘Ÿ + 𝑣 πœƒ π‘Ÿ πœ• 𝑣 𝑧 πœ•πœƒ + 𝑣 𝑧 πœ• 𝑣 𝑧 πœ•π‘§ =βˆ’ πœ•π‘ƒ πœ•π‘§ +𝜌 𝑔 𝑧 +πœ‡ 1 π‘Ÿ πœ• πœ•π‘Ÿ (π‘Ÿ πœ• 𝑣 𝑧 πœ•π‘Ÿ )+ 1 π‘Ÿ 2 πœ• 2 𝑣 𝑧 πœ•πœƒ 2 + πœ• 𝑣 𝑧 2 πœ• 𝑧 2 PS: What about pressure and gravity in the other directions?

7 Boundary Conditions At what π‘Ÿ values do we know what 𝑣 𝑧 is?
What else do we know?

8 Solve

9

10 What’s the velocity profile good for?
Shear stress

11 What’s the velocity profile good for?
Average velocity 𝑣 π‘Žπ‘£π‘” = 𝑉 𝐴 = 1 𝐴 𝐴 𝑣𝑑𝐴


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