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Atom Drawing Worksheet Answer Key Daniel R. Barnes Init:10/2/09 PT
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SWBAT . . . . . . draw an atom when given a chemical symbol with a mass number and an electric charge. “SWBAT = “Students will be able to”
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H He Li Be B C N O F Ne Mg S Ar
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 3 Li 3 Li 6.94 3 7S -3 4 SHOW ME THE END PRODUCT! NOW! Li+ Li PT
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neutral, so # = # 3 Li 3 Li 6.94 3 7S -3 4 Li+ Li PT
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SHOW ME THE END PRODUCT! NOW!
1 missing , so 3 – 1 = 2 Li + 3 Li 6.94 3 7S -3 4 SHOW ME THE END PRODUCT! NOW! Li+ Li PT
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1 missing , so 3 – 1 = 2 Li + 3 Li 6.94 3 7S -3 4 Li+ Li PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 6 C 6 C 12.01 6 12S - 6 6 oh noes! SHOW ME THE END PRODUCT! NOW! 14C C PT
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neutral, so # = # 6 C 6 C 12.01 6 12S - 6 6 14C C PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 6 14 C 6 C 12.01 6 14S - 6 8 SHOW ME THE END PRODUCT! NOW! 14C C PT
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neutral, so # = # 6 14 C 6 C 12.01 6 14S - 6 8 14C C PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 8 O 8 O 16.00 8 16S - 8 8 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT
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neutral, so # = # 8 O 8 O 16.00 8 16S - 8 8 18O2- 18O O2- O PT
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SHOW ME THE END PRODUCT! NOW!
2 extra , so = 10 O 2- 8 O 16.00 8 16S - 8 8 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT
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2 extra , so = 10 O 2- 8 O 16.00 8 16S - 8 8 18O2- 18O O2- O PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 8 18 O 8 O 16.00 8 18S - 8 10 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT
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neutral, so # = # 8 18 O 8 O 16.00 8 18S - 8 10 18O2- 18O O2- O PT
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SHOW ME THE END PRODUCT! NOW!
2 extra , so = 10 O 2- 18 8 O 16.00 8 18S - 8 10 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT
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O O 2 extra , so 8 + 2 = 10 2- 18 8 16.00 8 18S - 8 10 18O O2- O PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 2 He 2 He 4.00 2 4S -2 2 SHOW ME THE END PRODUCT! NOW! He2+ He PT
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neutral, so # = # 2 He 2 He 4.00 2 4S -2 2 He2+ He PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 1 H 1 H 1.01 1 1S -1 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT
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neutral, so # = # 1 H 1 H 1.01 1 1S -1 H3- 3H- H+ 3H 2H H PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 1 H 2 1 H 1.01 1 2S -1 1 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT
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neutral, so # = # 1 H 2 1 H 1.01 1 2S -1 1 H3- 3H- H+ 3H 2H H PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 1 H 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT
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neutral, so # = # 1 H 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H 2H H PT
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SHOW ME THE END PRODUCT! NOW!
2 missing , so 4 – 2 = 2 Be 2+ 4 Be 9.01 4 9S -4 5 SHOW ME THE END PRODUCT! NOW! Be2+ Be PT
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2 missing , so 4 – 2 = 2 Be 2+ 4 Be 9.01 4 9S -4 5 Be2+ Be PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 10 Ne 10 Ne 20.18 10 20S -10 10 SHOW ME THE END PRODUCT! NOW! Ne PT
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neutral, so # = # 10 Ne 10 Ne 20.18 10 20S -10 10 Ne PT
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SHOW ME THE END PRODUCT! NOW!
1 missing electron, so 1 – 1 = H + 1 H 1.01 1 1S -1 H3- 3H- H+ “H+” is just another way of saying “proton”, isn’t it? 3H SHOW ME THE END PRODUCT! NOW! 2H H PT
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H H 1 missing electron, so 1 – 1 = + 1 1.01 1 1S -1 H3- H+
H + 1 H 1.01 1 1S -1 H3- 3H- H+ “H+” is just another way of saying “proton”, isn’t it? 3H 2H H PT
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SHOW ME THE END PRODUCT! NOW!
1 extra , so = 2 H- 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT
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1 extra , so = 2 H- 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H 2H H PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 4 Be 4 Be 9.01 4 9S -4 5 SHOW ME THE END PRODUCT! NOW! Be2+ Be PT
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neutral, so # = # 4 Be 4 Be 9.01 4 9S -4 5 Be2+ Be PT
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SHOW ME THE END PRODUCT! NOW!
3 extra electrons, so 1 + 3 = 4 H 3- 1 H 1.01 1 1S -1 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT
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H H 3 extra electrons, so 1 + 3 = 4 3- 1 1.01 1 1S -1 H3- H+ 3H 2H H
H3- 3H- H+ 3H 2H H PT
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SHOW ME THE END PRODUCT! NOW!
2 missing electrons, so 2 - 2 = He 2+ 2 He 4.00 2 4S -2 2 He2+, which is basically just a naked helium nucleus, is also referred to as an “alpha particle” when it is shot out of a decaying, radioactive atom. SHOW ME THE END PRODUCT! NOW! He2+ He PT
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He He 2 missing electrons, so 2 - 2 = 2+ 2 2 4.00 4S -2 2
He 2+ 2 He 4.00 2 4S -2 2 He2+, which is basically just a naked helium nucleus, is also referred to as an “alpha particle” when it is shot out of a decaying, radioactive atom. He2+ He PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 5 B 5 B 10.81 5 11S -5 6 SHOW ME THE END PRODUCT! NOW! 6B3+ B PT
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neutral, so # = # 5 B 5 B 10.81 5 11S -5 6 6B3+ B PT
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SHOW ME THE END PRODUCT! NOW!
3 missing , so 5 – 3 = 2 B 3+ 6 5 B 10.81 5 6S -5 1 SHOW ME THE END PRODUCT! NOW! 6B3+ B PT
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3 missing , so 5 – 3 = 2 B 3+ 6 5 B 10.81 5 6S -5 1 6B3+ B PT
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SHOW ME THE END PRODUCT! NOW!
13 missing , so 7 – 13 = -6 N 13+ 7 N 14.01 7 14S -7 7 N3- SHOW ME THE END PRODUCT! NOW! N13+ N PT
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THIS ATOM IS NOT POSSIBLE!
13 missing , so 7 – 13 = -6 N 13+ 7 N 14.01 7 14S -7 7 N3- THIS ATOM IS NOT POSSIBLE! N13+ N PT
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SHOW ME THE END PRODUCT! NOW!
3 extra , so = 10 N 3- 7 N 14.01 7 14S - 7 7 N3- SHOW ME THE END PRODUCT! NOW! N13+ N PT
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3 extra , so = 10 N 3- 7 N 14.01 7 14S - 7 7 N3- N13+ N PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 9 F 9 F 19.00 9 19S - 9 10 SHOW ME THE END PRODUCT! NOW! F- F PT
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neutral, so # = # 9 F 9 F 19.00 9 19S - 9 10 F- F PT
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SHOW ME THE END PRODUCT! NOW!
1 extra , so = 10 F - 9 F 19.00 9 19S - 9 10 SHOW ME THE END PRODUCT! NOW! F- F PT
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1 extra , so = 10 F - 9 F 19.00 9 19S - 9 10 F- F PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 12 Mg 12 Mg 24.31 12 24S -12 12 SHOW ME THE END PRODUCT! NOW! Mg PT
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neutral, so # = # 12 Mg 12 Mg 24.31 12 24S -12 12 Mg PT
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SHOW ME THE END PRODUCT! NOW!
2 extra , so = 18 2- 30 S 16 S 32.07 16 30S -16 14 30S2- SHOW ME THE END PRODUCT! NOW! S2- S PT
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2 extra , so = 18 2- 30 S 16 S 32.07 16 30S -16 14 30S2- S2- S PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 18 Ar 18 Ar 39.95 18 40S -18 22 SHOW ME THE END PRODUCT! NOW! Ar PT
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neutral, so # = # 18 Ar 18 Ar 39.95 18 40S -18 22 Ar PT
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From here on, the slides do not correspond to the order of the atoms on the worksheet.
I’m working on it, okay?
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 16 S 16 S 32.07 16 32S -16 16 30S2- SHOW ME THE END PRODUCT! NOW! S2- S PT
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neutral, so # = # 16 S 16 S 32.07 16 32S -16 16 30S2- S2- S PT
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SHOW ME THE END PRODUCT! NOW!
2 extra , so = 18 2- S 16 S 32.07 16 32S -16 16 30S2- SHOW ME THE END PRODUCT! NOW! S2- S PT
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2 extra , so = 18 2- S 16 S 32.07 16 32S -16 16 30S2- S2- S PT
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SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 7 N 7 N 14.01 7 14S - 7 7 N3- SHOW ME THE END PRODUCT! NOW! N13+ N PT
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neutral, so # = # 7 N 7 N 14.01 7 14S - 7 7 N3- N13+ N PT
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SHOW ME THE END PRODUCT! NOW!
3 missing , so 5 – 3 = 2 B 3+ 5 B 10.81 5 11S -5 6 SHOW ME THE END PRODUCT! NOW!
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3 missing , so 5 – 3 = 2 B 3+ 5 B 10.81 5 11S -5 6
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H WARNING: - This one isn't from the worksheet! H 1 extra electron, so
1 + 1 = 2 WARNING: This one isn't from the worksheet! - H 1 H 1.01 1 1S -1
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C WARNING: This one isn't from the worksheet! C 3 extra , so 6 + 3 = 9
3- 13 C 6 C 12.01 6 13S - 6 7
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Sorry. I haven’t done N, N3-, or O yet. I need to finish grades for the 5 week progress report. I don’t care if we don’t know how to use PowerSchool yet. I’m still sticking to the deadline, gull durnit.
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Yeah, yeah, I know. I haven’t done any of the atoms after O2- either
Yeah, yeah, I know. I haven’t done any of the atoms after O2- either. So sue me. Go ahead! Steal an old lady’s Polident & Ensure money!
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