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Atom Drawing Worksheet Answer Key Daniel R. Barnes Init:10/2/09 PT.

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Presentation on theme: "Atom Drawing Worksheet Answer Key Daniel R. Barnes Init:10/2/09 PT."— Presentation transcript:

1 Atom Drawing Worksheet Answer Key Daniel R. Barnes Init:10/2/09 PT

2 SWBAT . . . . . . draw an atom when given a chemical symbol with a mass number and an electric charge. “SWBAT = “Students will be able to”

3 H He Li Be B C N O F Ne Mg S Ar

4 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 3 Li 3 Li 6.94 3 7S -3 4 SHOW ME THE END PRODUCT! NOW! Li+ Li PT

5 neutral, so # = # 3 Li 3 Li 6.94 3 7S -3 4 Li+ Li PT

6 SHOW ME THE END PRODUCT! NOW!
1 missing , so 3 – 1 = 2 Li + 3 Li 6.94 3 7S -3 4 SHOW ME THE END PRODUCT! NOW! Li+ Li PT

7 1 missing , so 3 – 1 = 2 Li + 3 Li 6.94 3 7S -3 4 Li+ Li PT

8 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 6 C 6 C 12.01 6 12S - 6 6 oh noes! SHOW ME THE END PRODUCT! NOW! 14C C PT

9 neutral, so # = # 6 C 6 C 12.01 6 12S - 6 6 14C C PT

10 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 6 14 C 6 C 12.01 6 14S - 6 8 SHOW ME THE END PRODUCT! NOW! 14C C PT

11 neutral, so # = # 6 14 C 6 C 12.01 6 14S - 6 8 14C C PT

12 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 8 O 8 O 16.00 8 16S - 8 8 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT

13 neutral, so # = # 8 O 8 O 16.00 8 16S - 8 8 18O2- 18O O2- O PT

14 SHOW ME THE END PRODUCT! NOW!
2 extra , so = 10 O 2- 8 O 16.00 8 16S - 8 8 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT

15 2 extra , so = 10 O 2- 8 O 16.00 8 16S - 8 8 18O2- 18O O2- O PT

16 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 8 18 O 8 O 16.00 8 18S - 8 10 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT

17 neutral, so # = # 8 18 O 8 O 16.00 8 18S - 8 10 18O2- 18O O2- O PT

18 SHOW ME THE END PRODUCT! NOW!
2 extra , so = 10 O 2- 18 8 O 16.00 8 18S - 8 10 18O2- 18O SHOW ME THE END PRODUCT! NOW! O2- O PT

19 O O 2 extra , so 8 + 2 = 10 2- 18 8 16.00 8 18S - 8 10 18O O2- O PT

20 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 2 He 2 He 4.00 2 4S -2 2 SHOW ME THE END PRODUCT! NOW! He2+ He PT

21 neutral, so # = # 2 He 2 He 4.00 2 4S -2 2 He2+ He PT

22 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 1 H 1 H 1.01 1 1S -1 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT

23 neutral, so # = # 1 H 1 H 1.01 1 1S -1 H3- 3H- H+ 3H 2H H PT

24 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 1 H 2 1 H 1.01 1 2S -1 1 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT

25 neutral, so # = # 1 H 2 1 H 1.01 1 2S -1 1 H3- 3H- H+ 3H 2H H PT

26 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 1 H 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT

27 neutral, so # = # 1 H 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H 2H H PT

28 SHOW ME THE END PRODUCT! NOW!
2 missing , so 4 – 2 = 2 Be 2+ 4 Be 9.01 4 9S -4 5 SHOW ME THE END PRODUCT! NOW! Be2+ Be PT

29 2 missing , so 4 – 2 = 2 Be 2+ 4 Be 9.01 4 9S -4 5 Be2+ Be PT

30 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 10 Ne 10 Ne 20.18 10 20S -10 10 SHOW ME THE END PRODUCT! NOW! Ne PT

31 neutral, so # = # 10 Ne 10 Ne 20.18 10 20S -10 10 Ne PT

32 SHOW ME THE END PRODUCT! NOW!
1 missing electron, so 1 – 1 = H + 1 H 1.01 1 1S -1 H3- 3H- H+ “H+” is just another way of saying “proton”, isn’t it? 3H SHOW ME THE END PRODUCT! NOW! 2H H PT

33 H H 1 missing electron, so 1 – 1 = + 1 1.01 1 1S -1 H3- H+
H + 1 H 1.01 1 1S -1 H3- 3H- H+ “H+” is just another way of saying “proton”, isn’t it? 3H 2H H PT

34 SHOW ME THE END PRODUCT! NOW!
1 extra , so = 2 H- 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT

35 1 extra , so = 2 H- 3 1 H 1.01 1 3S -1 2 H3- 3H- H+ 3H 2H H PT

36 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 4 Be 4 Be 9.01 4 9S -4 5 SHOW ME THE END PRODUCT! NOW! Be2+ Be PT

37 neutral, so # = # 4 Be 4 Be 9.01 4 9S -4 5 Be2+ Be PT

38 SHOW ME THE END PRODUCT! NOW!
3 extra electrons, so 1 + 3 = 4 H 3- 1 H 1.01 1 1S -1 H3- 3H- H+ 3H SHOW ME THE END PRODUCT! NOW! 2H H PT

39 H H 3 extra electrons, so 1 + 3 = 4 3- 1 1.01 1 1S -1 H3- H+ 3H 2H H
H3- 3H- H+ 3H 2H H PT

40 SHOW ME THE END PRODUCT! NOW!
2 missing electrons, so 2 - 2 = He 2+ 2 He 4.00 2 4S -2 2 He2+, which is basically just a naked helium nucleus, is also referred to as an “alpha particle” when it is shot out of a decaying, radioactive atom. SHOW ME THE END PRODUCT! NOW! He2+ He PT

41 He He 2 missing electrons, so 2 - 2 = 2+ 2 2 4.00 4S -2 2
He 2+ 2 He 4.00 2 4S -2 2 He2+, which is basically just a naked helium nucleus, is also referred to as an “alpha particle” when it is shot out of a decaying, radioactive atom. He2+ He PT

42 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 5 B 5 B 10.81 5 11S -5 6 SHOW ME THE END PRODUCT! NOW! 6B3+ B PT

43 neutral, so # = # 5 B 5 B 10.81 5 11S -5 6 6B3+ B PT

44 SHOW ME THE END PRODUCT! NOW!
3 missing , so 5 – 3 = 2 B 3+ 6 5 B 10.81 5 6S -5 1 SHOW ME THE END PRODUCT! NOW! 6B3+ B PT

45 3 missing , so 5 – 3 = 2 B 3+ 6 5 B 10.81 5 6S -5 1 6B3+ B PT

46 SHOW ME THE END PRODUCT! NOW!
13 missing , so 7 – 13 = -6 N 13+ 7 N 14.01 7 14S -7 7 N3- SHOW ME THE END PRODUCT! NOW! N13+ N PT

47 THIS ATOM IS NOT POSSIBLE!
13 missing , so 7 – 13 = -6 N 13+ 7 N 14.01 7 14S -7 7 N3- THIS ATOM IS NOT POSSIBLE! N13+ N PT

48 SHOW ME THE END PRODUCT! NOW!
3 extra , so = 10 N 3- 7 N 14.01 7 14S - 7 7 N3- SHOW ME THE END PRODUCT! NOW! N13+ N PT

49 3 extra , so = 10 N 3- 7 N 14.01 7 14S - 7 7 N3- N13+ N PT

50 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 9 F 9 F 19.00 9 19S - 9 10 SHOW ME THE END PRODUCT! NOW! F- F PT

51 neutral, so # = # 9 F 9 F 19.00 9 19S - 9 10 F- F PT

52 SHOW ME THE END PRODUCT! NOW!
1 extra , so = 10 F - 9 F 19.00 9 19S - 9 10 SHOW ME THE END PRODUCT! NOW! F- F PT

53 1 extra , so = 10 F - 9 F 19.00 9 19S - 9 10 F- F PT

54 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 12 Mg 12 Mg 24.31 12 24S -12 12 SHOW ME THE END PRODUCT! NOW! Mg PT

55 neutral, so # = # 12 Mg 12 Mg 24.31 12 24S -12 12 Mg PT

56 SHOW ME THE END PRODUCT! NOW!
2 extra , so = 18 2- 30 S 16 S 32.07 16 30S -16 14 30S2- SHOW ME THE END PRODUCT! NOW! S2- S PT

57 2 extra , so = 18 2- 30 S 16 S 32.07 16 30S -16 14 30S2- S2- S PT

58 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 18 Ar 18 Ar 39.95 18 40S -18 22 SHOW ME THE END PRODUCT! NOW! Ar PT

59 neutral, so # = # 18 Ar 18 Ar 39.95 18 40S -18 22 Ar PT

60 From here on, the slides do not correspond to the order of the atoms on the worksheet.
I’m working on it, okay?

61 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 16 S 16 S 32.07 16 32S -16 16 30S2- SHOW ME THE END PRODUCT! NOW! S2- S PT

62 neutral, so # = # 16 S 16 S 32.07 16 32S -16 16 30S2- S2- S PT

63 SHOW ME THE END PRODUCT! NOW!
2 extra , so = 18 2- S 16 S 32.07 16 32S -16 16 30S2- SHOW ME THE END PRODUCT! NOW! S2- S PT

64 2 extra , so = 18 2- S 16 S 32.07 16 32S -16 16 30S2- S2- S PT

65 SHOW ME THE END PRODUCT! NOW!
neutral, so # = # 7 N 7 N 14.01 7 14S - 7 7 N3- SHOW ME THE END PRODUCT! NOW! N13+ N PT

66 neutral, so # = # 7 N 7 N 14.01 7 14S - 7 7 N3- N13+ N PT

67 SHOW ME THE END PRODUCT! NOW!
3 missing , so 5 – 3 = 2 B 3+ 5 B 10.81 5 11S -5 6 SHOW ME THE END PRODUCT! NOW!

68 3 missing , so 5 – 3 = 2 B 3+ 5 B 10.81 5 11S -5 6

69 H WARNING: - This one isn't from the worksheet! H 1 extra electron, so
1 + 1 = 2 WARNING: This one isn't from the worksheet! - H 1 H 1.01 1 1S -1

70 C WARNING: This one isn't from the worksheet! C 3 extra , so 6 + 3 = 9
3- 13 C 6 C 12.01 6 13S - 6 7

71 Sorry. I haven’t done N, N3-, or O yet. I need to finish grades for the 5 week progress report. I don’t care if we don’t know how to use PowerSchool yet. I’m still sticking to the deadline, gull durnit.

72 Yeah, yeah, I know. I haven’t done any of the atoms after O2- either
Yeah, yeah, I know. I haven’t done any of the atoms after O2- either. So sue me. Go ahead! Steal an old lady’s Polident & Ensure money!

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