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Warm Up Determine the domain of the function.

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1 Warm Up Determine the domain of the function.
f(x) = 7π‘₯ βˆ’42 7x – 42 β‰₯ 0 x β‰₯ 6

2 Operations and Compositions of Functions

3 Operations with Functions Sum Difference Product Quotient
(f + g)(x) = f(x) + g(x) (f – g)(x) = f(x) – g(x) (f β€’ g)(x) = f(x) β€’ g(x) 𝑓(π‘₯) 𝑔(π‘₯) ( 𝑓 𝑔 )(x) =

4 f(x) + g(x) f(x) – g(x) Examples 1. f(x) = 2x + 1 g(x) = x – 2
Find each: a. (f + g)(x) b. (f – g)(x) f(x) + g(x) (2x + 1) + (x – 2) 3x – 1 f(x) – g(x) (2x + 1) – (x – 2) 2x + 1 – x + 2 x + 3

5 f(x) ● g(x) (2x + 1) ● (x – 2) 2 π‘₯ 2 – 4x + x – 2 2 π‘₯ 2 – 3x – 2
c. (f β€’ g)(x) d. ( 𝑓 𝑔 )(x) f(x) ● g(x) (2x + 1) ● (x – 2) 2 π‘₯ 2 – 4x + x – 2 2 π‘₯ 2 – 3x – 2 𝑓(π‘₯) 𝑔(π‘₯) 2π‘₯+1 π‘₯βˆ’2 ; x β‰  2

6 Examples 2. f(x) = 2x + 1 g(x) = x – 2 Find each: a. (f + g)(6)
f(x) + g(x) = 3x – 1 13 + 4 3(6) – 1 17 17

7 b. (f – g)(6) f(x) – g(x) = x + 3 f(6) – g(6) 6 + 3 13 – 4 9 9

8 f(x) β€’ g(x) = 2 π‘₯ 2 – 3x – 2 f(6) β€’ g(6) 2 (6) 2 – 3(6) – 2
c. (f β€’ g)(6) f(x) β€’ g(x) = 2 π‘₯ 2 – 3x – 2 f(6) β€’ g(6) 2 (6) 2 – 3(6) – 2 2(36) – 18 – 2 13 β€’ 4 72 – 18 – 2 52 52

9 𝑓(π‘₯) 𝑔(π‘₯) 2π‘₯+1 π‘₯βˆ’2 = 𝑓(6) 𝑔(6) = 2(6)+1 6βˆ’2 13 4 ; x β‰  2 = 12+1 6βˆ’2
d. 𝑓 𝑔 (6) 2π‘₯+1 π‘₯βˆ’2 = 𝑓(6) 𝑔(6) = 2(6)+1 6βˆ’2 13 4 ; x β‰  2 = βˆ’2 = 13 4 ; x β‰  2

10 Examples 3. f(x) = x + 3 Find each: a. (f + g)(x)
f(x) + g(x) (x + 3) + (2π‘₯) (π‘₯ βˆ’ 5) (π‘₯+3) (2π‘₯) (π‘₯ βˆ’ 5) ● (π‘₯ βˆ’ 5) (π‘₯ βˆ’ 5) 1 π‘₯ 2 βˆ’15 π‘₯ βˆ’5 π‘₯ 2 βˆ’ 5π‘₯ + 3π‘₯ βˆ’15 π‘₯ βˆ’5 + (2π‘₯) (π‘₯ βˆ’ 5) ; x β‰  5

11 (π‘₯+3) – (2π‘₯) (π‘₯ βˆ’ 5) f(x) – g(x) (x + 3) – (2π‘₯) (π‘₯ βˆ’ 5)
b. (f – g)(x) f(x) – g(x) (x + 3) – (2π‘₯) (π‘₯ βˆ’ 5) (π‘₯+3) – (2π‘₯) (π‘₯ βˆ’ 5) ● (π‘₯ βˆ’ 5) (π‘₯ βˆ’ 5) 1 π‘₯ 2 βˆ’ 5π‘₯ + 3π‘₯ βˆ’15 π‘₯ βˆ’5 – (2π‘₯) (π‘₯ βˆ’ 5) π‘₯ 2 βˆ’ 5π‘₯ + 3π‘₯ βˆ’15 βˆ’2π‘₯ π‘₯ βˆ’5 π‘₯ 2 βˆ’4π‘₯ βˆ’15 π‘₯ βˆ’5 ; x β‰  5

12 f(x) ● g(x) f(x) = x + 3 (π‘₯+ 3) 1 ● (2π‘₯) (π‘₯ βˆ’ 5) g(x) = πŸπ’™ 𝒙 βˆ’ πŸ“
(π‘₯+ 3) 1 ● (2π‘₯) (π‘₯ βˆ’ 5) g(x) = πŸπ’™ 𝒙 βˆ’ πŸ“ 2 π‘₯ 2 +6π‘₯ π‘₯ βˆ’5 c. (f β€’ g)(x) d. ( 𝑓 𝑔 )(x) ; x β‰  5 (π‘₯ + 3) 1 Γ· (2π‘₯) (π‘₯ βˆ’5) (π‘₯+3) (2π‘₯) (π‘₯ βˆ’5) (π‘₯ + 3) 1 ● (π‘₯ βˆ’ 5) (2π‘₯) π‘₯ 2 βˆ’2π‘₯ βˆ’15 2π‘₯ π‘₯ 2 βˆ’5π‘₯ +3π‘₯ βˆ’15 2π‘₯ ; x β‰  0, 5

13 Homework: Function Operation WS #1 – 7, 9 – 15, 17, 20

14 Warm Up Given the graph, state the domain and range and determine whether or not it represents a function: π‘«π’π’Žπ’‚π’Šπ’:βˆ’πŸβ‰€π’™β‰€πŸ“ π‘Ήπ’‚π’π’ˆπ’†:βˆ’πŸ‘β‰€π’šβ‰€πŸ‘ Not a function

15 (f ΠΎ g)(x) = f(g(x)) (g ΠΎ f)(x) = g(f(x)) Composition of Functions
- the process of combining two functions where one function is performed first and the result of which is substituted in place of eachΒ xΒ in the other function. read as β€œf of g of x” read as β€œg of f of x” (f ΠΎ g)(x) = f(g(x)) (g ΠΎ f)(x) = g(f(x))

16 Examples 3. f(x) = 2x + 1 g(x) = x – 2 Find each: a. (f ΠΎ g)(x)

17 = g(f(x)) = g(2x + 1) = (2x + 1) – 2 = 2x – 1
3. f(x) = 2x + 1 g(x) = x – 2 b. (g ΠΎ f)(x) = g(f(x)) = g(2x + 1) = (2x + 1) – 2 = 2x – 1

18 Examples 3. f(x) = x2 + 4 g(x) = x – 4 a. (f (g(x))
= x2 – 4x – 4x = x2 – 8x + 20

19 = g(f(x)) = g(x2 + 4) = (x2 + 4) – 4 = x2 b. (g(f(x)) 3. f(x) = x2 + 4

20 Homework: Function Operation WS #8, 16, 18, 19, 21, 22


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