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Distributed Forces: Centroids and Centers of Gravity

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Presentation on theme: "Distributed Forces: Centroids and Centers of Gravity"— Presentation transcript:

1 Distributed Forces: Centroids and Centers of Gravity

2 Contents Introduction Center of Gravity of a 2D Body
Centroids and First Moments of Areas and Lines Sample Problem 5.4 Centroids of Common Shapes of Areas Centroids of Common Shapes of Lines Composite Plates and Areas Sample Problem 5.1 Determination of Centroids by Integration Distributed Loads on Beams Sample Problem 5.9 Three-Dimensional Centers of Gravity and Centroids Centroids of Common 3D Shapes Composite Bodies Sample Problem 5.12

3 Application There are many examples in engineering analysis of distributed loads. It is convenient in some cases to represent such loads as a concentrated force located at the centroid of the distributed load.

4 Introduction The earth exerts a gravitational force on each of the particles forming a body – consider how your weight is distributed throughout your body. These forces can be replaced by a single equivalent force equal to the weight of the body and applied at the center of gravity for the body. The centroid of an area is analogous to the center of gravity of a body; it is the “center of area.” The concept of the first moment of an area is used to locate the centroid. Determination of the area of a surface of revolution and the volume of a body of revolution are accomplished with the Theorems of Pappus-Guldinus.

5 Center of Gravity of a 2D Body
Center of gravity of a plate Center of gravity of a wire

6 Centroids and First Moments of Areas and Lines
Centroid of an area Centroid of a line

7 Determination of Centroids by Integration
Double integration to find the first moment may be avoided by defining dA as a thin rectangle or strip.

8 Sample Problem 5.4 STRATEGY: Determine the constant k.
Evaluate the total area. Using either vertical or horizontal strips, perform a single integration to find the first moments. Determine by direct integration the location of the centroid of a parabolic spandrel. Evaluate the centroid coordinates. First, estimate the location of the centroid by inspection. Discuss with a neighbor where it is located, roughly, and justify your answer.

9 Sample Problem 5.4 MODELING: Determine the constant k.
ANALYSIS: Evaluate the total area.

10 Sample Problem 5.4 Using vertical strips, perform a single integration to find the first moments.

11 Sample Problem 5.4 Or, using horizontal strips, perform a single integration to find the first moments. Try calculating Qy or Qx by this method, and confirm that you get the same value as before.

12 Sample Problem 5.4 Evaluate the centroid coordinates.
Is this “center of area” close to where you estimated it would be? REFLECT and THINK: You obtain the same results whether you choose a vertical or a horizontal element of area, as you should. You can use both methods as a check against making a mistake in your calculations.

13 Determination of Centroids by Integration
Usually, the choice between using a vertical or horizontal strip is equally good, but in some cases, one choice is much better than the other. For example, for the area shown below, is a vertical or horizontal strip a better choice, and why? Think about this and discuss your choice with a neighbor. y x

14 First Moments of Areas and Lines
An area is symmetric with respect to an axis BB’ if for every point P there exists a point P’ such that PP’ is perpendicular to BB’ and is divided into two equal parts by BB’. The first moment of an area with respect to a line of symmetry is zero. If an area possesses two lines of symmetry, its centroid lies at their intersection. If an area possesses a line of symmetry, its centroid lies on that axis An area is symmetric with respect to a center O if for every element dA at (x,y) there exists an area dA’ of equal area at (-x,-y). The centroid of the area coincides with the center of symmetry.

15 Centroids of Common Shapes of Areas

16 Centroids of Common Shapes of Lines

17 Composite Plates and Areas
Composite area

18 Sample Problem 5.1 STRATEGY:
Divide the area into a triangle, rectangle, and semicircle with a circular cutout. Calculate the first moments of each area with respect to the axes. Find the total area and first moments of the triangle, rectangle, and semicircle. Subtract the area and first moment of the circular cutout. For the plane area shown, determine the first moments with respect to the x and y axes and the location of the centroid. Compute the coordinates of the area centroid by dividing the first moments by the total area.

19 Sample Problem 5.1 MODELING:
Find the total area and first moments of the triangle, rectangle, and semicircle. Subtract the area and first moment of the circular cutout.

20 Sample Problem 5.1 ANALYSIS:
Compute the coordinates of the area centroid by dividing the first moments by the total area. REFLECT and THINK: Given that the lower portion of the shape has more area to the left and that the upper portion has a hole, the location of the centroid seems reasonable upon visual inspection.

21 Distributed Loads on Beams
A distributed load is represented by plotting the load per unit length, w (N/m) . The total load is equal to the area under the load curve. A distributed load can be replace by a concentrated load with a magnitude equal to the area under the load curve and a line of action passing through the area centroid.

22 Sample Problem 5.9 STRATEGY:
The magnitude of the concentrated load is equal to the total load or the area under the curve. The line of action of the concentrated load passes through the centroid of the area under the curve. Determine the support reactions by (a) drawing the free body diagram for the beam and (b) applying the conditions of equilibrium. A beam supports a distributed load as shown. Determine the equivalent concentrated load and the reactions at the supports.

23 Sample Problem 5.9 MODELING and ANALYSIS:
The magnitude of the concentrated load is equal to the total load or the area under the curve. The line of action of the concentrated load passes through the centroid of the area under the curve.

24 Sample Problem 5.9 Determine the support reactions by applying the equilibrium conditions. For example, successively sum the moments at the two supports: And by summing forces in the x-direction: REFLECT and THINK: You can replace the given distributed load by its resultant, which you found in part a. Then you can determine the reactions from the equilibrium equations

25 Three-Dimensional Centers of Gravity and Centroids
Center of gravity G Results are independent of body orientation, For homogeneous bodies,

26 Centroids of Common 3D Shapes

27 Composite Bodies Moment of the total weight concentrated at the center of gravity G is equal to the sum of the moments of the weights of the component parts. For homogeneous bodies,

28 Sample Problem 5.12 STRATEGY:
Form the machine element from a rectangular parallelepiped and a quarter cylinder and then subtracting two 1-in. diameter cylinders. Locate the center of gravity of the steel machine element. The diameter of each hole is 1 in.

29 Sample Problem 5.12 MODELING:

30 Sample Problem 5.12 ANALYSIS:

31 Sample Problem 5.12 REFLECT and THINK:
By inspection, you should expect to be considerably less than (1/2)(2.5 in.) and (1/2)(4.5 in.), respectively, and to be slightly less in magnitude than (1/2)(2 in.). Thus, as a rough visual check, the results obtained are as expected.


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