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( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN

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Presentation on theme: "( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN"— Presentation transcript:

1 ( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN
REACTION STOICHIOMETRY FACTOR LABEL LOGIC 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) CALCULATE THE YIELD OF WATER IN GRAMS IF 32 GRAMS OF OXYGEN IS CONSUMED IN THE ABOVE BALANCED REACTION. KNOWN 32.O g O2 ( ) 32 g O2 1 mol O2 ( ) 14mol H2O 19 mol O2 ( ) 18 g H2O 1 mol H2O OBJECTIVE 13.23g H2O = CONVERT KNOWN TO MOLES FROM GRAMS, GRAMS CANCEL. MOLAR MASS OF O2 IS 32 G/MOL. GIVES MOLES OF KNOWN. MOLES = MASS MOLAR MASS MOLE RATIO: RATIO MOLES OF OBJECTIVE TO MOLES OF KNOWN., USE COEFFICIENTS OF BALANCED REACTION. THIS STEP GIVES MOLES OF OBJECTIVE. CONVERT MOLES OF OBJECTIVE TO GRAMS. THIS STEP GIVES GRAMS OF OBJECTIVE, WHICH THE QUESTION CALLED FOR

2 ( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN
REACTION STOICHIOMETRY FACTOR LABEL LOGIC 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) CALCULATE THE YIELD OF CO2 IN GRAMS IF 16. GRAMS OF OXYGEN IS CONSUMED IN THE ABOVE BALANCED REACTION. KNOWN 16.O g O2 ( ) 32 g O2 1 mol O2 ( ) 12mol CO2 19 mol O2 ( ) 44 gCO2 1 mol CO2 OBJECTIVE 13.89g CO2 =

3 ( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN
REACTION STOICHIOMETRY FACTOR LABEL LOGIC 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) CALCULATE THE YIELD OF C6H14 IN GRAMS IF 16. GRAMS OF OXYGEN IS CONSUMED IN THE ABOVE BALANCED REACTION. KNOWN 16.O g O2 ( ) 32 g O2 1 mol O2 ( ) 2mol C6H14 19 mol O2 ( ) 86 gC6H14 1 molC6H14 OBJECTIVE 4.53g C6H14 =

4 REACTION STOICHIOMETRY FACTOR LABEL LOGIC
2 KClO3(s)  3 O2(g) + 2 KCl(s) KNOWN 6 MOLES O2 ( ) 2 MOLES KClO3 3 MOLES O2 OBJECTIVE 4 MOL KClO3 =

5 ( ) ( ) = KNOWN 0.5 C2 H2 mol 5 mol O2 2 mol C2H2 32g O2 1 mol O2
( ) 5 mol O2 2 mol C2H2 ( ) 32g O2 1 mol O2 OBJECTIVE 40 g O2 = MOLE RATIO: RATIO MOLES OF OBJECTIVE TO MOLES OF KNOWN., USE COEFFICIENTS OF BALANCED REACTION. THIS STEP GIVES MOLES OF OBJECTIVE. CONVERT MOLES OF OBJECTIVE TO GRAMS. THIS STEP GIVES GRAMS OF OBJECTIVE, WHICH THE QUESTION CALLED FOR

6 ( ) ( ) ( ) = KNOWN 32.O g Cu 64 g Cu 1 mol Cu 2mol H2O 1 mol Cu
( ) 64 g Cu 1 mol Cu ( ) 2mol H2O 1 mol Cu ( ) 18 g H2O 1 mol H2O OBJECTIVE 18 g H2O = CONVERT KNOWN TO MOLES FROM GRAMS, GRAMS CANCEL. MOLAR MASS OF Cu IS 64 G/MOL. GIVES MOLES OF KNOWN. MOLES = MASS MOLAR MASS MOLE RATIO: RATIO MOLES OF OBJECTIVE TO MOLES OF KNOWN., USE COEFFICIENTS OF BALANCED REACTION. THIS STEP GIVES MOLES OF OBJECTIVE. CONVERT MOLES OF OBJECTIVE TO GRAMS. THIS STEP GIVES GRAMS OF OBJECTIVE, WHICH THE QUESTION CALLED FOR

7 ( ) ( ) ( ) = KNOWN 22 g C3H8 44 g C3H8 1mol C3H8 4 mol H2O 1 mol C3H8
( ) 44 g C3H8 1mol C3H8 ( ) 4 mol H2O 1 mol C3H8 ( ) 18 g H2O 1 mol H2O OBJECTIVE 36g H2O = CONVERT KNOWN TO MOLES FROM GRAMS, GRAMS CANCEL. MOLAR MASS IS 44 g/MOL. GIVES MOLES OF KNOWN. MOLES = MASS MOLAR MASS MOLE RATIO: RATIO MOLES OF OBJECTIVE TO MOLES OF KNOWN., USE COEFFICIENTS OF BALANCED REACTION. THIS STEP GIVES MOLES OF OBJECTIVE. CONVERT MOLES OF OBJECTIVE TO GRAMS. THIS STEP GIVES GRAMS OF OBJECTIVE, WHICH THE QUESTION CALLED FOR


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