1. differentiate double pulse

2. part 1

3. pulse start from zero

4. before find shoulder pulse

5. after find shoulder pulse

6. skip find shoulder pulse when pulse start from zero

7. part2

8. fail

9. peak and valley

11. Center TDC * 1 left -1 right condition set slope1 slope2 Set
left or right
Δ ADC12 <0.
Δ ADC23 >0. *
Δ ADC12 >0.
Δ ADC23 <0.
Δ ADC23 =0. 1
left -1
Δ ADC12 =0.
right
condition
Center TDC
Slope1>0
Slope2<0
(Right-left)/2
Slope1<0
Slope2>0

12. code for find MinTDC and MaxTDC
if ([diffADC12]>0.).and.([diffADC23]<0.) then
..….
elseif ([diffADC12]<0.).and.([diffADC23]>0.) then ……
elseif ([diffADC12]>0.) then
elseif ([diffADC12]<-1.) then
elseif ([diffADC23]<0.) then
…….
elseif ([diffADC23]>0.) then
endif

13. fail

14. fail
input right
input left
(67-54)/2=59.5 54
59.5 67

15. code for find MinTDC and MaxTDC
if ([diffADC12]>0.).and.([diffADC23]<0.) then
..….
elseif ([diffADC12]<0.).and.([diffADC23]>0.) then ……
elseif( ([diffADC12]>0.) .and.([diffADC23]=0.))then
elseif (([diffADC12]<0.) .and.([diffADC23]=0.))then
elseif (([diffADC23]<0.) .and.([diffADC12]=0.))then
…….
elseif (([diffADC23]>0.) .and.([diffADC12]=0.))then
endif

16. fail

17. fail
input right
input left
( )/2=118
120
113
114
118

18. code for find MinTDC and MaxTDC
if ([diffADC12]>0.) then ……
elseif ([diffADC12]<-1.) then
endif
if ([diffADC23]<0.) then
…….
elseif ([diffADC23]>0.) then
if ([diffADC12]>0.).and.([diffADC23]<0.) then
..….; slope1=0;slope2=0;
elseif ([diffADC12]<0.).and.([diffADC23]>0.) then

20. if ([slope1]>0).and.([slope2]<0.) then
......
if ([valley]=1) then
if ([tmpADC2] > [prevMaxADC]) then
ve/input tmpMaxTDC[ipart]([ipulse]) [tmpTDC2]
ve/input tmpMaxADC[ipart]([ipulse]) [tmpADC2]
prevMaxTDC = [tmpTDC2]
prevMaxADC = [tmpADC2]
else
endif
if ([slope1]<0).and.([slope2]>0.) then
......
if ([valley]=1) then
ve/input tmpMaxTDC[ipart]([ipulse]) [tmpTDC2]
ve/input tmpMaxADC[ipart]([ipulse]) [tmpADC2]
prevMaxTDC = [tmpTDC2]
prevMaxADC = [tmpADC2]
endif

21. ok

22. ok