1. Handout Ch 4 實習

2. 微積分複習第二波(1)
Example
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3. 微積分複習第二波(2)
變數變換
Example
這是什麼鬼
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4. 微積分複習第二波(3)
Ch 4積分補充
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5. Find x
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6. 新的消去法?
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7. Another way to expand an equation
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8. 歸去來析 ( 乾脆去死,台語)
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9. Expectation of a Random Variable
Discrete distribution
Continuous distribution
E(X) is called expected value, mean or expectation of X.
E(X) can be regarded as being the center of gravity of that distribution.
E(X) exists if and only if
E(X) exists if and only if Whenever X is a bounded random variable, then E(X) must exist.
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10. The Expectation of a Function
Let , then
Let , then
Suppose X has p.d.f as follows:
Let it can be shown that
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11. Example 1 (4.1.3)
In a class of 50 students, the number of students ni of each age i is shown in the following table:
If a student is to be selected at random from the class, what is the expected value of his age
Agei 18 19 20 21 25 ni 22 4 3 1
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12. Solution E[X]=18*0.4+19*0.44+20*0.08+21*0.06+ 25*0.02=18.92 Agei 18 19ni 22 4 3 1 Pi
0.4
0.44
0.08
0.06
0.02
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13. Properties of Expectations
If there exists a constant such that
If are n random variables such that each exists, then
For all constants
Usually
Only linear functions g satisfy
If are n independent random variable such that each exists, then
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14. Example 2 (4.2.6)
Suppose that a particle starts at the origin of the real line and moves along the line in jumps of one unit. For each jump, the probability is p (0<=p<=1) that the particle will jump one unit to the left and the probability is 1-p that the particle will jump one unit to the right. Find the expected value of the position of the particle after n jumps.
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15. Solution
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16. Properties of the Variance
Var(X ) = 0 if and only if there exists a constant c such that Pr(X = c) = 1.
For constant a and b,
Proof :
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17. Properties of the Variance
If X1 , …, Xn are independent random variables, then
If X1,…, Xn are independent random variables, then
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18. Example 3 (4.3.6)
Suppose that X and Y are independent random variables with finite variances such that E(X)=E(Y)
Show that
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19. Solution
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20. Moment Generating Functions
Consider a given random variable X and for each real number t, we shall let The function is called the moment generating function (m.g.f.) of X.
Suppose that the m.g.f. of X exists for all values of t in some open interval around t = 0. Then,
More generally,
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21. Properties of Moment Generating Functions
Let X has m.g.f ; let Y = aX+b has m.g.f Then for every value of t such that exists,
Proof:
Suppose that X1,…, Xn are n independent random variables; and for i = 1,…, n, let denote the m.g.f. of Xi. Let , and let the m.g.f. of Y be denoted by . Then for every value of t such that exists, we have
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22. The m.g.f. for the Binomial Distribution
Suppose that a random variable X has a binomial distribution with parameters n and p. We can represent X as the sum of n independent random variables X1,…, Xn.
Determine the m.g.f. of
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23. Uniqueness of Moment Generating Functions
If the m.g.f. of two random variables X1 and X2 are identical for all values of t in an open interval around t = 0, then the probability distributions of X1 and X2 must be identical.
The additive property of the binomial distribution
Suppose X1 and X2 are independent random variables. They have binomial distributions with parameters n1 and p and n2 and p. Let the m.g.f. of X1 + X2 be denoted by .
The distribution of X1 + X2 must be binomial distribution with parameters n1 + n2 and p.
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24. Example 4 (4.4.10)
Suppose that the random variables X and Y are i.i.d. and that the m.g.f. of each is
Find the m.g.f. of Z=2X-3Y+4
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25. Solution
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26. Properties of Variance and Covariance
If X and Y are random variables such that and , then
Correlation only measures linear relationship.
兩各變數可以dependent,但correlation=0
Example: Suppose that X can take only three values –1, 0, and 1, and that each of these three values has the same probability. Let Y=X 2. So X and Y are dependent.
E(XY)=E(X 3)=E(X)=0, so Cov(X,Y) = E(XY) – E(X)E(Y)=0 (uncorrelated).
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27. Example 5 (4.6.12)
Suppose that X and Y have a continuous joint distribution for which the joint p.d.f is as follows:
Determine the value of Var(2X-3Y+8)
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28. Solution
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