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ECE 576 POWER SYSTEM DYNAMICS AND STABILITY

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Presentation on theme: "ECE 576 POWER SYSTEM DYNAMICS AND STABILITY"— Presentation transcript:

1 ECE 576 POWER SYSTEM DYNAMICS AND STABILITY
Lecture 24 Initial conditions Professor M.A. Pai Department of Electrical and Computer Engineering © 2000 University of Illinois Board of Trustees, All Rights Reserved

2 DAE Model The DAE Model Backwards to get other initial conditions. OR
FOR SIMULATION WE NEED INITIAL CONDITIONS PROCEDURE Do Load Flow to get and work. Backwards to get other initial conditions.

3 VOLTAGE DEPENDENT LOADS
Review of Load Flow NET “INJECTED” REAL AND REACTIVE POWERS NETWORK VOLTAGE DEPENDENT LOADS

4 Network Equations Transfer Conductance Transfer Susceptance
Self Conductance Self Susceptance

5 Load Flow Equations Network Equations
The power-balance equations at the Buses 1,…,n are: Load Flow Equations are a subset of the above.

6 Load Flow Variables 1 2………m , m+1………n
Need 2n-(m+1) i.e. (2n-m-1) equations. We pick (2n-m-1) equations from the Network equations as follows: P-V Buses P-Q Buses

7 Load flow Equations (contd)
Solve for Compute Slack Bus Powers and Reactive Power at P-V buses as follows:

8 Load Flow Equations (contd)
This completes Load Flow problem. Wealth of literature on solving Load Flow equations Slack Bus P-V Bus

9 Initial Conditions of DAE Model (Polar)
+ + - LOAD - (TO BE USED LATER)

10 Initial Conditions (contd)
Step 1: Set Derivatives=0 and Compute Systematically KVL yields: Using (2) in (3) yields: (After a lot of Algebra!) (4) leads to graphical representation = 0

11 Initial Conditions (contd)
The right-hand side is a voltage behind the impedance and has an angle . The voltage has a magnitude and an angle “Phasor” Diagram Locating ‘q’ axis of machine

12 Initial Conditions (contd)
Step 2 is computed as Step 3 Compute for the machines as:

13 Initial Conditions (contd)
From Stator Algebraic Equations: Step 4 Compute Which also equals to This serves as a check on the earlier calculations. Step 5 From Step 1.

14 Initial Conditions (contd)
Step 6 Compute (after setting the derivative equal to zero) Step 7 The other variables and can be found (after setting the derivative equal to zero) (EXCITER)

15 Initial Conditions (contd)
Step 8 The mechanical state and input are found (after setting the derivatives to zero) This completes the computation of all dynamic-state initial conditions and fixed inputs. Thus we have computed and starting from the load-flow. } known

16 Initial Conditions (contd)
For a given disturbance, the inputs remain fixed throughout the simulation. If the disturbance occurs due to a fault or a network change, the algebraic states must change instantaneously. Dynamic states cannot change instantaneously. Hence solve all the algebraic equations inclusive of the stator equations with the dynamic states specified at their values just prior to the disturbance as initial conditions to determine the new initial values of the algebraic states.

17 Industry Model An equivalent but alternative formulation used widely in commercial power system simulation packages. Rearrange the equations from a programming point of view. .

18 Industry Model (contd)
Hence, are functions of either . or or

19 Industry Model (contd)
Define two vectors: E is the subset of the state vector x and W is a vector of algebraic variables. We can express the differential equations as:

20 Industry Model (contd)
The Network equations are: since E is a subset of the vector x. Thus, Eqn (2) has the structure A(x) is Block Diagonal.

21 Industry Model (contd)
Only dependency of A(x) on x comes through the saturation function in the exciter. A(x), B, and C are matrices having a block structure with each block belonging to a machine. G contains the stator algebraic equations and intermediate equations for and in terms of This formulation is easy to program. Alternatively, we can substitute (3) in (2) and for in (4) to obtain

22 Industry Model (contd) 3 M/C Example
The stator algebraic equations and the intermediate equations corresponding to (3) are:

23 Industry Model (contd)
and are used from the first two equations in the third equation. A similar substitution for leads to: Substitution of numerical values in the above equations is trivial, and is left as an exercise for the reader.


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