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Section 1.6 Law of Cosines.

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Presentation on theme: "Section 1.6 Law of Cosines."— Presentation transcript:

1 Section 1.6 Law of Cosines

2 Objectives: 1. To prove the law of cosines. 2. To solve triangles using the law of cosines.

3 Law of Cosines For any triangle ABC, where side lengths opposite angles A, B, and C are a, b, and c respectively, then a2 = b2 + c2 – 2bc cos A.

4 Alternate forms of the Law of Cosines
a2 = b2 + c2 – 2bc cos A b2 = a2 + c2 – 2ac cos B c2 = a2 + b2 – 2ab cos C

5 To apply the Law of Cosines, you must know either the measures of all three sides or the measures of two sides and the included angle.

6 EXAMPLE 1 Solve FDG if f = 8, d = 4, and g = 10.
f2 = d2 + g2 – 2dg cos F 82 = – 2(4)(10) cos F 64 = – 80 cos F 64 = 116 – 80 cos F -52 = -80 cos F mF = cos-1 (0.65) ≈ 49.46 (4928΄)

7 EXAMPLE 1 Solve FDG if f = 8, d = 4, and g = 10.
g2 = d2 + f2 – 2df cos G 102 = – 2(4)(8) cos G 100 = – 64 cos G 100 = 80 – 64 cos G 20 = -64 cos G mG = cos-1 ( ) ≈  (10813΄)

8 EXAMPLE 1 Solve FDG if f = 8, d = 4, and g = 10.
mD = 180 – (mF + mG) mD = 180 – (49.46 ) mD = 180 –  mD ≈ 22.33 (2219΄)

9 EXAMPLE 1 Solve FDG if f = 8, d = 4, and g = 10.
mF = 4928΄ f = 8 mD = 2219΄ d = 4 mG = 10813΄ g = 10

10 EXAMPLE 2 Solve ABC if A = 63, b = 12, and c = 9.
a2 = b2 + c2 – 2bc cos A a2 = – 2(12)(9) cos 63 a2 = – 216(.4540) a2 = 225 – 98.06 a ≈ 11.3

11 EXAMPLE 2 Solve ABC if A = 63, b = 12, and c = 9.
Use the law of sines to solve for C since C must be the smallest angle.

12 EXAMPLE 2 Solve ABC if A = 63, b = 12, and c = 9.
sin A c sin C = 11.3 sin 63 9 sin C = 9(sin 63) 11.3 sin C = mC = sin-1 ( ) ≈ 45.2

13 EXAMPLE 2 Solve ABC if A = 63, b = 12, and c = 9.
mB = 180 – (mA + mC) mB = 180 – (63 ) mB = 180 – 108.2 mB ≈ 71.8

14 EXAMPLE 2 Solve ABC if A = 63, b = 12, and c = 9.
mA = 63 a = 11.3 mB = 71.8 b = 12 mC = 45.2 c = 9

15 Practice: Find the mA if a = 38, b = 48, and c = 68
Practice: Find the mA if a = 38, b = 48, and c = 68. Round to the nearest degree. a2 = b2 + c2 – 2bc cos A 382 = – 2(48)(68) cos A 1444 = – 6528 cos A -5484 = cos A mA = cos-1 (0.8401) ≈ 33

16 Practice: Find the mC if a = 38, b = 48, and c = 68
Practice: Find the mC if a = 38, b = 48, and c = 68. Round to the nearest degree. c2 = a2 + b2 – 2ab cos C 682 = – 2(38)(48) cos C 4624 = – 3648 cos C 876 = cos C mC = cos-1 ( ) ≈ 104

17 Homework pp

18 ►A. Exercises 1. a = 6, b = 5, c = 8 62 = – 2(5)(8)(cos A) 36 = – 80 cos A 36 = 89 – 80 cos A -53 = -80 cos A cos A = mA = cos-1 (0.6625) mA ≈ 48.5°

19 ►A. Exercises 1. a = 6, b = 5, c = 8 52 = – 2(6)(8)(cos B) 25 = – 96 cos B 25 = 100 – 96 cos B -75 = -96 cos B cos B = mB = cos-1 ( ) mB ≈ 38.6°

20 ►A. Exercises 1. a = 6, b = 5, c = 8 mC = 180° - mA - mB mC = 180° ° ° mC ≈ 92.9°

21 ►A. Exercises 1. a = 6 b = 5 c = 8 mA ≈ 48.5 mB ≈ 38.6 mC ≈ 92.9

22 ►A. Exercises 3. b = 26, c = 18, mA = 64° a2 = – 2(26)(18)(cos 64°) a2 = – 936(0.4384) a2 = 1000 – 410.3 a2 = 589.7 a ≈ 24.3

23 ►A. Exercises 3. b = 26, c = 18, mA = 64° 262 = – 2(24.3)(18)(cos B) 676 = – 874.2(cos B) 676 = – 874.2(cos B) = (cos B) cos B = mB = cos-1 (0.2719) mB ≈ 74.2°

24 ►A. Exercises 3. b = 26, c = 18, mA = 64° mC = 180° - mA - mB mC = 180° - 64° ° mC ≈ 41.8°

25 ►A. Exercises 3. a ≈ 24.3 b = 26 c = 18 mA = 64 mB ≈ 74.2 mC ≈ 41.8

26 ►A. Exercises 7. A = 19.5°, B = 92°, c = 28 1. Basic trig ratios 2. Law of sines 3. Law of cosines

27 ►A. Exercises 9. A = 60°, B = 90°, b = 10 1. Basic trig ratios 2. Law of sines 3. Law of cosines

28 11. A radio antenna is placed on the top
►B. Exercises 11. A radio antenna is placed on the top of a 200-foot office building. The angle of elevation from a parking lot to the top of the antenna is 21°. The angle of depression looking from the bottom of the antenna to the lot is 10°. What is the height of the antenna?

29 ►B. Exercises 11. 10° 200 ft 21°

30 ►B. Exercises 11. 69° 100° x 200 ft 11°

31 ►B. Exercises sin10 = 200 x 11. sin10 200 x = x ≈ x 200 ft 10°

32 ►B. Exercises 11. x 69° 100° 1151.75 200 ft 11° sin69 1151.75 = sin11

33 ■ Cumulative Review 21. Convert 5 radians to degrees.

34 ■ Cumulative Review 22. Give the reference angle for -470°.

35 ■ Cumulative Review 23. Write 3 reciprocal ratios.

36 ■ Cumulative Review 24. In ∆ABC, find b if B = 27°, a = 8, and A = 90°

37 ■ Cumulative Review 25. In ∆ABC, find b if B = 27°, a = 8, and A = 20°


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