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THIS SERIES OF REACTIONS IS A TRANSMUTATION SERIES, A SERIES OF NUCLEII DECOMPOSE INTO ITHER SPECIES UNTILL A STABLE ISOTOPE IS PRODUCED TO END THE PROCESS.

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Presentation on theme: "THIS SERIES OF REACTIONS IS A TRANSMUTATION SERIES, A SERIES OF NUCLEII DECOMPOSE INTO ITHER SPECIES UNTILL A STABLE ISOTOPE IS PRODUCED TO END THE PROCESS."— Presentation transcript:

1 THIS SERIES OF REACTIONS IS A TRANSMUTATION SERIES, A SERIES OF NUCLEII DECOMPOSE INTO ITHER SPECIES UNTILL A STABLE ISOTOPE IS PRODUCED TO END THE PROCESS. A VARIETY OF RADIATION IS EMITTED.

2 QUESTIONS #8- WHAT IS THE TIME (h) FOR POTASSIUM-42 TO UNDERGO THREE HALF-LIFE PERIODS? 1 1/2 1ST T 2ND T 1/4 3RD T 1/8 NUMBER OF HALF LIFE PERIODS = t/T WHERE T = HALF LIFE (TABLE N) t = TIME ELAPSED 3 = t/ 12.4 h = 37.2h

3 #9 –If a sample of 10 grams decays to 5 grams after 2 days what is the half life?
1/2 1ST T 2ND T 1/4 3RD T 1/8 FRACTION REMAINING = REMAINING/ORIGINAL 5/10 = ½ REMAINING It takes one half life to get to ½ the original. In this question that is 2 days

4 #10- After 6 days what fraction of an element with a half life 2 days remains.
NUMBER OF HALF LIFE PERIODS = t/T WHERE T = HALF LIFE (TABLE N) t = TIME ELAPSED #T = t/T = 6/2 = 3 1 1/2 1ST T 2ND T 1/4 3RD T 1/8 6 days is 3 half lives and 1/8 of the sample remains,

5 40g Fraction persist= (1/2)t/T = (1/2)24d/8.07d = 1/8 1/8 of 40 = 5g
#11- How many grams of I-131 will persist after 24 d if 40.0g was present initially.? Fraction persist= (1/2)t/T = (1/2)24d/8.07d = 1/8 1/8 of 40 = 5g 40g 20g 1ST T 2ND T 10g 3RD T 5g


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