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Spheres! Section 11.4.

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Presentation on theme: "Spheres! Section 11.4."— Presentation transcript:

1 Spheres! Section 11.4

2 A sphere is the locus of points in space that are a fixed distance from a given point called the center of a sphere. A radius of a sphere connects the center of the sphere to any point on the sphere. A hemisphere is half of a sphere. A great circle divides a sphere into two hemispheres

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4 Example 1 Find the volume of the sphere. Give your answer in terms of . Volume of a sphere. = 2304 in3 Simplify.

5 Example 2 Find the diameter of a sphere with volume 36,000 cm3. Volume of a sphere. Substitute 36,000 for V. 27,000 = r3 r = 30 Take the cube root of both sides. d = 60 cm d = 2r

6 Example 3 Find the volume of the hemisphere. Volume of a hemisphere Substitute 15 for r. = 2250 m3 Simplify.

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8 Example 4 Find the surface area of a sphere with diameter 76 cm. Give your answers in terms of . S = 4r2 Surface area of a sphere S = 4(38)2 = 5776 cm2

9 Example 5 Find the volume of a sphere with surface area 324 in2. Give your answers in terms of . S = 4r2 Surface area of a sphere 324 = 4r2 Substitute 324 for S. r = 9 Solve for r. Substitute 9 for r. The volume of the sphere is 972 in2.

10 Example 6 Find the surface area of a sphere with a great circle that has an area of 49 mi2. A = r2 Area of a circle 49 = r2 Substitute 49 for A. r = 7 Solve for r. S = 4r2 = 4(7)2 = 196 mi2 Substitute 7 for r.

11 Example 7 Find the surface area and volume of the composite figure. Give your answer in terms of .

12 Assignment: Pg. 383 (13-15, 17-19, 24-26)


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