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Projectile Motion Free fall with an initial horizontal velocity

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Presentation on theme: "Projectile Motion Free fall with an initial horizontal velocity"— Presentation transcript:

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2 Projectile Motion Free fall with an initial horizontal velocity
Follows a parabolic trajectory An object dropped and an object given an initial horizontal velocity will reach the ground at the same time!! Myth Busters Video Roadrunner Physics Misconception

3 Points to Remember: Simplifying Problems
No horizontal acceleration: ax = 0 Constant horizontal velocity: vxi = vxf Vertical Acceleration = g = -9.8 m/s2 Time for horizontal = Time for vertical Simplifying Problems In this class we will not calculate values for projectiles with an initial vertical velocity: vyi = 0 Kinematic equations simplified to:

4 Simplified Projectile Equations
Horizontal Equation Vertical Equations

5 vx = initial horizontal velocity
Object Launched Horizontally vx = initial horizontal velocity Δy = initial height above ground t = total time in the air Δx = horizontal range

6 Concept Check Click for Answer

7 Object Launched at an Angle
vi = initial velocity q = launch angle Δy = maximum height t = total time in air Δx = horizontal range *Maximum range is accomplished with a 45° angle

8 Concept Check Click for Answer

9 Concept Check Click for Answer

10 Solving Projectile Problems
Completely separate x and y components Use this table and fill it out: ax is always 0 ay is always -9.8 m/s2 vxf is always the same as vxi Vyi is always 0 in this class Must first solve for time (using kinematic equations) Use time to solve for other unknown X (Horizontal) Y (Vertical) Δx = vxi = vyi = 0 vxf = vxi vyf = ax = 0 ay = -9.8 m/s2 t = ?

11 Practice Problem Click for Answer


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