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Published byRosalind Harvey Modified over 5 years ago
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Projectile Motion Free fall with an initial horizontal velocity
Follows a parabolic trajectory An object dropped and an object given an initial horizontal velocity will reach the ground at the same time!! Myth Busters Video Roadrunner Physics Misconception
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Points to Remember: Simplifying Problems
No horizontal acceleration: ax = 0 Constant horizontal velocity: vxi = vxf Vertical Acceleration = g = -9.8 m/s2 Time for horizontal = Time for vertical Simplifying Problems In this class we will not calculate values for projectiles with an initial vertical velocity: vyi = 0 Kinematic equations simplified to:
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Simplified Projectile Equations
Horizontal Equation Vertical Equations
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vx = initial horizontal velocity
Object Launched Horizontally vx = initial horizontal velocity Δy = initial height above ground t = total time in the air Δx = horizontal range
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Concept Check Click for Answer
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Object Launched at an Angle
vi = initial velocity q = launch angle Δy = maximum height t = total time in air Δx = horizontal range *Maximum range is accomplished with a 45° angle
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Concept Check Click for Answer
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Concept Check Click for Answer
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Solving Projectile Problems
Completely separate x and y components Use this table and fill it out: ax is always 0 ay is always -9.8 m/s2 vxf is always the same as vxi Vyi is always 0 in this class Must first solve for time (using kinematic equations) Use time to solve for other unknown X (Horizontal) Y (Vertical) Δx = vxi = vyi = 0 vxf = vxi vyf = ax = 0 ay = -9.8 m/s2 t = ?
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Practice Problem Click for Answer
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