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Not all chemical energy changes can be studied conveniently using simple calorimetry. Methods used to study these reactions are based on the principle.

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Presentation on theme: "Not all chemical energy changes can be studied conveniently using simple calorimetry. Methods used to study these reactions are based on the principle."— Presentation transcript:

1 Not all chemical energy changes can be studied conveniently using simple calorimetry.
Methods used to study these reactions are based on the principle that net changes in all properties of a system are independent of the way the system changes from the initial state to the final state.

2 Predicting ΔrH: Hess’ Law
Hess’ law states that the addition of chemical equations yields a net chemical equation whose enthalpy change is the sum of the individual enthalpy changes. ΔrH° = Δ1H° + Δ2H° + Δ3H° + … = ΣΔrH° Two things to remember: If a chemical equation is reversed, then the sign of ΔrH changes. If the coefficients of a chemical equation are altered by multiplying or dividing by a constant factor, then the ΔrH is altered by the same factor.

3 Use the following steps:
Write the net reaction equation, if it is not given. Manipulate the given equations so they will add to yield the net equation. Multiply, divide, &/or reverse the sign of the enthalpy of reaction. Cancel & add the remaining reactants & products to yield the net equation. Add the component enthalpy changes to obtain the net enthalpy change. Determine the molar enthalpy for a reactant or product, if required.

4 Example Problem Calculate the enthalpy change of the reaction
2 Fe(s) /2O2(g) → Fe2O3(s) using the following equations: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3CO2(g) ∆rH˚ = kJ CO(g) + ½ O2(g) → CO2(g) ∆rH˚ = kJ

5 Step 1. Net 2 Fe(s) + 3/2O2(g) → Fe2O3(s) ∆rH˚ = ? Step 2 and 3. 2 Fe(s) + 3CO2(g) → Fe2O3(s) + 3 CO(g) ∆rH˚ = kJ 3 CO(g) + 3/2 O2(g) → 3 CO2(g) ∆rH˚ = kJ Remember, every term is multiplied by 3, including the ∆rH. This equation also allows the unwanted substances from Equations 1 & 2 to cancel out.

6 Step 4 and 5. (1) 2 Fe(s) + 3CO2(g) → Fe2O3(s) + 3 CO(g) ∆rH˚ = kJ (2) 3 CO(g) + 3/2 O2(g) → 3 CO2(g) ∆rH˚ = kJ 2 Fe(s) + 3/2 O2(g) → Fe2O3(s) ∆rH˚ = kJ

7 Use the following given equations and their standard enthalpy changes.

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10 Homework: Read pgs. 502 – 504 Practice #’s 1 – 4 (p. 504, 505)
Section 11.4 Questions #’s 2,3,9,10 (p )


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