Presentation is loading. Please wait.

Presentation is loading. Please wait.

Trig Equations.

Similar presentations


Presentation on theme: "Trig Equations."β€” Presentation transcript:

1 Trig Equations

2 f(x)= cos π‘₯ 2 , 0Β°<π‘₯≀360Β° g x =βˆ’tan π‘₯+30 , βˆ’360Β°<π‘₯≀0Β°
Trigonometry KUS objectives BAT rearrange and solve trig equations BAT Starter: sketch these graphs f(x)= cos π‘₯ 2 , Β°<π‘₯≀360Β° g x =βˆ’tan π‘₯+30 , βˆ’360Β°<π‘₯≀0Β° h x =βˆ’2sin π‘₯βˆ’90 , βˆ’180Β°<π‘₯≀180Β° Check using Desmos / geogebra

3 Solve sin πœƒ =2 cos πœƒ in the interval 0≀ πœƒ ≀360Β°
WB29 Solve sin πœƒ =2 cos πœƒ in the interval 0≀ πœƒ ≀360Β° Divide by CosΞΈ Use Trig Identities Use Tan-1 2 y = TanΞΈ 90 180 270 360 63.4 243.4

4 Solve 𝑠𝑖𝑛 2 (πœƒβˆ’30) = 1 2 in the interval 0≀ πœƒ ≀360Β°
WB30 solve Quadratic Equations given to you using Sin, Cos or Tan Solve 𝑠𝑖𝑛 2 (πœƒβˆ’30) = in the interval 0≀ πœƒ ≀360Β° Work out the acceptable range. Subtract 30 Square root both sides. On fractions root top and bottom separately. Can be positive or negative. 45 135 1/√2 y = SinΞΈ -1/√2 90 180 270 360 225 315 360 added to get a value in the range

5 Work out what value would make either bracket 0
WB31 solve Quadratic Equations given to you using Sin, Cos or Tan Solve π‘π‘œπ‘  2 πœƒ βˆ’ cos πœƒ βˆ’1 =0 in the interval 0≀ πœƒ ≀360Β° Factorise Work out what value would make either bracket 0 360 1 CosΞΈ = 1 has 2 solutions y = CosΞΈ -0.5 CosΞΈ = -0.5 has 2 solutions 90 180 270 360 120 240

6 Work out what value would make either bracket 0
WB32 solve Quadratic Equations given to you using Sin, Cos or Tan Solve 𝑠𝑖𝑛 2 πœƒ βˆ’3 sin πœƒ +2=0 in the interval 0≀ πœƒ ≀360Β° Factorise Work out what value would make either bracket 0 2 SinΞΈ = 2 has no solutions 90 1 SinΞΈ = 1 has 1 solution y = SinΞΈ 90 180 270 360

7 Work out what value would make 0
WB33 solve Quadratic Equations given to you using Sin, Cos or Tan Solve 𝑠𝑖𝑛 2 πœƒ + sin πœƒ =0 in the interval 0≀ πœƒ ≀360Β° 3 𝑠𝑖𝑛 2 πœƒ + sin πœƒ =0 Factorise sin πœƒ 3 sin πœƒ +1 =0 Work out what value would make 0 sin πœƒ =0 or sin πœƒ = 1 3 sin πœƒ =0 gives πœƒ=90Β° sin πœƒ = gives πœƒ=19.5Β°, 160.5Β°,

8 4 𝑠𝑖𝑛 2 π‘₯ +2=10 cos π‘₯ cos π‘₯ = 1 2 or cos π‘₯ =βˆ’3
WB34 exam Q Solve for 0≀ ΞΈ ≀360°   all the solutions of 4 sin 2 x +2=10 cos x You must show clearly how you obtained your answers 4 𝑠𝑖𝑛 2 π‘₯ +2=10 cos π‘₯ cos π‘₯ = or cos π‘₯ =βˆ’3 4 βˆ’4 π‘π‘œπ‘  2 π‘₯ +2=10 cos π‘₯ 4 π‘π‘œπ‘  2 π‘₯ +10 cos π‘₯ βˆ’6=0 cos π‘₯ =βˆ’3 gives π‘›π‘œ π‘ π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘›π‘  2 π‘π‘œπ‘  2 π‘₯ +5 cos π‘₯ βˆ’3=0 2 cos π‘₯ βˆ’1 cos π‘₯ +3 =0 cos π‘₯= gives x=60Β°, 300Β°

9 π‘‘π‘Žπ‘› 2 πœƒβˆ’π‘‘π‘Žπ‘›πœƒ=0, 0β‰€πœƒβ‰€360 2sin πœƒβˆ’π‘π‘œπ‘ πœƒ=0, 0β‰€πœƒβ‰€180
Practice 3 Solve these equations 2sin πœƒβˆ’π‘π‘œπ‘ πœƒ=0, 0β‰€πœƒβ‰€180 π‘‘π‘Žπ‘› 2 πœƒβˆ’π‘‘π‘Žπ‘›πœƒ=0, 0β‰€πœƒβ‰€360 4 π‘π‘œπ‘  2 πœƒ+3 sin πœƒ =4, 0β‰€πœƒβ‰€360 𝑠𝑖𝑛 2 πœƒ= , β‰€πœƒβ‰€180

10 One thing to improve is –
KUS objectives BAT rearrange and solve trig equations self-assess One thing learned is – One thing to improve is –

11 END


Download ppt "Trig Equations."

Similar presentations


Ads by Google