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Predicting Reactions – Double Replacement
Are the compounds: a) both ionic? b) an acid and a base Step 1: Write ONE of each ion on the product side in the proper order Step 2: Balance the charges of each ion pair (USE ONLY SUBSCRIPTS) Step 3: Balance the equation (DO NOT TOUCH SUBSCRIPTS!!!) Step 1: Write ONE of each ion on the product side in the proper order Step 2: Balance the charges of each ion pair (USE ONLY SUBSCRIPTS) Step 1: Write ONE of each ion on the product side in the proper order (Switch anions) A B C D A D C B RbI + KF Rb F + K I
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Predicting Reactions – Double Replacement
Step 1: AlCl3 + MgSO4 Al SO4 + Mg Cl Step 2: AlCl3 + MgSO4 Al3+ SO42- + Mg2+ Cl- Al2(SO4)3 MgCl2 Step 3: 2 AlCl3(aq) + 3 MgSO4(aq) Al2(SO4)3(aq) + 3 MgCl2(aq) 2 AlCl3(aq) + 3 MgSO4(aq) Al2(SO4)3(aq) + 3 MgCl2(aq) 2 AlCl3(aq) + 3 MgSO4(aq) Al2(SO4)3(aq) + 3 MgCl2(aq) 2 AlCl3(aq) + 3 MgSO4(aq) Al2(SO4)3(aq) + 3 MgCl2(aq)
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Predicting Reactions – Double Replacement
Write the balanced chemical reaction for the reaction of calcium oxalate with nickel (III) acetate A B C D A D C B Step 1: CaC2O4 + Ni(C2H3O2)3 Ca C2H3O2 + Ni C2O4 Step 2: CaC2O4 + Ni(C2H3O2)3 Ca2+ C2H3O2- + Ni3+ C2O42- Ca(C2H3O2)2 Ni2(C2O4)3 Step 3: 3 CaC2O4(s) + 2 Ni(C2H3O2)3(aq) 3 Ca(C2H3O2)2(aq) + Ni2(C2O4)3(s) 3 CaC2O4(s) + 2 Ni(C2H3O2)3(aq) 3 Ca(C2H3O2)2(aq) + Ni2(C2O4)3(s) 3 CaC2O4(s) + 2 Ni(C2H3O2)3(aq) 3 Ca(C2H3O2)2(aq) + Ni2(C2O4)3(s) 3 CaC2O4(s) + 2 Ni(C2H3O2)3(aq) 3 Ca(C2H3O2)2(aq) + Ni2(C2O4)3(s)
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Balancing Chemical Equations
Write the balanced chemical equation for the reaction between hydrochloric acid and titanium (IV) hydroxide A D C B A B C D 4 HCl(aq) + Ti(OH)4(s) 4 H2O(l) + TiCl4(aq) 4 HCl(aq) + Ti(OH)4(s) 4 H2O(l) + TiCl4(aq) HCl(aq) + Ti(OH)4(s) + Ti(OH)4 4 HOH 4 H2O 4 H+ 4 H2O(l) OH- + Ti+4 TiCl4(aq) TiCl4 Cl- Write the balanced chemical equation for the reaction between sulfuric acid and cobalt (III) hydroxide A B BA 3 H2SO4(aq) + Co(OH)3(s) Co2(SO4)3(aq) + H2O(l) 3 H2SO4(aq) + 2 Co(OH)3(s) Co2(SO4)3(aq) + H2O(l) 3 H2SO4(aq) + 2 Co(OH)3(s) Co2(SO4)3(aq) + 6 H2O(l) H2SO4(aq) + Co(OH)3(s) + Co(OH)3 Co2(SO4)3(aq) Co2(SO4)3 + H2O(l) Co+3 SO4-2
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Balancing Chemical Equations
Write the balanced chemical equation for the reaction between hydroiodic acid and solid calcium carbonate 2 HI(aq) + CaCO3(s) H2CO3(aq) + CaI2(aq) HI(aq) + CaCO3(s) H2CO3(aq) H2CO3 + CaI2(aq) Coefficient of CO2 and H2O will be the same as the H2CO3 CO2(g) H2O(l) 2 HI(aq) + CaCO3(s) CO2(g) + H2O(l) + CaI2(aq)
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An aqueous solution of mercury (I) nitrate is added to an aqueous solution of copper (I) bromide. What is the balanced equation for this reaction? Step 1: Hg2(NO3)2(aq) + CuBr(aq) Hg2 Br + Cu NO3 Step 2: Hg2+2 Br- Cu+ NO3- Hg2(NO3)2(aq) + CuBr(aq) Hg2Br2(s) + CuNO3(aq) Step 3: Hg2(NO3)2(aq) + 2 CuBr(aq) Hg2Br2(s) + 2 CuNO3(aq) Hg2(NO3)2(aq) + 2 CuBr(aq) Hg2Br2(s) + 2 CuNO3(aq) Hg2(NO3)2(aq) + 2 CuBr(aq) Hg2Br2(s) + 2 CuNO3(aq)
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Step 1: Write a balanced chemical equation (molecular equation)
A solution of chromium (III) sulfate is added to a solution of cesium phosphate. Give the net ionic equation for any reaction that happens. Step 1: Write a balanced chemical equation (molecular equation) Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) Cr2(SO4)3 Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) Cr2(SO4)3(aq) + 2 Cs3PO4(aq) 2 CrPO4(s) + 3 Cs2SO4(aq) + Cs3PO4 CrPO4 + Cs2SO4 SE SE NE SE Cr+3 PO4-3 Cs+ SO4-2 Step 2: Break STRONG ELECTROLYTES ONLY into ions 2 Cr+3(aq) + 3 SO42-(aq) + 6 Cs+(aq) + 2 PO4-3(aq) 2 CrPO4(s) 2 Cr+3(aq) + 3 SO42-(aq) + 6 Cs+(aq) + 2 PO4-3(aq) 2 Cr+3(aq) + 3 SO42-(aq) 2 Cr+3(aq) + 3 SO42-(aq) + 6 Cs+(aq) + 2 PO4-3(aq) 2 CrPO4(s) + 6 Cs+(aq) + 3 SO42-(aq) Step 3: Cross out all spectator ions N.I.E 2 Cr+3(aq) + 2 PO4-3(aq) 2 CrPO4(s) 2 Cr+3(aq) + 2 PO4-3(aq) 2 CrPO4(s)
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Step 1: Write a balanced chemical equation (molecular equation)
A zinc acetate solution is combined with 3.50 M perchloric acid. Give the net ionic equation. Step 1: Write a balanced chemical equation (molecular equation) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) 2 HClO4(aq) + Zn(C2H3O2)2(aq) 2 HC2H3O2(aq) + Zn(ClO4)2(aq) HClO4 + Zn(C2H3O2)2 HC2H3O2 SE SE WE SE H+ C2H3O2- Zn+2 ClO4- Step 2: Break STRONG ELECTROLYTES ONLY into ions 2 H+(aq) + 2 ClO4-(aq) 2 H+(aq) + 2 ClO4-(aq) + Zn2+(aq) + 2 C2H3O2-(aq) 2 H+(aq) + 2 ClO4-(aq) + Zn2+(aq) + 2 C2H3O2-(aq) 2 HC2H3O2(aq) 2 H+(aq) + 2 ClO4-(aq) + Zn2+(aq) + 2 C2H3O2-(aq) 2 HC2H3O2(aq) + Zn2+(aq) + 2 ClO4-(aq) Step 3: Cross out all spectator ions N.I.E 2 H+(aq) + 2 C2H3O2-(aq) 2 HC2H3O2(aq) 2 H+(aq) + 2 C2H3O2-(aq) 2 HC2H3O2(aq)
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Step 1: Write a balanced chemical equation (molecular equation)
A 1.11 M solution of potassium chromate is added to a 0.72 M manganese (IV) nitrate solution. Give the N.I.E. Step 1: Write a balanced chemical equation (molecular equation) potassium chromate + manganese (IV) nitrate potassium nitrate + manganese (IV) chromate potassium chromate + manganese (IV) nitrate potassium nitrate + manganese (IV) chromate potassium chromate + manganese (IV) nitrate potassium nitrate + manganese (IV) chromate potassium chromate + manganese (IV) nitrate SE SE SE NE 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3 2 K2CrO4(aq) + Mn(NO3)4 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) 2 K2CrO4(aq) + Mn(NO3)4(aq) 4 KNO3(aq) + Mn(CrO4)2(s) Step 2: Break STRONG ELECTROLYTES ONLY into ions 4 K+(aq) + 2 CrO42-(aq) + Mn4+(aq) + 4 NO3-(aq) 4 K+(aq) + 4 NO3-(aq) 4 K+(aq) + 2 CrO42-(aq) + Mn4+(aq) + 4 NO3-(aq) 4 K+(aq) + 2 CrO42-(aq) 4 K+(aq) + 2 CrO42-(aq) + Mn4+(aq) + 4 NO3-(aq) 4 K+(aq) + 4 NO3-(aq) + Mn(CrO4)2(s) Step 3: Cross out all spectator ions N.I.E 2 CrO42-(aq) + Mn4+(aq) Mn(CrO4)2(s)
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