Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chapter 14 Refraction.

Similar presentations


Presentation on theme: "Chapter 14 Refraction."— Presentation transcript:

1 Chapter 14 Refraction

2 Section 14-1 Refraction ~ the bending of a wave as it passes at an angle from one medium into another. Refraction occurs because of a change in the wave speed.

3 With light, if the speed decreases going from the first to the second material, the ray is bent towards the normal.

4 If the speed increases in the second material, the ray is bent away from the normal.

5 The index of refraction, n, is the ratio of the speed of light in a vacuum (c) to its speed in a given medium (v). Since c and v are both given in m/s the index of refraction has no units. The slower the speed, the more optically dense the medium is and the greater n is.

6 Index of Refraction for Various Substances:
Water at 20 degrees C Ice at 0 degrees C Air at 0 degrees C CO2 at 0 degrees

7 Medium 1 Medium 2 Incident Ray Refracted Ray Reflected Ray The relationship between the angles of incidence and refraction is given by Snell’s Law

8 Snell’s Law n1(sin q1) = n2(sin q2)
n1= index of refraction for medium 1 q1 = incident angle n2 = index of refraction for medium 2 q2 = refracted angle

9

10 Section 14-1 Practice Problem
A light ray of wavelength 598 nm (produced by a sodium lamp) traveling through air strikes a smooth, flat slab of crown glass at an angle of 30.0 degrees to the normal. Find the angle of refraction,  r. Given: q1 = 30 degrees n1 = 1.00 n2 = 1.52 Unknown: q2 = ? Use the equation for Snell’s Law: Ni(sin i )= N r (sin  r )  r = sin-1 [(ni / nr) (sin  i)] = sin=1 [ (1.00 / 1.52) (sin 30 degrees)]  r = 19.2 degrees


Download ppt "Chapter 14 Refraction."

Similar presentations


Ads by Google