1. BELLWORK

2. ANSWER D

3. Boyle’s Law 11.2 PPT

4. What is Boyle’s Law?
Boyle’s Law states that when a gas is under pressure it takes up less space:
Boyles Law tells us about the relationship between the volume of a gas and its pressure at a constant temperature. The higher the pressure, the smaller the volume.

5. BOYLE’S LAW VIDEO

6. Volume vs. Pressure Inverse Relationship

7. Sample Problem:
A deep sea diver is working at a depth where the pressure is 3.0 atmospheres. He is breathing out air bubbles. The volume of each air bubble is 2 cm3. At the surface the pressure is 1 atmosphere. What is the volume of each bubble when it reaches the surface?

8. BOYLE’S LAW
Figure out which variables the problems deals with (Volume and Pressure only)
Use the Combined Gas Law Formula (Refer to reference sheet)
Ignore the Temperature in the Formula
P1V1= P2V2
T T2

9. How we work this out:
This is the formula we are going to use: (Derived from the Combined Gas Law on your reference page)
Formula first: P1 x V1 = P2 x V2
(Refer to reference Page)
Given:= P1 = 3.0 atm
V1 = 2 cm3
P2 = 1.0 atm
Unknown: V2

10. Here’s what you should have calculated
P1 x V1 = P2 x V2
3 atm x 2 cm3 = 1 atm x V2
6 = 1 (V2)
V2= 6 cm3

11. The Temperature-Volume Relationship
Charles’ Law
The Temperature-Volume Relationship

12. Charles’ Law
French chemist Jacques Charles discovered that the volume of a gas at constant pressure changes with temperature.
Temperature and volume are directly related……As the temperature of the gas increases, so does its volume, and vice versa

13. VIDEO

14. Volume vs. Temperature Direct Relationship

15. Example
If the temperature of a given amount of gas is doubled, for example, its volume will also double (as long as pressure remains unchanged).

16. Charles’ Law Example Problem:
A sample of neon gas occupies a volume of 752 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant?
Given:
V1 = 752 mL
T1 = 25°C = 298K
T2 = 50°C = 323K

17. Charles’ Law
Determine which variables are in the problem.
Delete the variable that is not in the problem. (Pressure) That means that pressure remains constant.
Use the Combined Gas Law to extrapolate the right equation to solve this problem (reference sheet)
P1V1 = P2V2
T T2

18. Equation Used:
V1 = V2
T1 T2
752 mL = V2
298 K K
298K = mL
V2 = 815 mL

19. Gay-Lussac’s Law

20. What is Gay-Lussac’s Law?
Gay-Lussac’s Law states that when a gas is under constant volume, there is a direct relationship between temperature and pressure.
The higher the temperature, the higher the pressure.

21. Gay-Lussac’s Law: P and T
Gay-Lussac’s law states that
The pressure exerted by a gas is directly related to the Kelvin temperature.
V is constant.
An increase in temperature increases the pressure of a gas. 21

22. PRESSURE VS. TEMP

23. Calculation with Gay-Lussac’s Law
A gas has a pressure at 2.0 atm at 18 ˚C. What is the new pressure when the temperature is increased to 62 ˚C?
Which variable is constant? 23

24. Gay-Lussac’s Law P1 V1 = P2 V2 T1 T2 Used the Combined Gas Law
When you have problems that give you volume and pressure.
Delete Volume in the Equation
P1 V1 = P2 V2
T T2

25. Gay-Lussac’s Law P1 = P2 T1 T2
This formula is used when the volume is constant.
P1 = P2
T T2

26. CLASSWORK
11.1 WKSHT