1. Solomons • Fryhle • Snyder
Organic Chemistry
ELEVENTH EDITION
Solomons • Fryhle • Snyder
Chapter 11
Alcohols and Ethers
Copyright © 2014 by John Wiley & Sons, Inc. All rights reserved.

20. Only used to avoid carbocation rearrangements

24. Need to use Hg(OAc)2 to make this work without rearrangement

32. H2O and ROH order reversed for R = CH3

33. HO– and RO– order reversed for R = CH3

42. Secondary carbocation rearranges before bromide adds

45. Turning OH into a Leaving Group Without C+ Rearrangements
Thionyl chloride replaces Cl for OH without carbocation rearrangements
Mechanism ultimately involves SN2 reaction, so inversion of configuration results
Can also use PCl3 to achieve the same result

47. Phosphorus tribromide replaces Br for OH without carbocation rearrangements
Mechanism ultimately involves SN2 reaction, so inversion of configuration results
Can also use thionyl bromide to achieve same result

50. Alkanesulfonyl chlorides turn OH groups into leaving groups which can be replaced by ANY nucleophile (not just Br or Cl)
No carbocations are involved; no rearrangements occur
Ultimate substitution involves SN2 reaction so inversion stereochemistry results

63. If necessary mercury can be used to add ROH across a double bond without carbocation rearrangements.
If double bond is not symmetric, pseudopolarize it and polarize the alcohol with H(+) and RO(-) to figure out the correct product

67. TBS will replace H of an alcohol to act as a protecting group for the alcohol
Polarize H(+) and RO(-) in the alcohol and TBS(+) and Cl(-) in TBSCl
Si loves F even more than O and will grab F– and spit out RO– when you need to break off the TBS protecting group

69. Regeneration of the original alcohol by breaking off the TBS protecting group after doing some chemical reactions on the R group

77. Normally only HBr, HI, and H2SO4 are acidic enough to cleave ethers
In this case, however, the stability of tertiary carbocation which results from H– shifting and substituting for CH3OH makes this reaction work with HCl
If tertiary carbocations can be formed then HCl is strong enough to cleave ethers

84. In acid the nucleophile attacks the carbon which would support the most stable carbocation (unconventional SN2 reaction - driven by charge on C rather than steric accessibility)
This carbon only develops a partial + charge; remains bonded to O until this bond broken by nucleophile
Therefore no carbocation rearrangements occur (O bridge prevents them like in Hg case)
Also product has nucleophile and OH group oriented as if they did an ANTI addition to a double bond (like in Br2 or Cl2 addition to a double bond)

85. In base the nucleophile attacks the less hindered carbon (conventional SN2)
Orientation of nucleophile and OH are low symmetry like in acid case

86. For product analysis polarize the less hindered C(+) and the epoxide O(–)
Polarize the nucleophile in the normal manner, break the correct C-O epoxide bond, and add the + fragment from the nucleophile to the – epoxide O; add the – fragment from the nucleophile to the + carbon of the epoxide ring

87. Under acidic conditions the C which supports the most + charge gets the + polarization
Polarize everything else in the usual fashion and swap partners as usual with polar reactions
The correct bond to break in the epoxide is the one which connects the negatively-polarized O to the carbon which you polarized positive

93. In this case the products are low-symmetry
Because the three groups on one chiral carbon are the same as the three groups on the other chiral carbon the high-symmetry product would be meso
Since the reactant is high-symmetry (cis) and the reaction produces the same product as a low-symmetry (anti) addition to a double bond the product symmetry is low

94. In this case a low-symmetry reactant (trans) multiplied by a low-symmetry reaction (effective anti addition) calculates a high-symmetry product (meso)

95. In these cases the actual calculation goes as follows:
Start with a high- or low-symmetry alkene (+ or -)
Multiply by a high-symmetry reaction (+) to make the cis epoxide
Multiply by a low-symmetry reaction (SN2 inversion, – symmetry) to make the final product

96. Crown Ethers
Make ionic compounds soluble in nonpolar solvents and make anionic nucleophiles very reactive