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Chapter 4 Compounds and Their Bonds

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1 Chapter 4 Compounds and Their Bonds
4.1 Valence Electrons 4.2 Octet Rule and Ions LecturePLUS Timberlake

2 LecturePLUS Timberlake
Chemical Bonds Attraction between two or more atoms Interaction between valence electrons Ionic bonds Covalent bonds Metallic bonds LecturePLUS Timberlake

3 LecturePLUS Timberlake
Valence Electrons Electrons in the highest (outer) electron level Have most contact with other atoms Outer shells of noble gases contain 8 valence electrons (except He = 2) Example: Ne 2, 8 Ar 2, 8, 8 LecturePLUS Timberlake

4 Electron Dot Structures
Symbols of atoms with dots to represent the valence-shell electrons 1A A 3A A A A 7A A H He:            Li Be  B   C   N   O  : F  :Ne :                    Na Mg  Al  Si  P S :Cl  :Ar :         LecturePLUS Timberlake

5 LecturePLUS Timberlake
Learning Check A. X would be the electron dot formula for 1) Na 2) K 3) Al   B  X  would be the electron dot formula 1) B 2) N 3) P LecturePLUS Timberlake

6 LecturePLUS Timberlake
Solution A. X would be the electron dot formula for 1) Na 2) K   B  X  would be the electron dot formula 2) N 3) P LecturePLUS Timberlake

7 LecturePLUS Timberlake
Octet Rule An octet in the outer shell makes atoms stable Electrons are lost, gained or shared to form an octet Unpaired valence electrons strongly influence bonding LecturePLUS Timberlake

8 Metals forming ions- Cations (cats have paws-pos)
Metals lose electrons to match the number of valence electrons of their nearest noble gas Positive ions form as a result LecturePLUS Timberlake

9 Formation of Sodium Ion
Sodium atom Sodium ion Na  – e  Na + ( = Ne) 11 p p+ 11 e e- LecturePLUS Timberlake

10 Formation of Magnesium Ion
Magnesium atom Magnesium ion Mg  – 2e  Mg2+ (=Ne) 12 p p+ 12 e e- LecturePLUS Timberlake

11 Some Typical Ions with Positive Charges (Cations)
Group 1A Group 2A Group 3A H+ Mg2+ Al3+ Li+ Ca2+ Na+ Sr2+ K+ Ba2+ LecturePLUS Timberlake

12 LecturePLUS Timberlake
Learning Check A. Number of valence electrons in aluminum 1) 1 e ) 2 e- 3) 3 e- B. Change in electrons for octet 1) lose 3e ) gain 3 e ) gain 5 e- C. Ionic charge of aluminum 1) ) ) 3+ LecturePLUS Timberlake

13 LecturePLUS Timberlake
Solution A. Number of valence electrons in aluminum 3) 3 e- B. Change in electrons for octet 1) lose 3e- C. Ionic charge of aluminum 3) 3+ LecturePLUS Timberlake

14 LecturePLUS Timberlake
Learning Check Give the ionic charge for each of the following: A. 12 p+ and 10 e- 1) 0 2) 2+ 3) 2- B. 50p+ and 46 e- 1) 2+ 2) 4+ 3) 4- C. 15 p+ and 18e- 2) ) 3- 3) 5- LecturePLUS Timberlake

15 LecturePLUS Timberlake
Solution Give the ionic charge for each of the following: A. 12 p+ and 10 e- 2) 2+ B. 50p+ and 46 e- 2) 4+ C. 15 p+ and 18e- 2) 3- LecturePLUS Timberlake

16 LecturePLUS Timberlake
Learning Check A. Why does Ca form a Ca2+ ion? B. Why does O form O2- ion? LecturePLUS Timberlake

17 LecturePLUS Timberlake
Solution A. Why does Ca form a Ca2+ ion? Loses 2 electrons to give octet (like Ar) B. Why does O form O2- ion? Gains 2 electrons to give octet e (like Ne) LecturePLUS Timberlake

18 Nonmetal Ions-anions (a negative ion)
Nonmetals in 5A, 6A, and 7A gain electrons from metals, become negatively charged Nonmetal ionic charge: 3-, 2-, or 1- LecturePLUS Timberlake

19 LecturePLUS Timberlake
Fluoride Ion unpaired electron octet     : F  e : F :     (= Ne) 9 p p+ 9 e e- ionic charge LecturePLUS Timberlake

20 LecturePLUS Timberlake
Learning Check Complete the names of the following ions: 5A A A N3 O2 F nitride __________ fluoride P3 S2 Cl ___________ __________ _________ Br  _________ LecturePLUS Timberlake

21 LecturePLUS Timberlake
Solution 5A A A N3 O2 F nitride oxide fluoride P3 S2 Cl phosphide sulfide chloride Br  bromide LecturePLUS Timberlake


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