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Multiplying Binomials

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Presentation on theme: "Multiplying Binomials"— Presentation transcript:

1 Multiplying Binomials

2 Binomial An algebraic expression which contains two terms
is known as Binomial  Example 1 : 2x + 3x2  It is a Binomial, because it contains two terms 2x and 3x2  Example 2 : 9pq + 11p2q It is a Binomial, because it contains two terms 9pq and 11p2q

3 "FOIL" Method  for multiplying binomial
FOIL stands for "First, Outer, Inner, Last"  It is the sum of: · multiplying the First terms of each binomial, · multiplying the Outer terms of each binomial, · multiplying the Inner terms of each binomial, and · multiplying the Last terms of each binomial Recap: Multiplying powers with the same base: Add the exponents. (am)x(an) = am+n For example: ( a3 )x(a2) = a3+2 = a5

4 Ans: 2y2+ 9y + 10 Example 1: (2y + 5)(y + 2) Solution:
F: (2y + 5) (y + 2) O: (2y + 5) (y + 2) I: (2y + 5) (y + 2) L: (2y+ 5) (y + 2) F : Multiplying the first term of each binomial we get (2y) x y = 2y2 O : Multiplying the outer term of each binomial, we get (2y) x (2) = 4y I : Multiplying the inner term of each binomial, we get 5 x y = 5y L : Multiplying the last term of each binomial, we get 5 x 2= 10 After taking sum of above , we get 2y2 + 4y + 5y + 10 = 2y2+ 9y + 10 Ans: 2y2+ 9y + 10

5 Ans: 6x2 + 7x - 3 Example 2: (2x + 3)(3x – 1) F : (2x + 3) (3x - 1)
Solution: F : (2x + 3) (3x - 1) O : (2x + 3) (3x - 1) I : (2x + 3) (3x - 1) L : (2x + 3) (3x - 1) F : Multiplying the first term of each binomial we get 2x x 3x = 6x2 O : Multiplying the outer term of each binomial, we get 2x x (-1) = -2x I : Multiplying the inner term of each binomial, we get 3 x 3x = 9x L : Multiplying the last term of each binomial, we get 3 x (-1) = -3 After taking sum of above , we get 6x2 +(-2x) + 9x + (-3) = 6x2 - 2x + 9x - 3 = 6x2 + 7x - 3 Ans: 6x2 + 7x - 3

6 Try These Multiply (2j + 6) (j + 4) Multiply (3m + 8) (2m - 9)


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