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Lecture: Natural Selection and Genetic Drift and Genetic Equilibrium

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1 Lecture: Natural Selection and Genetic Drift and Genetic Equilibrium

2 Genetic Drift Random change in allele frequency
Just by chance or chance events Most effect on smaller populations (100 individuals or less) Founder effect- allele frequencies change as a result of the migration of a small subgroup of a population Chance events can like migrations or natural disasters can reduce population size or create new, smaller populations from an original larger population

3 Genetic equilibrium Hardy-Weinberg principle- allele frequencies in a population will remain constant unless one or more factors causes those alleles to change Genetic Equilibrium- allele frequencies in the population remain the same, nothing is changing Conditions under which evolution will not occur 5 Conditions Random Mating No Immigration or Emigration (Migration) No Mutations No Natural Selection Large Populations

4 Hardy-Weinberg Equation
p2 + 2pq + q2 = 1 p + q = 1 p=frequency of dominant allele, q= frequency of recessive allele p2 = frequency of individuals who are homozygous dominant, q2 = frequency of individuals who are homozygous recessive, 2pq= frequency of individuals who are heterozygous If the frequency of people in the United States that have a certain recessive trait is 2% (or 0.02), what is the frequency of the allele for that trait? q2 = frequency of individuals who are homozygous recessive = 0.02 q= frequency of recessive allele= √0.02 = 0.14 or 14%

5 Sample Problem A certain recessive disease has a frequency of 1 in 2500 people. What is the frequency of each allele and the frequency of carriers? (Assuming the population is at Hardy-Weinberg equilibrium) What is the genotype of a recessive disease? So q2= 1/2500= , and q= √ = 0.02 If q is present 0.02 or 2% of the time, and p is the only other allele, how often is p present? So q= 0.02, p= 0.98, those are the frequencies of the alleles! What is the genotype of a carrier of a recessive disease? p2 + 2pq + q2 = 1 So 2pq= 2 x 0.02 x 0.98= 0.04 Frequency of homozygous dominant= 0.982= 0.96 Frequency of homozygous recessive= 0.022= = 1


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