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Algebra 1 Section 10.3.

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Presentation on theme: "Algebra 1 Section 10.3."— Presentation transcript:

1 Algebra 1 Section 10.3

2 Factoring ax2 + bx + c (3x – 2)(x + 5) 3x2 + 15x – 2x – 10
Sum of the middle terms First terms (FOIL) Last terms (FOIL)

3 Find factors of +6 whose sum is +7.
Example 1 Factor 3x2 + 7x + 2. ac = 6 and b = 7 Find factors of +6 whose sum is +7. 3x2 + 1x + 6x + 2

4 Example 1 3x2 + 1x + 6x + 2 Group the first two terms and the last two terms and factor the GCF from each grouping. (3x2 + 1x) + (6x + 2) x(3x + 1) + 2(3x + 1) (x + 2)(3x + 1)

5 Factoring Trinomials of the Form ax2 + bx + c
Find factors of ac whose sum is b. Rewrite the middle term as a sum of terms with these factors of ac as their coefficients.

6 Factoring Trinomials of the Form ax2 + bx + c
Factor the four-term polynomial by grouping the terms in pairs. Factor the common monomial from each pair. Factor the common binomial from each new term.

7 Factoring Trinomials of the Form ax2 + bx + c
Check your factorization by multiplying the factors.

8 Example 2 Factor 2x2 – 19x + 24. ac = 48 and b = -19
Find factors of +48 whose sum is -19. Both factors must be negative. 2x2 – 3x – 16x + 24

9 Example 2 2x2 – 3x – 16x + 24 (2x2 – 3x) + (-16x + 24)

10 Find factors of -60 whose sum is -7.
Example 3 Factor 3x2 – 20 – 7x. 3x2 – 7x – 20 ac = -60 and b = -7 Find factors of -60 whose sum is -7. 3x2 – 12x + 5x – 20

11 Example 3 3x2 – 12x + 5x – 20 (3x2 – 12x) + (5x – 20)

12 Factoring Remember: The first step in factoring a polynomial is to factor out any common monomial factors. In Example 4, there is a common factor of 2x.

13 Find factors of 30 whose sum is -13.
Example 4 Factor 12x3 – 26x2 + 10x. 2x(6x2 – 13x + 5) ac = 30 and b = -13 Find factors of 30 whose sum is -13. 2x(6x2 – 10x – 3x + 5)

14 Example 4 2x(6x2 – 10x – 3x + 5) 2x[(6x2 – 10x) + (-3x + 5)]

15 Example 5 Factor 2x2 + 3xy – 14y2. Proceed as before, but remember the “y”. ac = -28 and b = 3 Find factors of -28 whose sum is 3. 2x2 + 7xy – 4xy – 14y2

16 Example 5 2x2 + 7xy – 4xy – 14y2 (2x2 + 7xy) + (-4xy – 14y2)
x(2x + 7y) – 2y(2x + 7y) (x – 2y)(2x + 7y)

17 Factoring ax2 + bx + c It is also possible, for trinomials with small coefficients, to use a method of listing the combinations of coefficients. Notice that Example 6 uses this method, and notice the similarities to Example 5.

18 Homework: pp


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