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Milagros Duran & Keslie Chapa December 18, 2013 7+8A

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A pair of boots and a pair of tennis shoes cost $196.12. The difference in their cost is $44.38. Determine the cost of each. Problem Situation

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Define Variables X= cost of a pair of boots Y= cost of a pair of tennis shoes

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X –Y = 44.38 System of Equations X + Y = 196.12

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Elimination Add the equations to eliminate the variable Y. Solution Method

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X + Y = 196.12 Add the equations X –Y = 44.38 2X = 240.50 X = 120.25 Step 1 of Solution

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X + Y = 196.12 Rewrite knowing that X equals 120.25 120.25 + Y = 196.12 Subtract 120.25 from both sides. Y = 75.87 Step 2 of Solution

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(X, Y) (120.25, 75.87) Solution to the System of Equations

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151.74+44.38=196.12 Check of Solution

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The cost of a pair of boots is $120.25. The cost of a pair of tennis shoes is $75.87. Solution in the Problem Situation

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POD Solve each expression if x=4, y=7, and z=5 basicadvanced x + y +12 3x + y 2 − (-z) 4 + 7 +12 11 +12 23 3(4) + 7 2 − (-5) 3(4) + 49 − (-5) 12 + 49 −

POD Solve each expression if x=4, y=7, and z=5 basicadvanced x + y +12 3x + y 2 − (-z) 4 + 7 +12 11 +12 23 3(4) + 7 2 − (-5) 3(4) + 49 − (-5) 12 + 49 −

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