# Milagros Duran & Keslie Chapa December 18, 2013 7+8A.

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Milagros Duran & Keslie Chapa December 18, 2013 7+8A

A pair of boots and a pair of tennis shoes cost \$196.12. The difference in their cost is \$44.38. Determine the cost of each. Problem Situation

Define Variables X= cost of a pair of boots Y= cost of a pair of tennis shoes

X –Y = 44.38 System of Equations X + Y = 196.12

Elimination Add the equations to eliminate the variable Y. Solution Method

X + Y = 196.12 Add the equations X –Y = 44.38 2X = 240.50 X = 120.25 Step 1 of Solution

X + Y = 196.12 Rewrite knowing that X equals 120.25 120.25 + Y = 196.12 Subtract 120.25 from both sides. Y = 75.87 Step 2 of Solution

(X, Y) (120.25, 75.87) Solution to the System of Equations

151.74+44.38=196.12 Check of Solution

The cost of a pair of boots is \$120.25. The cost of a pair of tennis shoes is \$75.87. Solution in the Problem Situation