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Flows and Networks Plan for today (lecture 6):

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1 Flows and Networks Plan for today (lecture 6):
Last time / Questions? Jackon network Kelly / Whittle network Interpretation traffic equations Optimal design of a Kelly / Whittle network

2 Jackson network : Mean sojourn time
Simple queues, FCFS, Transition rates Traffic equations Open network Partial balance equations: Equilibrium distribution Sojourn time in each queue: Sojourn time on path i,j,k:

3 Kelly / Whittle network
Transition rates for some functions :S[0,),  :S(0,) Traffic equations Open network Partial balance equations: Theorem: Assume then satisfies partial balance, and is equilibrium distribution Kelly / Whittle network

4 Flows and Networks Plan for today (lecture 6):
Last time / Questions? Jackon network Kelly / Whittle network Interpretation traffic equations Optimal design of a Kelly / Whittle network

5 Interpretation traffic equations
Transition rates for some functions :S(0,), Traffic equations Open network Theorem: Suppose that the equilibrium distribution is then and rate jk PROOF

6 Flows and Networks Plan for today (lecture 6):
Last time / Questions? Jackon network Kelly / Whittle network Interpretation traffic equations Optimal design of a Kelly / Whittle network

7 Optimal design of Kelly / Whittle network (1)
Transition rates for some functions :S[0,),  :S(0,) Routing rules for open network to clear input traffic as efficiently as possible Cost per time unit in state n : a(n) Cost for routing jk : Design : b_j0=+ : cannot leave from j; sequence of queues Expected cost rate PROOF

8 Optimal design of Kelly / Whittle network (2)
Transition rates Given: input traffic Maximal service rate Optimization problem : minimize costs Under constraints

9 Optimal design of Kelly / Whittle network (3)
Lagrangian (without nonnegativity constraints) Interpretation Lagrange multipliers Theorem : (i) the marginal costs of input satisfy with equality for those nodes j which are used in the optimal design, where (ii) If the routing jkis used in the optimal design the equality holds in (i) and the minimum in the rhs is attained at given k. (iii) If node j is not used in the optimal design then αj =0. If it is used but at less that full capacity then cj =0.

10 Optimal design of Kelly / Whittle network (4)
PROOF: Kuhn-Tucker conditioins Dynamic programming equation: for nodes that are used in the optimal design: For networks with fixed routing or fixed service: Optimize lambda or p

11 Optimal design of Kelly / Whittle network (5)
Some structure is known: Corollary: Suppose Then optimal network has no cycles Dynamic programming equation: for nodes that are used in the optimal design: Notice that cj is also determined by αj This is bridge to deterministic network flow problems.

12 Next: Multiple job-types General queues Exercises


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